Which two numbers both round to 1,500 when rounded to the nearest hundred?

Answers

Answer 1

Answer:

The two numbers where both round to 1,500 when rounded to the nearest hundred is option c. 1457 and 1547.

What is Rounded number?

The rounded number should be that where the number should be rounded to the nearest tenth, hundred or thousand

Since the number is 1500

So for hundred the number should be likely 1457 and 1547.

hence, the option c is correct.

learn more about number here: brainly.com/question/21474983

Answer 2

Answer:

Answer:

Step-by-step explanation:

Just take it lol

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The computer that controls a bank's automatic teller machine crashes a mean of 0.5 times per day. What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

Answers

Answer:

0.3216 = 32.16% probability that, in any seven-day week, the computer will crash less than 3 times

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval

Mean of 0.5

7-day week, so $\mu = 7*0.5 = 3.5$

What is the probability that, in any seven-day week, the computer will crash less than 3 times?

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

$P(X = 0) = (e^(-3.5)*(3.5)^(0))/((0)!) = 0.0302$

$P(X = 1) = (e^(-3.5)*(3.5)^(1))/((1)!) = 0.1057$

$P(X = 2) = (e^(-3.5)*(3.5)^(2))/((2)!) = 0.1850$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0302 + 0.1057 + 0.1857 = 0.3216$

0.3216 = 32.16% probability that, in any seven-day week, the computer will crash less than 3 times

Final answer:

To find the probability that the computer will crash less than 3 times in a seven-day week, we can use the binomial probability formula.

Explanation:

To find the probability that the computer will crash less than 3 times in a seven-day week, we can use the binomial probability formula. The formula for binomial probability is:

$P(X = k) = C(n, k) * p^k * (1-p)^{(n-k)$

Where:

P(X = k) is the probability of exactly k successes
C(n, k) is the combination function for choosing k items from a set of n
p is the probability of success for each individual trial
n is the number of trials

In this case, the mean number of crashes per day is 0.5, which means the probability of a crash in a single day is 0.5. Since we're interested in the probability of less than 3 crashes in a seven-day week, we can calculate P(X < 3) using the binomial probability formula with n = 7, p = 0.5, and k = 0, 1, 2:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

Using the binomial probability formula, we can calculate:

$P(X = 0) = C(7, 0) * 0.5^0 * (1-0.5)^(^7^-^0)\nP(X = 1) = C(7, 1) * 0.5^1 * (1-0.5)^(^7^-^1)\nP(X = 2) = C(7, 2) * 0.5^2 * (1-0.5)^(^7^-^2)$

Adding these probabilities together will give us the probability of less than 3 crashes in a seven-day week.

Rounding the final probability to four decimal places, we get the probability that the computer will crash less than 3 times in a seven-day week.

Learn more about Binomial probability here:

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A plant produces 500 units/hour of an item with dimensions of 4” x 6” x 2”. The manager wants to store two weeks of supply in containers that measure 3 ft x 4 ft x 2 ft. (Note: She can store the units in the containers such as that the 4” dimension aligns with either the 3 ft width or the 4 ft length of the box, whichever allows more units to be stored.) A minimum of 2 inches of space is required between adjacent units in each direction. If the containers must be stacked 4-high, and the warehouse ceiling is 9 feet above the floor, then determine the amount of floor space required just for storage.

Answers

Answer:

564 ft²

Step-by-step explanation:

To account for the extra space between units, we can add 2" to every unit dimension and every box dimension to figure the number of units per box.

Doing that, we find the storage box dimensions (for calculating contents) to be ...

3 ft 2 in × 4 ft 2 in × 2 ft 2 in = 38 in × 50 in × 26 in

and the unit dimensions to be ...

(4+2)" = 6" × (6+2)" = 8" × (2+2)" = 4"

A spreadsheet can help with the arithmetic to figure how many units will fit in the box in the different ways they can be arranged. (See attached)

When we say the "packing" is "462", we mean the 4" (first) dimension of the unit is aligned with the 3' (first) dimension of the storage box; the 6" (second) dimension of the unit is aligned with the 4' (second) dimension of the storage box; and the 2" (third) dimension of the unit is aligned with the 2' (third) dimension of the storage box. The "packing" numbers identify the unit dimensions, and their order identifies the corresponding dimension of the storage box.

We can see that three of the four allowed packings result in 216 units being stored in a storage box.

