Answer:
Step-by-step explanation:
Answer:
y= -3/20x+90
y= -20/3x+6000
Step-by-step explanation:
refer to the above attachment ↑
Answer:
0.1041667 (approximation)
Step-by-step explanation:
divide that by 12
College 20 6 8 18 10 14 13.3 5.2
High School 20 3 5.5 16 10.5 11 11 5.4
Which of the choices below best describes how to measure the spread of this data?
A. Both spreads are best described with the IQR.
B. Both spreads are best described with the standard deviation.
C. The college spread is best described by the IQR. The high school spread is best described by the standard deviation.
D. The college spread is best described by the standard deviation. The high school spread is best described by the IQR.
Answer:
C. The college spread is best described by the IQR. The high school spread is best described by the standard deviation.
Step-by-step explanation:
If data is normally distributed we use Standard deviation otherwise we use Interquartile Range (IQR) for measuring the spread.
Further, data is said to be normally distributed if Mean = Median = Mode.
So, High School data is normally distributed but College data is not.
So, We measure the spread of College data by IQR and High School data by Standard Deviation.
Thus, Option C is the only correct option.
We know the first place after decimal is tenths
The second place after decimal is hundredths
The third place after decimal is the thousandths place
So for 0.056
0 is at the tenths place
5 is at the hundredths place
and 6 is at the thousandths place
Expanding 22.056 we get
22.056 = 20 + 2 + 0.05 + 0.006
OR
22.056 =