Answer:
Since the calculated Z= -1.886 lies within the Z∝ = ± 1.96 we fail to reject our null hypothesis that population mean is 31.8 oz. and not 32 ounces. There is evidence that Mill Valley Brewery is cheating customers by under-filling their bottles.
Step-by-step explanation:
Let the null hypothesis be
H0 : u = 31.8 oz against Ha: u ≠ 31.8 oz two tailed test
For a two tailed test and alpha = 0.05 the z∝ = ± 1.96
The rejection region is Z ≥ ± 1.96
Here n = 50
sample mean = x= 31.8 oz
and sample standard deviation= s= 0.75
Population mean= u= 32
Test statistics to be used is
Z= x- u / s/ √n which is approximately normal
Z= 31.8-32/0.75/ √50
z= -1.886
Since the calculated Z= -1.886 lies within the Z∝ = ± 1.96 we fail to reject our null hypothesis that population mean is 31.8 oz. and not 32 ounces. There is evidence that Mill Valley Brewery is cheating customers by under-filling their bottles.
5/4 times x=1
3 1/2 times x=1
5/7 times x=1
Show work
Answer:
Let x be the number of person and y be the total cost per person.
As per the statement:
A catering company charges a $300 set up fee and $10 per person for a lunch buffet.
"$10 per person" translated to 10x
then;
Total cost per person = 10x+300
It is also given that: total cost per person is $14.
⇒
Subtract 10x from both sides we have;
Divide both sides by 4 we have;
x = 75
Therefore, 75 number of people must attend the lunch so that the total cost per person is $14
CATERING TOTAL COST F(X) = 10X + 300
TOTAL REQUIRED 14X
10X + 300 = 14X
10X - 14X = -300
-4X = -300
4X = 300
X= 300/4
X=75 <------------------SOLUTION