Carlos purchased an antique chair for $56.He later sold the chair for $68 to an antique
dealer. What was the percent markup of the
chair?

Answers

Answer 1

Answer:

Answer:

about 22 percent

Step-by-step explanation:

Related Questions

Dylan and Julia are each making lemonade for a competition at the Sun City Citrus Festival. Both of their recipes call for the same amount of lemon juice, but Julia's recipe calls for more water than Dylan's recipe. Whose lemonade will have a stronger lemon flavor?
K = (°F + 460) ÷ 1.8 Find the temperature in Kelvin, on a balmy Autumn day, where the thermometer reads 56 Farenheit. A) 286.67 Kelvin. B) 315.56 Kelvin. C) 884.00 Kelvin. D) 918.88 Kelvin.
A box contains 8 chocolate, 4 powdered sugar, 6 cinnamon, and 6 red velvet munchkins. If you grab a munchkin, eat it, and then grab another one, what is P(chocolate, and then red velvet)? Show your work.
When are the expressions 5(p + 4) and 5p + 20 equivalent?
PLEASE HELP IF YOU KNOW THIS!!!!!

What is the value of the expression when a = 6, b = 4, and c = 8? 2a/3b−cA: 1

B: 3

C: 8

D: 12

Answers

Answer:

Step-by-step explanation:

$(2a)/(3b-c) \n=(2(6))/(3(4) - 8) \n=(12)/(12-8) \n=(12)/(4) \n=3$

I hope I was of assistance! #SpreadTheLove <3

Please help thank youuu

Answers

Answer:

D: 61 degrees.

Step-by-step explanation:

right angles add up to 90 degrees.

Answer:

61 degrees

Step-by-step explanation:

29+x=90

x=90-29

x=61

Hello can you please help me posted picture of question

Answers

This is true statement.

Sample space is made from all the possible outcomes that an event can have.
For example when tossing a coin, the possible outcomes are Head and Tail so the sample space will be {Head, Tail}.

Thus, option A is the correct answer

Compute the area of the region D bounded by xy=1, xy=16, xy2=1, xy2=36 in the first quadrant of the xy-plane. Using the non-linear change of variables u=xy and v=xy2, find x and y as functions of u and v.x=x(u,v)= ?

y=y(u,v)=?

Find the determinant of the Jacobian for this change of variables.

∣∣∣∂(x,y)/∂(u,v)∣∣∣=det=?

Using the change of variables, set up a double integral for calculating the area of the region D.

∫∫Ddxdy=?

Evaluate the double integral and compute the area of the region D.

Area =

Answers

Answer:

53.7528

Step-by-step explanation:

Notice that when

$xy = 1 ,\,\,\, xy = 16 , \,\,\, xy^2 = 1 \,\,\,, xy^2 = 36 \n\n$

If you set

$u = xy , v = xy^2$

as they suggest, then

$y = (v)/(u)} \,\,\,\, \text{and} \,\,\,\, \n\n{\displaystyle x = (u)/(y) = (u)/(v/u) = (u^2)/(v)$

Then

${\diplaystyle (\partial(x,y))/(\partial(u,v))} =\det \begin{pmatrix} 2u/v && -u^2/v^2 \n -v/u^2 && 1/u \end{pmatrix} = (1)/(v) }$

Therefore

$\iint\limits_(D) dx\,dy = \int\limits_(1)^(36)\int\limits_(1)^(16) (1)/(v) \, du \, dv = 15 \ln(36) = 53.7528$

A Jacobian matrix is formed by the first partial derivatives of a multivariate function that utilizes a training algorithm, and further calculation as follows:

Jacobian:

To evaluate the integral, cover the bounds, the integrand, and the differential area dA.

Transform the four equations in terms of u and v, notice that $u= xy \ \ and \ \ xy = 1, xy = 16$

implies that $1\leq u \leq 16.$

Similarly, $v= xy^2\ \ and\ \ xy^2= 1 , xy^2= 25$ implies that $1 \leq v \leq 25$

so write this integration region as $S= {(u,v) |1 \leq u \leq 18, 1 \leq v \leq 25}.$

Translate the equations from uv - plane to xy- plane. It is obtained by solving,

$u= xy, y= xy^2 \n\n\left.\begin{matrix}u=xy & \n v=xy^2& \end{matrix}\right\} \to \left.\begin{matrix}u^2=x^2y^2 & \n v=xy^2& \end{matrix}\right\} \n\n\to x=(u^2)/(v), y=(v)/(u)$

Convert dA part of the integral , using is $dA= |(\partial (x,y))/(\partial(u,v))| dudv.$

That is, $dA= \begin{vmatrix}(\partial x)/(\partial u) & (\partial x)/(\partial v)\n (\partial y)/(\partial u) & (\partial y)/(\partial v) \end{vmatrix} \ du dv \n\n$

Sampule the partial derivatives to find the Jacobian.

$dA=\begin{vmatrix}(2u)/(v) &-(u^2)/(v^2) \n -(v)/(u^2) &(1)/(u) \end{vmatrix} \ dudv\n\n=[((2u)/(v)) ((1)/(u)) -(- (u^2)/(v^2))(-(v)/(u^2))]\ du dv\n\n=((2)/(v)- (1)/(v)) \ dudv\n\n=(1)/(v)\ du dv\n\n$

The Jacobian the transformation is $dA= (1)/(v)dudv$

The region is $S={(u,v) |1\leq u \leq 16, 1\leq v\leq 25}.$

Rewrite the integral, using the transformation: $S,\ x=(u^2)/(v) =, y=(v)/(u) \ \ and\ \ dA=(1)/(v) dudv\n\n\int\int_R 1dA =\int \int_S (1)/(v)\ dudv= \int^(25)_(1) \int^(16)_(1) \ (1)/(v) \ dudv\n\n$

Evaluate the inner integral with respect to u.

$\to \int\int_R 1dA = \int^(25)_(1) \int^(16)_(1) \ (1)/(v) \ dudv\n\n$

by solving the value we get

$= 30 \ ln (5) \approx 48.28$

Find out more about the Jacobians here:

brainly.com/question/9381576

You have decided to wallpaper your rectangular bedroom. the dimensions are 12 feet 6 inches by 10 feet 6 inches by 8 feet 0 inches high. the room has two windows, each 4 feet by 3 feet and a door 7 feet by 3 feet. determine how many rolls of wallpaper are needed to cover the walls, allowing 10% for waste and matching. each roll of wallpaper is 30 inches wide and 30 feet long. how many rolls of wallpaper should be purchased?

Answers

The wall area is the product of the room perimeter and the room height:
A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²

The window and door area together is
A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²

The area of one roll of wallpaper is
A₃ = (2.5 ft)*(30 ft) = 75 ft²

Then the number of rolls of wallpaper required will be
1.1*(A₁ - A₂)/A₃ ≈ 4.74

5 rolls of wallpaper should be purchased.

_____
As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).

Travis milks his cows each morning. He has never gotten fewer than 3 gallons of milk; however, he always gets fewer than 9 gallons of milk.