Need help with the equations thank you

Answers

Answer 1

Answer:

Step-by-step explanation:

Equation 1 = 2-6 over 1-3

Equation 1 = 1-4 over 2+3 Because instead of subtracting a negative you can write adding cause the double negative makes a positive

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What is the equation for the line that passes through (1, 1) and has a slope equal to 4?a. y = 4x – 3
b. y = 4x + 3
c. y = 3x + 4
d. y = 3x – 4
Which line is parallel to 2x + 4y = 6?
a. 4x + 6y = 8
b. 3x + 6y = –7
c. 4x + 2y = –6
d. 6x + 3y = 5

Answers

Hello,

1)
y-1=4(x-1)
==>y=4x-3
Answer A

2)
Only the answer B has a slope of -1/2

answer B

30 1/4% in simplest form

Answers

Answer: 1 1/5

Step-by-step explanation: Convert 1/4 into a decimal (.25) then find the percent of that decimal (25) simplify 30 (30/5) and 25 (25/5) then converted the fraction into a mixed number (1 1/5).

F(x) = 2x / (x-6) Find the domain of f (all permissible inputs of x)

Answers

Answer:

domain { x : x ∈ R, x ≠ 6 }

Step-by-step explanation:

given

f(x) = $(2x)/(x-6)$

the denominator of f(x) cannot be zero as this would make f(x) undefined

Equating the denominator to zero and solving gives the value that x cannot be.

x - 6 = 0 ( add 6 to both sides )

x = 6 ← excluded value in the domain

domain is {x : x ∈ R, x ≠ 6 }

karl needs to build a stage that has an area of 72 square feet. the length of the stage should be longer than the width. what are the possible whole number measurements for the length and width of the stage?

Answers

Length could be 9 width could be 8. Because 8 times 9 is 72.

length,width
9,8
12,6
72,1
18,4

Find f.

A) 7.4

B) 8.2

C) 10.5

D) 11.1

Answers

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^( 2 )+{ g }^( 2 )-{ f }^( 2 ) }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^( 2 )+{ 6 }^( 2 )-{ f }^( 2 ) }{ 2\cdot e\cdot 6 } \n \n \cos { \left( 72 \right) } =\frac { { e }^( 2 )+36-{ f }^( 2 ) }{ 12e }$

$\n \n 12e\cdot \cos { \left( 72 \right) } ={ e }^( 2 )+36-{ f }^( 2 )\n \n \therefore \quad { f }^( 2 )={ e }^( 2 )-12e\cdot \cos { \left( 72 \right) } +36\n \n \therefore \quad f=\sqrt { { e }^( 2 )-12e\cdot \cos { \left( 72 \right) +36 } } \n \n \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \n \n \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \n \n \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

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Answer:

hi Krystal , I am Felicia

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