MATHEMATICS HIGH SCHOOL

The pep club ia selling t-shirts for $7.50. They buy the t-shirts for $5.00from the printing store. How much profit do they earn on each t-shirt?

Answers

Answer 1

Answer:

Answer:

$2.50

Step-by-step explanation:

7.50 - 5.00 = 2.50

They sell the shirts for $2.50 more than the original price so profit $2.50 off each shirt .

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Which statements are true of the function f(x) = 3(2.5)x? Check all that apply.The function is exponential.The initial value of the function is 2.5.The function increases by a factor of 2.5 for each unit increase in x.The domain of the function is all real numbers.The range of the function is all real numbers greater than 3.
Five ninths times the difference of f and 32

G(x) = 3x -1. Find x such that g(x)= 20.g(x)= 3x+1. Find x such that g(x)= 22.

g(x)= 2x-5. Find g(1/2) and g(a)=99.
g(x)=x+5/2. Find g(3), g(0), g(-3) and g(x)=0

Please solve this quickly. I need it right now. No silly answer will not be allowed.

Answers

Step-by-step explanation:

i. 3x-1=20

or, 3x= 21

x= 7

ii. 3x+1= 22

3x= 21

x= 7

iii. 2x-5=99

2x= 104

x=52

iv. g(3)= 3+5/2= 11/2

g(0)= 0+ 5/2=5/2

g(-3)= -3+5/2 = -1/2

x+5/2= 0

so, x= -5/2

Which option is a function

Answers

(x,y)
for every x there is exatly 1 y
basically, x never repeats with a differnt y

first one works, no x's repeart

2nd is not, 1 repeats wwth 9 and -4

3rd is correct

4th is wrong, 0 repreats with 3 and 7

5th is correct

so the functions are 1st 3rd 5th

Find the equation of the circle whose center and radius are given.center ( -2, -5), radius = 1

Answers

Answer: The required equation of the circle is $x^2+y^2+4x+10y+28=0.$

Step-by-step explanation: We are given to find the equation of the circle with center (-2, -5) and radius of length 1 unit.

We know that

the standard equation of a circle with center (h, k) and radius of length r units is given by

$(x-h)^2+(y-k)^2=r^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

For the given circle, we have

center, (h, k) = (-2, -5) and radius, r = 1 units.

Therefore, from equation (i), we get

$(x-(-2))^2+(y-(-5))^2=1^2\n\n\Rightarrow (x+2)^2+(y+5)^2=1\n\n\Rightarrow x^2+4x+4+y^2+10x+25=1\n\n\Rightarrow x^2+y^2+4x+10y+29-1=0\n\n\Rightarrow x^2+y^2+4x+10y+28=0.$