Calculate the current in the 200.-ohm resistor.
Answer:
current in 200ohm resistor = 0.05A
Explanation:
for current in 200 ohm resistor,
let 'I2' and 'R2' be current and resistance in 200 ohm resistor,
potential difference remains same thorughout the circuit because they are connected in parallel,
we have,
V=10V
R2=200 ohm
I2=?
then by ohm's law,
V=I2*R2
10=I2*200
I2=0.05A
The power dissipated by the 100-ohm resistor is 400 watts. The current in the 200-ohm resistor is 0.05 Amps.
To determine the power dissipated by the 100-ohm resistor, we can use the formula P = I^2 * R, where P is the power, I is the current, and R is the resistance. Since the current is the same throughout a parallel circuit, the current flowing through the 100-ohm resistor is the same as the total current in the circuit. Using the formula P = I^2 * R, we can calculate the power dissipated by the 100-ohm resistor as P = (2.00 A)^2 * 100 ohms = 400 watts.
To calculate the current in the 200-ohm resistor, we can use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R). In this case, the voltage supplied by the battery is 10.0 volts. Using Ohm's Law, we can calculate the current in the 200-ohm resistor as I = V / R = 10.0 V / 200 ohms = 0.05 Amps.
#SPJ2
Magnets are used in the doors of refrigerators and cupboards to keep the doors closed firmly, create a reliable seal, and increase energy efficiency.
Magnets are often fitted to the doors of refrigerators and cupboards for a reason rooted in physics. This setup helps in keeping the doors closed firmly. The magnets are usually embedded in the door seal, creating an attraction with the metal body of the refrigerator or cupboard. This magnetic attraction pulls the door seal flush against the refrigerator when the door is closed, making an airtight seal. As a result, it prevents the cold air inside the refrigerator from escaping, thereby maintaining the interior temperature and ensuring energy efficiency.
#SPJ3