Which graph of y= 3/4x-3​

Answer:

If Connor makes x dollars in sales, he will make 0.05x + 300 that week.

He makes $408.75 in a week if he makes $2175 in sales.

Step-by-step explanation:

y = 0.05x + 300

y = 0.05(2175) + 300

y = 408.75

Final answer:

To compute 17 ÷ 2 using remainder notation, divide 17 by 2 and find the quotient and remainder. The quotient is 8 and the remainder is 1.

Explanation:

To compute 17 ÷ 2 using remainder notation, you divide 17 by 2 and find the quotient and remainder. In this case, the quotient is the whole number part of the division and the remainder is the leftover part. When you divide 17 by 2, the quotient is 8 and the remainder is 1. Therefore, the answer is 8 with a remainder of 1.

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Answer:8.5

Step-by-step explanation:

a) The probability that a new municipal bond issued by a city will receive an A rating is 0.625 or 62.5%.

b) 56% of municipal bonds are issued by cities.

c) The proportion of municipal bonds issued by suburbs is 0.325 or 32.5%.

Let's solve each part of the problem:

a. If a new municipal bond is to be issued by a city, what is the probability that it will receive an A rating?

Use conditional probability here.

Using conditional probability notation, we have:

P(A | City)

To calculate this, use the following formula:

P(A | City) = P(A and City) / P(City)

We are given:

- P(A) = 0.70 (probability of an A rating)

- P(B) = 0.20 (probability of a B rating)

- P(C) = 0.10 (probability of a C rating)

For bonds issued in cities:

- P(City | A) = 0.50 (probability that it's a city if it's rated A)

- P(City | B) = 0.60 (probability that it's a city if it's rated B)

- P(City | C) = 0.90 (probability that it's a city if it's rated C)

Now, let's calculate:

P(A and City) = P(A) * P(City | A)

P(City) = P(A) * P(City | A) + P(B) * P(City | B) + P(C) * P(City | C)

Substitute the values:

P(A and City) = 0.70 * 0.50

                      = 0.35

P(City) = (0.70 * 0.50) + (0.20 * 0.60) + (0.10 * 0.90)

          = 0.35 + 0.12 + 0.09

          = 0.56

Now, calculate the conditional probability:

P(A | City) = P(A and City) / P(City)

                = 0.35 / 0.56

                = 0.625

So, the probability is 0.625 or 62.5%.

b. What proportion of municipal bonds are issued by cities?

56% of municipal bonds are issued by cities.

c. What proportion of municipal bonds are issued by suburbs?

To find the proportion of municipal bonds issued by suburbs,  use a similar approach:

P(Suburb) = P(A) * P(Suburb | A) + P(B) * P(Suburb | B) + P(C) * P(Suburb | C)

We are given:

- P(Suburb | A) = 0.40

- P(Suburb | B) = 0.20

- P(Suburb | C) = 0.05

Now, calculate:

P(Suburb) = (0.70 * 0.40) + (0.20 * 0.20) + (0.10 * 0.05)

                 = 0.28 + 0.04 + 0.005

                 = 0.325

So, the proportion of municipal bonds issued by suburbs is 0.325 or 32.5%.

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Final answer:

The probability that a municipal bond issued by a city will receive an A rating is 35%. The proportion of all municipal bonds issued by cities is 56%. The proportion of all municipal bonds issued by suburbs is 32.5%.

Explanation:

This question requires an understanding of probability and conditional probability.

a) To find the probability that a new municipal bond issued by a city will receive an A rating, we must first determine the likelihood that an A-rated municipal bond is issued by a city. Given that 50% of A-rated bonds are issued by cities and that 70% of all bonds receive an A rating, we can calculate this probability as (0.50)*(0.70) = 0.35, or 35%.

b) To find the proportion of municipal bonds issued by cities, we must add up the bonds issued by cities across all ratings. So, (0.70*0.50) + (0.20*0.60) + (0.10*0.90) = 0.35 + 0.12 + 0.09 = 0.56, or 56%.

c) To calculate the proportion of municipal bonds issued by suburbs, we do the same calculation as in part b) but for suburbs. So, (0.70*0.40) + (0.20*0.20) + (0.10*0.05) = 0.28 + 0.04 + 0.005 = 0.325, or 32.5%.

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Answer:

Figure out the various probabilities first, that will make the rest of the questions easier:

P(discovered) = .7

P(not discovered) = 1 - .7 = .3

P(locator|discovered) = .6

P(no locator|discovered) = 1 - .6 = .4

P(locator|not discovered) = 1 - .9 = .1

P(no locator|not discovered) = .9

P(discovered and locator) = .7 * .6 = .42

P(discovered and no locator) = .7 * .4 = .28

P(not discovered and locator) = .3 * .1 = .03

P(not discovered and no locator) = .3 * .9 = .27

a) The total probability that an aircraft has a locator is .42 + .03 = .45. So the probability it will not be discovered, given it has a locator, is .03/.45 = .067

b) The total probability that an aircraft does not have a locator is .28 + .27 = .55. So the probability it will be discovered, given it does not have a locator, is .28/.55 = .509

c) Probability that 7 are discovered = C(10,7) * P(discovered|locator)^7 * P(not discovered|locator)^3

We already figured out P(not discovered|locator) = .067, so P(discovered|locator) = 1-.067 = .933. C(10,7) = 10*9*8, so we can compute total probability: 10*9*8 * .933^7 * .067^3 = .133

Step-by-step explanation:

i think k is 5 but if i am wrong srry hope it helped

Answer:

4%

Step-by-step explanation:

264 interest/3 years=88 interest/year

principal x interest rate =interest/year

2200 x interest rate =88

interest rate =88/2200

interest rate =.04 or 4%