A road crew must repave a road that is 3/5 miles long. They can repave 1/15 miles each hour. How long will it take the crew to repave the road?

Answers

Answer 1

Answer:

The Total number of hours required to repave the whole road is 36.

What is the unitary method?

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

The Total length of the road that needs to be repaved = 3/5 miles

The Total length of the road which is repaved by the road crew per hour = 3/5 miles

The Total number of hours required to repave the whole road

= (Length of the road to be repaved)/(Length of the road repaved by the crew per hour)

= 3/4 divided by 1/48

= 3/4*48/1= 144/4

= 36

Hence, The Total number of hours required to repave the whole road is 36.

Learn more about the unitary method;

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Answer 2

Answer:

Answer: 36 hours

Step-by-step explanation: Plz mark me brainlest

3/4 divided by 1/48

KCF

3/4*48/1= 144/4= 36

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Solve for x. 3x - 5x + 8x + x = 42 A. 6 B. 7 C. 8
What's the Discriminant of X^2-2X-15 ?
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Here are 10 test scores: 50, 74, 76, 77, 78, 79, 80, 80, 82, 84. The mean of these scores is 76. How does removing the outlier 50 affect the mean?A.
The set has 50 as an outlier and removing it decreases the mean by about 6.

B.
The set has 50 as an outlier and removing it decreases the mean by about 2.

C.
The set has 50 as an outlier and removing it increases the mean by about 3.

Answers

The answer is C.
The set has 50 as an outlier and removing it increases the mean by about 3.

Since 50 is significantly smaller number than all others, it is expected that removing 50 will increase the mean.
The first mean is 76:
$X_(1) = (50+74+76+77+78+79+80+80+82+84)/(10) = (760)/(10) =76$

The mean after removing 50 is:
$X_(2) = (74+76+77+78+79+80+80+82+84)/(10) = (710)/(90) =78.89<span>$
X₂ ≈ 79

The difference between the second and the first mean is 79 - 76 = 3, thus
removing 50 as an outlier increases the mean by about 3.

The endpoints of are A(2, 2) and B(3, 8). is dilated by a scale factor of 3.5 with the origin as the center of dilation to give image . What are the slope (m) and length of ? Use the distance formula to help you decide: .

Answers

m=6,a'b'=3.5 square root 37

Answer:

The slope is m=6 and length of line is $d' =3.5√(37)$

Step-by-step explanation:

Given : The endpoints of line AB are A(2, 2) and B(3, 8). Line AB is dilated by a scale factor of 3.5 with the origin as the center of dilation to give image line A'B' .

To find : What are the slope (m) and length of line AB?

Solution :

The slope of a line does not change.

Slope formula is,

$m=(y_2-y_1)/(x_2-x_1)$

The slope of AB A(2, 2) and B(3, 8) is :

$m=(8-2)/(3-2)\n\nm=(6)/(1)\n\nm=6$

Distance formula, $d = √((x_2-x_1)^2 + (y_2-y_1)^2)$

The length of AB by distance formula,

$d = √((3 - 2)^2+(8-2)^2)\nd = √((1)^2+(6)^2)\nd=√(1+36)\nd=√(37)$

Line AB is dilated by a scale factor of 3.5.

The length of A'B' is :

$d' =3.5*√(37)\nd' =3.5√(37)$

Therefore, The slope is m=6 and length of line is $d' =3.5√(37)$

Solve 2cos^2x + cosx − 1 = 0 for x over the interval [0, 2 π ).a.π and π/3
b.π, π/3, and 5π/3
c.1 and 2π/3
d.1, 2π/3, and 4π/3
e.1, π/3, and 5π/3

Answers

the answer is (b) all this value of x satisfy the equation

Answer:

Option B

Step-by-step explanation:

$\pi ,(\pi )/(3), and (5\pi )/(3)$

Write a quadratic function in standard form with zeros 9 and -4

Answers

$if\ x_1\ and\ x_2\ zeros,\ then\ quadratic\ function\:\n\nf(x)=a(x-x_1)(x-x_2)\n\n\n9;\ -4-zeros,\ then:\n\nf(x)=a(x-9)(x+4)=a(x^2+4x-9x-36)=a(x^2-5x-36)\n\n\nif\ a=1\ then\ f(x)=x^2-5x-36$

If f(x) is a polynomial with real coefficients and zeros of 4(multiplicity 2 ), -1(multiplicity2 ),-1+8i , and 2-2i, what is the minimum degree of f(x) ?

Answers

Answer:

The minimum degree of polynomial f(x) = 6

Step-by-step explanation:

Multiplicity for a polynomial equation is the number of times the polynomial has that particular root.

The roots of this polynomial is given as

4(multiplicity 2 ), -1(multiplicity2 ), (-1+8i), and (2-2i)

Hence, the true roots of this particular polynomial are 4, 4, -1, -1, (-1+8i), and (2-2i)

Making a total of 6 roots.

The number of roots of a polynomial is the minimum degree of such a polynomial.

Hence, the minimum degree of this polynomial is 6.

Hope this Helps!!!

What is the value of 5.7 × 108?a. 5,700,000,000
b. 5.70000000
c. 570,000,000
d. 57,000,000 User: Which of the following has a value of 84?
a. 83
b. 512
c. 4,096
d. 32 User: What is the prime factorization of 1,260?
a. 2 × 3 × 5 × 6 × 7
b. 2 × 3 × 5 × 7
c. 4 × 5 × 7 × 9
d. 2 × 2 × 3 × 3 × 5 × 7 User: Which of the following is a composite number?
a. 139
b. 29
c. 91
d. 13

Answers

The value of 5.7 x 10⁸ is 570,000,000 CHOICE C.

The value of 8⁴ is 8 * 8 * 8 * 8 = 4,096 CHOICE C.

Prime factorization of 1,260

1260 ÷ 2 = 630
630 ÷ 2 = 315
315 ÷ 3 = 105
105 ÷ 3 = 35
35 ÷ 5 = 7

2 x 2 x 3 x 3 x 5 x 7 CHOICE D.

Composite numbers are numbers that have more factors other than 1 and itself.

91 / 1 = 91
91 / 7 = 13 CHOICE C. 91 is a composite number.

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