MATHEMATICS HIGH SCHOOL

Help please quickly!!!

Answers

Answer 1

Answer:

Answer:

rotation

Step-by-step explanat

Answer 2

Answer: The answer is rotation,hope this helps:)

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Triangle ABC has side lengths 18,24, and 30. Do the side lengths form a Pythagorean triple? Yes or No?

Answers

Answer: Yes, the side lengths form a pythagorean triple.

Step-by-step explanation: Given that the side lengths of triangle ABC are as follows :

$AB=18,~~BC=24,~~CA=30.$

We are to check whether the side lengths form a pythagorean triple or not.

For making a pythagorean triple, the side lengths must satisfy the following :

$AB^2+BC^2=CA^2.$

We have

$AB^2=18^2=324,\n\nBC^2=24^2=576,\n\nCA^2=30^2=900.$

So,

$AB^2+BC^2=324+576=900=CA^2.$

Thus, the side lengths will form a pythagorean triple.

yes, the equation is a^2+b^2=c^2 so if u take 18^2+24^ it equals 900 so to test that you take 30^2 which is = to 900 also so yes

Question 2 (Multiple Choice Worth 6 points)(09.03 LC)

Tanya drives to work every day and passes two independently operated traffic lights. The probability that both lights are red is 0.55. The probability that the first light is red is 0.69. What is the probability that the second light is red, given that the first light is red?
0.83
0.75
0.80
0.73

Answers

Answer:

Step-by-step explanation:

Let the probability that the first light is red is= $P_(1)$ and

the probability that the second light is red= $P_(2)$ . Then,

Probability that both lights are red= $P( P_(1) and P_(2) )$ = 0.55,

Probability that the first light is red= $P(P_(1))$ =0.69,

Probability that the second light is red, given that the first light is red= $P( P_(2) /P_(1))$ = $(P(P_(1) and P_(2)) )/(P(P_(1)) )$

= $(0.55)/(0.69)$

= $0.7971$

≈ $0.80$

Given:
Probability that both lights are red 0.55
Probability that 1st light is red 0.69

Find the probability that the 2nd light is red, given that the first light is red.

0.55/0.69 = 0.797 or 0.80

The probability that the 2nd light is red while the 1st light is also red is 0.80.

39 out of 40 as a percent