6x + 10 + 2x = 42
Solve with variables

Answers

Answer 1
Answer:

Answer:

4

Step-by-step explanation:

Step 1:

6x + 10 + 2x = 42          Equation

Step 2:

8x + 10 = 42     Combine Like Terms

Step 3:

8x = 32     Subtract 10 on both sides

Step 4:

x = 32 ÷ 8     Divide

Answer:

x = 4

Hope This Helps :)


Related Questions

PLEASE HELP MEEEEEEEEEEEEE
A study was produced which involved 800 randomly selected individuals. Each participant was asked to identify whether they were currently employed or not. 583 responded they were employed while 148 responded that they were not employed. Identify the problem with this study.loaded questions nonresponse correlation and causality self interest
What is the length of a rectangle with width 10 inches and area 45 inches^2? Use 3.14
The length of a football field is 120 yd. The width of the football field is 50 yd. Which is the correct unit of measurement to use when figuring out how much rope is needed to surround the field? A. yd B. yd2 C. yd3
HELP ASAP CLICK Here !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Create a quadratic polynomial function f(x) and a linear binomial in the form (x − a).Show all work using long division to divide your polynomial by the binomial.

Answers

x - a is divisor of f(x) if and only if f(a) = 0

f(x) = x^2 -1

linear binomial: x + 1

(x^2 - 1)/(x + 1) = (x + 1)(x - 1)/(x + 1) = x - 1
hence is a divisor

f(1) = 0
so it corroborates the reminder theorem

If an object is dropped from a height of 144 feet, the function h(t) = -16t2 + 144 gives the height of the object after t seconds. When will the object hit the ground? A) 9 seconds

B) 6 seconds

C) 1.5 seconds

D) 3 seconds

Answers

So this question is asking for the zeros, or the x-intercepts, of this equation. For this, we have to set h(t) to zero to solve for it.

For this, we will be using the quadratic formula, which is x=(-b+√(b^2-4ac))/(2a),(-b-√(b^2-4ac))/(2a) (a = t^2 coefficient, b = t coefficient, and c = constant). In this case, our equation is t=(-0+√(0^2-4*(-16)*144))/(2*(-16)),(-0-√(0^2-4*(-16)*144))/(2*(-16)) . From here we can solve for t.

  1. Firstly, solve the exponents and multiplications: t=(-0+√(0+9216))/(-32),(-0-√(0+9216))/(-32)
  2. Next, solve the additions and subtractions: t=(√(9216))/(-32),(-√(9216))/(-32)
  3. Next, square root 9216: t=(96)/(-32),(-96)/(-32)
  4. Lastly, divide and your answers are going to be t=-3,3

Since we cannot have negative time,the object hits the ground at 3 seconds, or D.

1200+0.075x>=3300 what is the solution to the inequality

Answers

Solving inequalities is just like solving any other Algebraic problem...look to P.E.M.D.A.S. (Parenthesis, Exponents, Division, Addition, Subtraction). So lets take a look at this problem now.

1200 + 0.075x\geq3300


Subtract 1200 from both sides...
0.075x\geq2100

Now divide by 0.075...
x\geq28000


NOTE: If you divide or multiple by a negative number while solving inequalities, you must flip the sign. Ex: You answer would be x\leq28000 if you would've multiplied or divided by a negative.




Which of the following are true? Group of answer choices a.As long as the function is defined anywhere in your program,
b.it can be used anywhere else.
c.A function can call another function.

Answers

Answer:

c. A function can call another function

Step-by-step explanation:

A function can call function inside its body ( the function can be itself as well as another function)

In case, function calls itself in its body, is termed as "Recursion".

The prime factorization of
is 24 x 5

Answers

Answer:

80

Step-by-step explanation:

Answer:

5 x 24 = 120

120 pf= 2 x 2 x 2 x 3 x 5

or the answer is

2^3    x 3 x 5

Step-by-step explanation:

Regular Hexagon ABCDEF rotates 240' counterclockwise about its center to produce hexagon A'B'C'D'E'F'. Which points will A' and B' coincide within the pre image

Answers

Answer:

A' will coincide with C of the pre image, and B' will coincide with D of the pre image.

Step-by-step explanation:

A Regular Hexagon could be imagined as a circle divided into six points on the circle, that are separated by angles of 60° (notice that 6 times 60° is 360°).

Now we name each point as ABCDEF clockwise, and then we rotate the hexagon about its center (counterclockwise)... the original points ABCDEF are renamed as A'B'C'D'E'F' in the rotated hexagon.

As the rotation was of 240°, the points will coincide with some of the original points: point A will "jump" for points, the same as point B.

This means that point A rotated, (wich is A') will coincide with point C pre rotated, and that point B rotated, (wich is B') will coincide with point D pre rotated.