Write a paragraph describing the series of events that occur in the operation of a complex machine that you have used recently and Identify the simple machines that make up parts of the complex machine.

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Answer 1
Answer: Complex machine i dont but i need to answer a question so i can ask a question so that is why i am answering for u

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An ant sits on the back of a mouse. The mouse carries the ant across the floor for a distance of 10 meters. Was there work done by the mouse? Explain.

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yes because the mouse was moving with kts kwn force.

Answer: no

Explanation:

force and distance are not in the same direction

Think about multiplying each speed by a factor to calculate kinetic energy at that speed.Is there a common factor that works for every speed? If so, what’s this factor?

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Answer:

To calculate kinetic energy, you use the formula KE = 0.5 * m * v^2, where "m" is the mass and "v" is the speed. There isn't a common factor that works for every speed; the factor you use is 0.5. This formula is derived from the principles of classical mechanics and doesn't change with speed; it's a fundamental equation for calculating kinetic energy.

The Biot-Savart force law does not apply if the velocity is parallel to the field direction. a. True
b. False

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The statement ‘The Biot-Savart force law does not apply if the velocity is parallel to the field direction’ is true. The answer is letter A. Any electron moving in a conductor will produce a magnetic fiels around the flow. this is the fundamental of Biot – Savart law.

a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall. the ball bounces back at nearly the same speed with which it hit the wall. which object experiences the greater momentum change?

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The bouncy ball experiences the greater momentum change.

To understand why, you need to remember that momentum is actually
a vector quantity ... it has a size AND it has a direction too.

The putty and the ball have the same mass, and you throw them
with the same speed.  So, on the way from your hand to the wall,
they both have the same momentum.
Call it " M in the direction toward the wall ".

After they both hit the wall:

-- The putty has zero momentum.
    Its momentum changed by an amount of  M .

-- The ball has momentum of " M in the direction away from the wall ".
    Its momentum changed by an amount of  2M .

Rubber ball will experience the greater momentum change than the lump of putty

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Further explanation

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\large {\boxed {F = ma }

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

\texttt{ }

Given:

mass of a lump of putty = m

mass of rubber ball = m

initial speed of putty = v

final speed of putty = 0

initial speed of rubber ball = v

final speed of rubber ball = -v

Asked:

the change in momentum = Δp = ?

Solution:

Lump of Putty :

\Delta p_(putty) = mv_f' - mv_i

\Delta p_(putty) = m(0) - mv

\Delta p_(putty) = - mv

\texttt{ }

Rubber Ball:

\Delta p_(ball) = mv_f' - mv_i

\Delta p_(ball) = m(-v) - mv

\Delta p_(ball) = - 2mv

\texttt{ }

\Delta p_(ball) : \Delta p_(putty) = - 2mv : - mv

\Delta p_(ball) : \Delta p_(putty) = 2 : 1

\Delta p_(ball) = 2\Delta p_(putty)

\Delta p_(ball) > \Delta p_(putty)

From calculation above , we can conclude that rubber ball will experience the greater momentum change than the lump of putty

\texttt{ }

Learn more

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Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

A hypothesis is a lucky guess. True or False. . . Question 2.2. The conclusion of a study should always be that the hypothesis is correct. True. or False Question 3.3. Which variable is measured in an experiment? a. independent variable. b.dependent variable c.experimental variable. . . Question 4.4. Most scientists come up with questions to investigate out of the blue. True. or False

Answers

The answer for the first is False, it is not based on luck but on previously conducted research or previous studies. The second one is also False. Even not proving a hypothesis can help science because then future researches know what is not true and can create new hypotheses based on that. The third one is C. experimental variable. That's when everything is the same except for that one which makes it an experiment. The last one is also false. The questions are usually based on previous research that was studied, read, or similar.

The person who answered them all one of them is incorrect the rest are right. But the one about "Which variable is measured in an experiment?" The answer is dependent variable.

In a machine shop, a hydraulic lift is used to raise heavy equipment for repairs. The system has a small piston with a cross-sectional area of 0.075 m2 and a large piston with a cross-sectional area of 0.237 m2 . An engine weighing 3400 N rests on the large piston. What force must be applied to the small piston in order to lift the engine? Answer in units of N.

Answers

Answer:

F_s=1075.9493\ N

Explanation:

Given:

  • area of piston on the smaller side of hydraulic lift, a_s=0.075\ m^2
  • area of piston on the larger side of hydraulic lift, a_l=0.237\ m^2
  • Weight of the engine on the larger side, W_l=3400\ N

Now, using Pascal's law which state that the pressure change in at any point in a confined continuum of an incompressible fluid is transmitted throughout the fluid at its each point.

P_s=P_l

(F_s)/(a_s)=(W_l)/(a_l)

(F_s)/(0.075) =(3400)/(0.237)

F_s=1075.9493\ N is the required effort force.

Answer:

   F = 1076 N

Explanation:

given,

small piston area, a = 0.075 m²

large piston area, A = 0.237 m²

weight on the large piston, W = 3400 N

force applied on the second piston, F = ?

using pascal law for the force calculation

(F)/(W)=(a)/(A)

(F)/(3400)=(0.075)/(0.237)

   F = 0.3165 x 3400

   F = 1076 N

The force applied to the small piston in order to lift the engine is equal to 1076 N.