Answer: no
Explanation:
force and distance are not in the same direction
Answer:
To calculate kinetic energy, you use the formula KE = 0.5 * m * v^2, where "m" is the mass and "v" is the speed. There isn't a common factor that works for every speed; the factor you use is 0.5. This formula is derived from the principles of classical mechanics and doesn't change with speed; it's a fundamental equation for calculating kinetic energy.
b. False
The statement ‘The Biot-Savart force law does not apply if the velocity is parallel to the field direction’ is true. The answer is letter A. Any electron moving in a conductor will produce a magnetic fiels around the flow. this is the fundamental of Biot – Savart law.
Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
Given:
mass of a lump of putty = m
mass of rubber ball = m
initial speed of putty = v
final speed of putty = 0
initial speed of rubber ball = v
final speed of rubber ball = -v
Asked:
the change in momentum = Δp = ?
Solution:
Lump of Putty :
Rubber Ball:
From calculation above , we can conclude that rubber ball will experience the greater momentum change than the lump of putty
Grade: High School
Subject: Physics
Chapter: Dynamics
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
The person who answered them all one of them is incorrect the rest are right. But the one about "Which variable is measured in an experiment?" The answer is dependent variable.
Answer:
Explanation:
Given:
Now, using Pascal's law which state that the pressure change in at any point in a confined continuum of an incompressible fluid is transmitted throughout the fluid at its each point.
is the required effort force.
Answer:
F = 1076 N
Explanation:
given,
small piston area, a = 0.075 m²
large piston area, A = 0.237 m²
weight on the large piston, W = 3400 N
force applied on the second piston, F = ?
using pascal law for the force calculation
F = 0.3165 x 3400
F = 1076 N
The force applied to the small piston in order to lift the engine is equal to 1076 N.