How would the environment impact a multifactorial trait like height in someone with normal genetic variation? How would environment impact someone with a mutation that results in dwarfism?

Answers

Answer 1
Answer:

Answer:

Explanation:

On someone with a normal genetic variation, the environment helps them adapt and pushes for the evolution of the traits that will help that species increase their chances of survival in future generations. This includes traits such as height, thus increasing this trait so that the species is able to reach food in higher places or reach higher places in order to find shelter. This does not have the same effect when dealing with a certain genetic mutation such as dwarfism since the mutation targets a specific value for these traits and is not affected by its environment.

Answer 2
Answer:

Final answer:

The environment can influence height in individuals with normal genetic variation through factors such as nutrition and exercise. However, the impact of the environment on someone with a mutation leading to dwarfism is less significant.

Explanation:

The environment can impact a multifactorial trait like height in someone with normal genetic variation through factors such as nutrition, exercise, and overall health. For example, a well-nourished individual who engages in regular physical activity may reach their full potential height. On the other hand, an environment with inadequate nutrition or limited access to healthcare could lead to stunted growth and shorter height.

In the case of someone with a mutation resulting in dwarfism, the impact of the environment may be less significant. Dwarfism is primarily caused by genetic mutations that affect the production of growth hormone. While environmental factors can still influence overall health and well-being, they are unlikely to significantly alter the person's height.

Therefore, the environment plays a more prominent role in affecting height in individuals with normal genetic variation compared to those with a specific genetic mutation causing dwarfism.

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Explain why hormones are able to travel through the body but only affect certain cells.

Answers

Answer:

Hormones are able to travel the body but only affect certain cells because only those target cells have receptors for that particular hormone. Some hormones bind to receptors on the surface of target cells. Others enter the cells and bind to receptors in the cytoplasm or nucleus.

The different processes that an animal, such as an insect,goes through as it grows and reproduces is called its

Answers

Answer:

Life cycle is my answer

Explanation:

it might be wrong

Anonymousanonymous 3 years ago
Sue lives in a coastal location. Every year she enjoys surfing from November to February. She never goes surfing from May to August. Which of these statements best explains Sue's behavior?
From May to August, the ocean water is more dense.
From May to August, the beaches are warm and sunny.
From November to February, the tides take water further offshore.
From November to February, strong winds create high, steady ocean waves.
Biology

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From November to February, strong winds create high, steady ocean waves.

Which cell is a plant cell?

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Answer:

b

Explanation:

_____releases carbon dioxide as a waste product. *Chloroplast
O Cytoplasm
Ribosomes
O Mitochondria

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Answer:

Mitochondria

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If the metabolic rate of cockroaches at 15°C is 0.01 ml O2/hr and their metabolic rate at 25°C is 0.015 ml O2/hr. What is its metabolic rate at 20°C?

Answers

Answer:

0.0035 mL of oxygen per hour is metabolic rate at 20°C at cockroach.

Explanation:

  • Metabolic rate of cockroaches at 15°C is 0.01 ml O2/h
  • Metabolic rate of cockroaches at 25°C is 0.015 ml O2/hr

From the data we can see that metabolic rate of cockroach is in direct relation with temperature.

Rate \propto Time

On graph, with metabolic rate on y-axis and temperature on x axis straight line will obtained , and the equation of the line can be determined by the help of point slope:

(y-y_1)=m(x-x_1)

m = Slope of the line = (y_2-y_1)/(x_2-x_1)

As per information given , :

(x_1,y_1) , (x_2,y_2) = (15,0.01) (25,0.015)

m=(0.015-0.01)/(25-15)=(0.005)/(10)=0.0005

(y-0.01)=0.0005(x-15)

y-0.001=0.0005x-0.0075

y=0.0005x-0.0065

x = temperature

y = metabolic rate

Now , put x = 20

y=0.0005* 20-0.0065

y = 0.0035

0.0035 mL of oxygen per hour is metabolic rate at 20°C at cockroach.