MATHEMATICS HIGH SCHOOL

Find the slope between each pair of points

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

y2-y1

‐---------

x2-x1

7-5

------

6-4

-- = 1

Answer 2

Answer: The answer is 1

This is because y2-y1/x2-x1
If you plug that in you get 5-7/4-6
That simplifies to -2/-2
Which is 1

Hope this helped!

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Which of the binomial below is a factor of this trinomial 4x^3-20x^2+24xa) x+3
b)x-3
c)2x-3
d)2x+3

Answers

$4x^3-20x^2+24x$

$4x (x^2-5x+6)$

$4x(x-2)(x-3)$

$(b)x-3$

b) x - 3

see attached for proof

A perfect square trinomial can be represented by a square model with equivalent length and width. Which polynomial can be represented by a perfect square model?

Answers

x2 – 6x + 9 is the answer

Answer:

A is the answer. X^2 -6x+9

Step-by-step explanation:

Please need help!!!!

Answers

it's is true because 4 and 5are closer

Which relation is a function?A. {(2, 3), (1, 5), (2, 7)}

B. {(-1, 5), (-2, 6), (-3, 7)}

C. {(11, 9), (11, 5), (9, 3)}

D.{(3, 8), (0, 8), (3, -2)}

Answers

Answer: Option B

Step-by-step explanation:

A function has a rule, for each point in the domain, there can be only one point associated in the range.

This means that f(x) can have only one value y that is associated to the point x in the domain.

now, with this in mind, let's analyze the options, where the pairs are always written as (x, y)

A) Here we can see the pairs (2,3) and (2, 7), so we have the point in the domain, 2, that is associated with two different values in the range, so this relation can not be a function.

B) In this set, there are no problems because we do not have ani point in the domain with more than one value in the range, so this can be a function.

C) here point 11 has two different values in the range, so this can not be a function.

D) here point 3 has two different values in the range, so this can not be a function.

b, because for every one you take away from the x value, you add one to the y value

Suppose that a department contains 12 men and 17 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men?