If storage boxes are stacked 4 deep in a 9' space, the 2' dimension must be the vertical dimension, and the floor area of each stack of 4 boxes is 3' × 4' = 12 ft². There are 216×4 = 864 units stored in each 12 ft² area.

If we assume that 2 weeks of production are 80 hours of production, then we need to store 80×500 = 40,000 units. At 864 units per 12 ft² of floor space, we need ceiling(40,000/864) = 47 spaces on the floor for storage boxes. That is ...

47 × 12 ft² = 564 ft²

of warehouse floor space required for storage.

_____

The second attachment shows the top view and side view of units packed in a storage box.

(4r2 – 3r + 2) – (-r2 – 3r) =

Answers

Answer:

5r^2+2

Step-by-step explanation:

(4r^2 – 3r + 2) – (-r^2 – 3r) =

Distribute the minus sign

(4r^2 – 3r + 2) +r^2 + 3r =

Combine like terms

(4r^2 + r^2 – 3r+ 3r + 2) =

5r^2+2

Forty-five CEO’s from the electronics industry were randomly sampled and a 99 % % confidence interval for the average salary of all electronics CEO’s was constructed. The interval was $101,866<μ<$115,016 $101,866<μ<$115,016 To make more useful inferences from the data, it is desired to reduce the width of the confidence interval. What will result in a reduced interval width? Select one: a. Any of these methods will result in a reduced interval width. b. Keep the sample size the same and decrease the confidence level. c. Keep the sample size the same and increase the confidence level. d. Decrease the sample size and keep the same confidence level.

Answers

Answer:

b. Keep the sample size the same and decrease the confidence level.

Step-by-step explanation:

We first have to find the critical value of z, which depends of the confidence level.

90% confidence level

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = (1-0.9)/(2) = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

99% confidence level

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = (1-0.99)/(2) = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

The width of the interval is:

$W = z*(\sigma)/(√(n))$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

So, as z increses, so does the width. If z decreases, the width decreases. Lower confidence levels have lower values of z.

As n increases, the width decreses.

What will result in a reduced interval width?

b. Keep the sample size the same and decrease the confidence level.

Find the perimeter of trapezoid WXYZ with vertices W(2, 3), X(4, 6), Y(7, 6), and Z(7,3). Leave your answer in simplest radical form.

Answers

Answer:

$Perimeter = 11 + √(13)$

Step-by-step explanation:

To find the perimeter of WXYZ we need to find the length of all four sides: WX, XY, YZ and WZ.

To find the length of each side, we can use the formula for the distance of two points:

$distance = √((x_1 - x_2)^2 + (y_1 - y_2)^2)$

So we have that:

$WX = √((2 - 4)^2 + (3 - 6)^2) = √(13)$

$XY = √((4 - 7)^2 + (6 - 6)^2) = 3$

$YZ = √((7 - 7)^2 + (6 - 3)^2) = 3$

$WZ = √((2 - 7)^2 + (3 - 3)^2) = 5$

The perimeter is:

$Perimeter = WX + XY + YZ + WZ$

$Perimeter = √(13) + 3 + 3 + 5 =11 + √(13)$

A cereal comes in three different package sizes. 8 ounce box $12, 12 ounce box $16,16 ounce box $20 what is the ratio of the coast of an 8 ounce box to a 16 ounce box of cereal

Answers

The ratio between two numbers can be written in terms of fraction by writing the first number as numerator and the second number as denominator. The ratio of the given two boxes is 0.6.

What is the application ratio and proportion?

A ratio is the relation between two numbers a and b as a / b. A proportion is the equality of two ratios as a / b = c / d.

Ratio and proportion can be applied to solve Mathematical problems dealing with unit values of the quantities.

Given that,

The cost of 8 ounce box is $12,

The cost of 12 ounce box is $16,

And, the cost of 16 ounce box is $20.

The ratio of two numbers a and b is given as a : b = a / b.

Thus the ratio of the cost of an 8 ounce box to a 16 ounce box is given as,

12 : 20

= 12 / 20

= 0.6.

Hence, the ratio between the cost of the two boxes is 0.6.

To know more about ratio and proportion click on,

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Check and simplify ratios:

8 ounces to 12 dollars - 8:12
Simplified: 2:3

16 ounces to 20 dollars - 16:20
Simplified: 4:5

Percentages?

2 / 3 = 66.66%
4 / 5 = 80%

The 16 ounce box has a larger ratio than the 8 ounce box

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