MATHEMATICS HIGH SCHOOL

During every soccer game that Ronald plays, he runs all over the field. In his last game, he played on a soccer field that was 69,300 square feet. There are 3 feet in a yard. What is the area, in square yards (sq yd), of the soccer field where Ronald played his last game? Group of answer choices 7,700 sq yd 23,100 sq yd 207,900 sq yd 623,700 sq yd

Answers

Answer 1

Answer:

Answer:

The area of the soccer field where Ronald played his last game is 7,700 sq yd.

Step-by-step explanation:

From the question,

The area of the soccer field where Ronald played his last game was 69,300 square feet.

To determine the area, in square yards (sq yd), of the soccer field where Ronald played his last game, we will convert 69,300 square feet to square yards.

Also, from the question

There are 3 feet in a yard, that is, 3 feet = 1 yard

If 3 feet = 1 yard

∴ 3² square feet (ft²) will be equal to 1² square yard (yd²)

That is,

9 square feet = 1 square yard

Now,

If 9 square feet = 1 square yard

Then, 69,300 square feet will be

(69,300 square feet × 1 square yard) / 9 square feet = (69300/9 )square yards

= 7700 square yards (sq yd)

Hence, the area of the soccer field where Ronald played his last game is 7,700 sq yd.

Related Questions

Camillo estimates the weight of his dog. The veterinarian says that the dog weighs 84 pounds. The percent error in Camillo's estimates is less than 10%.Decide whether each of the following weight estimates could have been Camillo's estimate.a. 80 pounds yes or nob. 78 pounds yes or noc. 94 pounds yes or nod. 77 pounds yes or noe. 92 pounds yes or nof. 75 pounds yes or no
What is the domain…..
Jim has gotten scores of 99 and 93 on his first two tests. what score must he get on his third test to keep an average of 90 or greater
AC and BD are perpendiculare bisectors of each other find the perimeter of ABC 30
Which statement is true about the equation 3/4z = 1/4z − 3 + 5? It has no solution. It has one solution It has two solutions. It has infinitely many solutions.

What is the sum of the given polynomials in standard form?
(x2 – 3x) + (–2x2 + 5x – 3)

Answers

Combine like terms. -x2 +2x -3 is the answer.

Answer:

$-x^2+2x-3$

Step-by-step explanation:

The given polynomial expression is

$(x^2-3x)+(-2x^2+5x-3)$

We regroup the terms in the polynomial to obtain;

$x^2-2x^2-3x+5x-3$

We combine like terms to get;

$-x^2+2x-3$

When we arrange the terms in the polynomial in descending powers of x, then we say it is in standard form.

The simplified polynomial in standard form is $-x^2+2x-3$

Solve the equation 5m+4m=72

Answers

First of all we group our m's together.
So first add
5m + 4m = 9m

Now lets set up our equation again
9m = 72 .... divide both sides by 9 to get m alone
÷9 = ÷9
************ now m is alone on the left side and we solve on the right side.
m = 8

So your answer is
m = 8

Hello my friend

9m=72

Divide both sides by 9 so you can find the value for m

9m/9=72/9

m=8

I hope that's help:)

13.4 ___13.40

A : >
B : <
C : =

Answers

13.4 = 13.40

This is because the 0 at the end is a trailing decimal, and so when testing for inequalities, you can simply disregard it.

Indra baked and frosted a rectangular cake to sell at a bake sale for the Model UN club. The cake, including frosting, was 4 inches high, 16 inches wide, and 12 inches long. She centered the cake on a circular tray. The circular tray had a radius of 10 inches. What is the area, to the nearest square inch, of the tray that is not covered by the cake?A. 100
B. 114
C. 122
D. 314
E. 192

Answers

Answer:

C. 122

Step-by-step explanation:

Given,

Dimension of the cake:

Length = 12 in Width = 16 in Height = 4 in

We have to find out the area of the tray that is not covered by the cake.

Indra centered the cake on a circular tray.

Radius of the tray = 10 in.

So area of the tray is equal to π times square of the radius.

Framing in equation form, we get;

Area of tray = $\pi* r^2=3.14*{10}^2=3.14* 100=314\ in^2$

Since the cake is placed in circular tray.

That means only base area of cake has covered the tray.

Base Area of cake = $length* width=12* 16=192\ in^2$

Area of the tray that is not covered by the cake is calculated by subtracting area of base of cake from area of circular tray.

We can frame it in equation form as;

Area of the tray that is not covered by the cake = Area of tray - Base Area of cake

Area of the tray that is not covered by the cake = $314-192=122\ in^2$

Hence The area of the tray that is not covered by the cake is 122 sq. in.

PLEEESE HELLLLLLP If you have a test average of 92 and a standard deviation of 1.8, you generally do well on tests.t f

Answers

Yes, that's true PROVIDED your test scores are normally distributed.

If they are, then more than 99% of your test scores are within three
standard deviations of the mean.

You told us that 3-sigma = 5.4 . So less than one score out of every
hundred tests you take is lower than 86.6 or higher than 97.4 .

You are remarkably consistent, so I guess Jupiter must have been
in its ascendancy next door to the house of Andromeda about an
hour before you were born, or some such nonsense.

Davinci Digital Media’s wholesale price to the retailer for a digital video camcorder is $1,399.99. Manufacturing costs include $360.00 for production wages and benefits. Production wages and benefits are what percent of the wholesale price to the retailer?

Answers

If you would like to know what percent of the wholesale price to the retailer are production wages and benefits, you can calculate this using the following steps:

x% of $1,399.99 is $360.00
x% * 1,399.99 = 360.00
x/100 * 1,399.99 = 360.00
x = 360.00 * 100 / 1,399.99
x = 25.71%

The correct result would be 25.71%.

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