Answers
The question is incomplete, below is the complete question.
Polydactyly is a rare autosomal dominant trait that is 80% penetrant. What is the chance that a child born to an affected father and a normal mother will have the disorder?
Assume the paternal grandfather is normal.
I will use P to encode polydactyl as it is dominant and use p allele to encode normal phenotype
P= Polydactyl
p= Normal
From what is given in the question,the paternal grandfather is normal and that means that the father of the child receives one wild type allele from the paternal grandfather, however,the father is affected with the disease,hence the genotype is A a but the mother being normal will have the genotype of aa.
That is Parents;
Father Aa × Mother aa
Gametes a a A Aa ( P ) Aa ( P )
a aa ( p ) aa ( p )
So if it is 100% penetrant, that implies that the chances of the affected child is;
(2/4 ) ×100=50%
However, only 80% penetrant is given here,so that is why the chances of the affected is then ; (50/100) ×(80/100) ×100= 40%
That means the affected child chances are 40%.
Final answer:
Polydactyly is a rare autosomal dominant trait with 80% penetrance.
Explanation:
Polydactyly is a rare autosomal dominant trait that is 80% penetrant. This means that if a person carries the genetic mutation for polydactyly, there is an 80% chance that they will express the trait. Therefore, if the father is affected by polydactyly (carries the gene) and the mother is normal (does not carry the gene), each child they have has a 50% chance of inheriting the gene from the father and a 50% chance of inheriting the normal gene from the mother.
However, if a child inherits the gene for polydactyly from the father, there is an 80% chance that they will express the trait, meaning they will have the disorder. On the other hand, if the child inherits the normal gene from the mother, they will not have the disorder.
Learn more about Polydactyly here:
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