A giraffe is 5 m 20cm tall. An Elephant is 1m 77cm shorter than the giraffe. A rhinoceros is 1m 58 cm shorter than the elephant. How tall is the rhinoceros

Answers

Answer 1
Answer: The answer 1m and 85cm

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In the first quadrant you start at (6, 10) and move 6 units right and 4 units down what point will you end up with

Answers

Answer:

(12,6)

Step-by-step explanation:

If you move 6 units right, you get to (12,10). Moving 4 units down takes you to (12,6).

It would be 12,6 I believe

Solve the inequality and write the solution set using both set-builder notation and interval notation. -3a-15≤-2a+6

Answers

Answer:

Set builder notation: {a | a ≥ -21}

Interval notation: [-21, ∞)

Step-by-step explanation:

A set represents a collection of things, objects, or numbers. A set builder notation is in the form y = {x | x is an odd number between 8 and 10}, which means y contains all the odd numbers between 8 and 10.

Interval notation is a way to define a set of numbers between a lower limit and an upper limit using end-point values. for example (8, 20) means numbers between 8 and 20.

Given -3a-15≤-2a+6; solving :

-3a - 15 ≤ -2a + 6

-3a + 2a ≤ 6 + 15

-a ≤ 21

dividing through by -1:

a ≥ -21

The solution is:

Set builder notation: {a | a ≥ -21}

Interval notation: [-21, ∞)

I need help with this math problem please (3x+2)(5x-7)

Answers

Answer:

Hey there!

Using the foil method: (3x+2)(5x-7)

15x^2+10x-21x-14

15x^2-11x-14

Let me know if this helps :)


Here’s your answer (3x+2)x(5x-7)

Find the sum? Enter your answer in simplest form 1/8 +5/6

Answers

Answer:

23/24

Step-by-step explanation:

1/8 + 5/6

The common denominator is 24

1/8 *3/3 = 3/24

5/6*4/4 = 20/24

3/24 + 20/24

23/24

The sum of (1)/(8) and (5)/(6)  given  as an expression using the least common multiple  in the simplest form is   (23)/(24).

 When both the numerator and denominator does not have any common factor in between them is called as  simplest form. Simplest form is also called as lowest form.

A statement containing variables, numbers or connected by an operator is called expression.

According to the given expression

The least common multiple (LCM) for 8 and 6 is 24. We can convert both fractions to have a denominator of 24:

\frac {1}{8} +(5)/(6)

Now that both fractions have a common denominator of 24, we can add them,

(3)/(24) + (20)/(24) \n \n  =(23)/(24)

Therefore, the sum of(1)/(8) and (5)/(6) is   (23)/(24)

Learn more about  the least common multiple  here :

brainly.com/question/30060162

#SPJ6

If two objects travel through space along two different curves, it's often important to know whether they will collide. (Will a missile hit its moving target? Will two aircraft collide?) The curves might intersect, but we need to know whether the objects are in the same position at the same time. Suppose the trajectories of two particles are given by the vector functions for t 0. Do the particles collide? If they collide find t. If not enter NONE.r1(t)=r2(t)=<9t-14,t^2,13t-42>t=

Answers

Answer:

The particles collide when t = 7 at the point (49, 49, 49).

Step-by-step explanation:

We know the trajectories of the two particles,

r_1(t)=\langle t^2,16t-63,t^2\rangle\nr_2(t)=\langle 9t-14,t^2,13t-42\rangle

To find if the tow particles collide you must:

  • Equate the x-components for each particle and solve for t

t^2=9t-14\nt^2-9t+14=0\n\left(t^2-2t\right)+\left(-7t+14\right)=0\nt\left(t-2\right)-7\left(t-2\right)=0\n\left(t-2\right)\left(t-7\right)=0

The solutions to the quadratic equation are:

t=2,\:t=7

  • Equate the y-components for each particle and solve for t

16t-63=t^2\n^2-16t+63=0\n\left(t^2-7t\right)+\left(-9t+63\right)=0\nt\left(t-7\right)-9\left(t-7\right)=0\n\left(t-7\right)\left(t-9\right)=0

The solutions to the quadratic equation are:

t=7,\:t=9

  • Equate the z-components for each particle and solve for t

t^2=13t-42\nt^2-13t+42=0\n\left(t^2-6t\right)+\left(-7t+42\right)=0\nt\left(t-6\right)-7\left(t-6\right)=0\n\left(t-6\right)\left(t-7\right)=0

The solutions to the quadratic equation are:

t=6,\:t=7

Evaluate the position vectors at the common time. The common solution is when t = 7.

r_1(7)=\langle 7^2,16(7)-63,7^2\rangle=\langle 49,49,49\rangle\n\nr_2(7)=\langle 9(7)-14,7^2,13(7)-42\rangle=\langle 49,49,49\rangle

For two particles to collide, they must be at exactly the same coordinates at exactly the same time.

The particles collide when t = 7 at the point (49, 49, 49).

What is the portion that repeats of the repeating decimal of seven thirteenths

Answers

Answer:

hi want to talk to me ?

Step-by-step explanation:

Answer:

7 13/100

Step-by-step explanation: