Answer: 13,879 days
If Joan's father is 38 years old today, that means that he was born in 1982. (2020-38=1982).
If we multiply 38 years by 365 days per year, we get 13,870 days.
But we need to take into account leap years, which happen every 4 years! In a leap year, there's an extra day in February. There have been 9 leap years since Joan's father was born.
So, we add 9 days to 13870 days, to get: 13,879 days.
Please give me Brainliest if this helped! :)
Joan's father, who is 38 years old, would be 13,870 days old. This is calculated by multiplying 38 years by 365 days/year.
To calculate how many days old Joan's father is, you simply need to multiply his age in years by the number of days in a year. Since we typically consider a year to have 365 days, the calculation is as follows: 38 years * 365 days/year. The answer, therefore, is 13,870 days. The main concept here is the conversion of units, in this case converting years to days. Remember to always consider the number of units in one when converting.
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Y = 5x – 3
A) No solutions
B) (0,4)
C) Infinitely many solutions
D) (0,-3)
tion of system?
Y = 5x + 4
Y = 5x – 3
A) No solutions
B) (0,4)
C) Infinitely many solutions
D) (0,-3)
Answer: 12.5%
Step-by-step explanation:
To find the probability that exactly n cards are dealt before the first ace appears, we can use the concept of a geometric distribution. In a geometric distribution, we're interested in the number of trials (in this case, card draws) required for a success to occur (in this case, drawing an ace) for the first time.
The probability of drawing an ace in a single draw from a well-shuffled pack of 52 cards is 4/52 because there are 4 aces out of 52 cards.
So, the probability of drawing a non-ace in a single draw is (52 - 4)/52 = 48/52.
Now, let X be the random variable representing the number of cards drawn before the first ace appears. X follows a geometric distribution with parameter p, where p is the probability of success on a single trial.
P(X = n) = (1 - p)^(n - 1) * p
In this case, p is the probability of drawing an ace on a single trial, which is 4/52, and n is the number of cards drawn before the first ace.
So, the probability that exactly n cards are dealt before the first ace appears is:
P(X = n) = (1 - 4/52)^(n - 1) * (4/52)
Now, to find the probability that exactly k cards are dealt in all before the second ace appears, we need to consider two scenarios:
1. The first ace appears on the nth card, and the second ace appears on the kth card after that. This is represented by P(X = n) * P(X = k).
2. The first ace appears on the kth card, and the second ace appears on the nth card after that. This is represented by P(X = k) * P(X = n).
So, the total probability that exactly k cards are dealt before the second ace appears is:
P(X = n) * P(X = k) + P(X = k) * P(X = n)
You can calculate this probability using the formula for the geometric distribution with p = 4/52 as mentioned earlier for both P(X = n) and P(X = k).
3t-y
3(t-y)
The expression that represents "three times the difference between t and y" is
"It is a mathematical statement which consists of numbers, variables and some mathematical operations."
For given question,
We need to write an expression for the statement "three times the difference between t and y"
The statement "the difference between t and y" in mathematical expression form would be t - y
Now, we write "three times the difference between t and y" in expression form as,
Therefore, the expression that represents "three times the difference between t and y" is
Learn more about expressions here:
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