Hello please help me geometry :)

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Answer 1

Answer:

Answer:

$the \: hieght \: of \: the \: trapazium \: \n is \: 2.5 \: inches$

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Help pls with answer!!!Rewrite the function in the given form.

1. How many one-fifths are there in 17 1/2

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Answer:

Step-by-step explanation:

= 17 1/2 ÷ 1/5

= 35/2 (improper fraction should be used as a dividend) × 5/1 (the divisor will be reciprocal and the operation will be multiplication)

= 175/2

= 87 1/2

Since the question is how many ⅕, the fraction will not be included.

Ivanna drove 696 miles in 12 hours. At the same rate, how many miles would she drive in 7 hours?

Answers

Answer:

406

Step-by-step explanation:

We need to find the unit rate or how many miles can they drive in 1 hour. So we do 696/12 which is 58. So we have 58 miles in 1 hour. Now we multiply the number of desired hours, 7 and multiply it by 696. Which is 406

Just need help with this simple math question
Simplify:
2(n-4)

Answers

2(n-4) = 2n - 8 .........distributive property

the answer is 2n - 8
you are distributing 2 into n and 4 so 2 times n is 2n and 2 times 4 is 8

A certain human red blood cell has a diameter of 0.000007 meters which expression represents this diameter in meters in scientific notation

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0.000007 in scientific notation is equal to 7 $7^(-6)$ times 10

I think it’s 7 x 10^6

A family has two cars. The first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of 20 miles per gallon of gas. During one particular week, the two cars went a combined total of 2200 miles, for a total gas consumption of 75 gallons. How many gallons were consumed by each of the two cars that week?

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Answer:

The car that has a fuel efficiency of 40 mpg consumed 35 gallons, while the car that has a fuel efficiency of 20 mpg consumed 40 gallons.

Step-by-step explanation:

The variable a will represent the fuel consumed by the first car, and the variable b will represent the fuel consumed by the second car.

Set up the formula: a+b=75, which will represent the total gas consumption.

The formula 20a+40b=2200 will help you solve.

To solve, we will first solve for a by changing the formula from a+b=75 to b=75-a. Then you plug in the value of b to the second formula:

20a+40(75-a)=2200

20a+3000-40a=2200

3000-20a=2200

After subtracting 3000 from both sides, you are left with -20a=-800. Multiply both sides by -1 so that both sides are positive:

20a=800

a=40

Now that we know that the car with a 20 mpg fuel efficiency consumed 40 gallons that week, we can subtract 40 from 75, leaving us with 35 being the amount of gallons consumed by the car with a 40 mpg efficiency.

Given the linear programming problem, use the method of corners to determine where the minimum occurs and give the minimum value.Minimize

Exam Image

Subject to
x ≤ 3
y ≤ 9
x + y ≥ 9
x ≥ 0
y ≥ 0

Answers

Answer:

Minimum value of function $C=x+10y$ is 63 occurs at point (3,6).

Step-by-step explanation:

To minimize :

$C=x+10y$

Subject to constraints:

$x\leq 3---(1)\ny\leq 9---(2)\nx+y\geq 9----(3)\nx\geq 0\ny\geq 0$

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line

Eq (2) is in green in figure attached and region satisfying (2) is below the green line

Considering $x+y\geq 9$ , corresponding coordinates point to draw line are (0,9) and (9,0).

Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line

Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)

Now calculate the value of function to be minimized at each of these points.

$C=x+10y$

at A(0,9)

$C=0+10(9)\nC=90$

at B(3,9)

$C=3+10(9)\nC=93$

at C(3,6)

$C=3+10(6)\nC=63$

Minimum value of function $C=x+10y$ is 63 occurs at point C (3,6).

Applying the method of corners to the linear programming problem yields a minimum value of 6 at the point (3, 0) for the given objective function and constraints.

The linear programming problem involves minimizing an objective function subject to certain constraints. The constraints are given as follows:

Minimize z = 2x + 3y

Subject to:

x ≤ 3

y ≤ 9

x + y ≥ 9

x ≥ 0

y ≥ 0

To find the minimum value, we employ the method of corners. The feasible region is determined by the intersection of the inequalities. The corner points of this region are where the constraints intersect.

Intersection of x ≤ 3 and y ≥ 0 gives the point (3, 0).

Intersection of y ≤ 9 and x ≥ 0 gives the point (0, 9).

Intersection of x + y ≥ 9 and y ≥ 0 gives the point (9, 0).

Now, evaluate the objective function z = 2x + 3y at each corner point:

z1 = 2(3) + 3(0) = 6

z2 = 2(0) + 3(9) = 27

z3 = 2(9) + 3(0) = 18

The minimum value occurs at point (3, 0) with z_min = 6.

For more such information on: linear programming

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