If people from Georgia have just experienced an extremely cold winter the last couple of months, what would the climate most likely be classified as? Polar
Temperate
Maritime
Tropical

Answers

Answer 1
Answer: temperate I'm not sure, cuz polar is like freeze, and tropical is hot
Answer 2
Answer:

Answer:

polar

Explanation:

they said it was extreme so atleast it would be polar


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a balloon is ascending at 3.0 m/s at a height of 20.0 m above ground when a package is released. the time taken, in the absence of air resistance, for the package to reach the ground is:

Answers

Answer:

Approximately 2.35\; {\rm s}, assuming that g = 9.81\; {\rm m\cdot s^(-2)}.

Explanation:

Under the assumptions, the package would start with an initial upward velocity of u = 3.0\; {\rm m\cdot s^(-1)} and accelerate downward at a constant a = (-g) = (-9.81)\; {\rm m\cdot s^(-2)} (negative because acceleration points downward.)

Right before landing, the package would be 20.0\; {\rm m} below where it was released. Hence, the displacement of the package at that moment would be x = (-20.0)\; {\rm m} (negative since this position is below the initial position.)

The duration of the motion can be found in the following steps:

  • Apply the SUVAT equation v^(2) - u^(2) = 2\, a\, x to find velocity v right before landing.
  • Divide the change in velocity (v - u) by acceleration to find the duration of the motion.

Rearrange the SUVAT equation v^(2) - u^(2) = 2\, a\, x to find v, the velocity of the package right before reaching the ground. Notice that because the package would be travelling downward, the value of v\! should be negative.

\begin{aligned} v &= -\sqrt{u^(2) + 2\, a\, x} \n &= -\sqrt{(3.0)^(2) + 2\, (-9.81)\, (-20.0)}\; {\rm m} \n &\approx (-20.035)\; {\rm m}\end{aligned}.

Subtract the initial velocity from the new value to find the change in velocity. Divide this change in velocity by acceleration (rate of change in velocity) to find the duration of the motion:

\begin{aligned}t &= (v - u)/(a) \n &\approx ((-20.035) - (3.0))/((-9.81))\; {\rm s} \n &\approx 2.35\; {\rm s}\end{aligned}.

A 0.5 kg ball is dropped from rest at a point 1.2m above the floor. The ball rebounds straight upward to a height of 0.7m. What are the magnitude and direction of the impulse of the net force applied to the ball during the collision with the floor.

Answers

Answer:

4.281 kgm/s upward

Explanation:

Impulse:This can be defined product of force and time. The S.I unit of impulse is Ns.

From Newton's second law of motion,

Impulse = Change in momentum.

I = mΔv....................... Equation 1.

Where m = mass of the ball, Δv = change in velocity of the ball  

and Δv = v -u

Where u = velocity of the ball before it hit the floor, v = velocity of the ball after if hit the floor

I = m(v-u) -------------- Equation 2

But

the initial kinetic energy of the ball = potential energy at the initial height (1.2 m above)

1/2mu² = mgh₁

Where h₁ = initial height. or height of the ball before collision

making u the subject of the equation,

u = √(2gh₁)........................ Equation 3

Where h₁ = 1.2 m g = 9.81 m/s²

Substitute into equation 3

u = √(2×1.2×9.81)

u =√(23.544)

u = -4.852 m/s.

Note: u is negative because the ball was moving downward at the first instance.

Similarly,

v = √(2gh₂)............................. Equation 3

h₂ = height of the ball after collision

Given: h₂ = 0.7 m, g = 9.81 m/s²

Substitute into equation

v = √(2×9.81×0.7)

v = √13.734

v = 3.71 m/s.

Also given: m = 0.5 kg,

Substituting into equation 2

I = 0.5(3.71-(4.852)

I = 0.5(8.562)

I = 4.281 kgm/s. Upward.

Thus the impulse = 4.281 kgm/s upward

What of the following frequencies falls in the range of RF waves used by commercial radio broadcasting stations

Answers

There are no broadcasting frequencies included on your list.
In fact, there are no frequencies at all on your list.
In fact, there's no list !
Where are the choices ?  What does "the following" mean anyway ? ?

In the USA . . .

-- AM radio broadcasting operates between 550 KHz and 1.7 MHz.

-- FM broadcasting operates between 87.9 MHz and 108.1 MHz.

-- The numbers are slightly different in some other countries.

-- Regarding TV . . . don't ask.  It can get really complicated.

What do we call the minimum energy that is required by an electron to leave the metal target in the photoelectric effect?Select one of the options below as your answer: A. energy function B. minimum function C. work function D. quanta E. electrical energy

Answers

Answer:

C. work function

Explanation:

In the photoelectric effect, the energy of the incident photon is used in part to extract the electron from the metal (and this energy is called work function) and the rest is converted into kinetic energy of the electron. In formula:

hf = \phi +K

where

hf is the energy of the incident photon, which is the product between h (the Planck constant) and f (the photon's frequency)

\phi is the work function

K is the kinetic energy of the photoelectron as it leaves the material

The work function is what we call the minimum energy that is required by an electron to leave the metal target in the photoelectric effect. 

Which one of the following lenses is a converging lens

Answers

Hi There! :)

Which one of the following lenses is a converging lens

Double-convex lens

A force of 5 N gives to mass my and an acceleration of 8m/s2 and a mass m2an acceleration of 24m/s2. What acceleration would it give if both masses are
tied together

Answers

Answer:

a=6m/sec²

Explanation:

f=5 N

a1=8m/sec²

a2=24m/sec

m1=f/a1=5/8kg

m2=f/a2=5/24kg

New, f=(m1+m2)a

a=5/5/8+5/24=5/15+5/24=24*5/20

a=6m/sec²