The range of the function is all real numbers.
The vertex of the function is .
The function has two x-intercepts.
The function is increasing over the interval (, ∞
we have
using a graphing tool
see the attached figure
This is a quadratic equation (vertical parabola) open up
The vertex is a minimum---------> Vertex
The domain of the function is all real numbers-------> interval (-∞,∞)
The range of the function is the interval----------> [-6.125,∞)
The function has two x-intercepts-----> and
The function is increasing over the interval-----> (0.25,∞)
The function is decreasing over the interval-----> (-∞,0.25)
Answer:
C
180(.6) because 40% off is 0.4 and what is left over is 60% or 0.6. When you multiply this you get 108. 5% sales tax is a 5% increase, so multiple 108(1.05) and you get $113.40.
Select one:
a. B = 23.7°, C = 143.3°, c ≈ 23.3
b. B = 23.7°, C = 123.3°, c ≈ 17.5
c. Cannot be solved
d. B = 23.7°, C = 123.3°, c ≈ 29.2
Answer:
D.
Took the test
B=23.7 degrees
C=123.3 degrees
c=29.2
When Ivan divides his coins into groups of 2 nickels and 1 quarter, worth $0.35, he find that he has $8.75/$0.35 = 25 such groups.
Ivan has 25 quarters and 50 nickels.
Let n denote the number of nickels.
and q denote the number of quarters.
1 nickel=0.05 dollar
and 1 quarter=0.25 dollar
Hence, we have:
0.05n+0.25q=8.75
( Since, Ivan has $8.75 in nickels and quarters in his desk drawer )
On multiplying both side of the equation by 100 we have:
5n+25q=875
on dividing both side of the equation by 5 we have:
n+5q=175-----------------(1)
Also, n=2q---------------(2)
( Since, the number of nickels is twice the number of quarters )
Hence, on putting equation (2) in equation (1) we have:
2q+5q=175
i.e.
7q=175
i.e. q=25
and on putting the value of q in equation (2) we have:
n=50
The area of original square is 16 centimetre square.
The area is the region bounded by the shape of an object.
Let consider 'a' as the side of the original square.
When it fold vertically then the top and bottom sides will be half of the original side.
The perimeter of folded square = 12 cm
i.e. (2* 0.5a)+ 2a =3a =12 cm
Then, a=4cm
The area of original square is given by a^2.
Then, a^2 = 4*4 =16
Hence, 16 centimeter is the area of the original square.
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