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8=16-8n Solve for N
N=

Answers

Answer 1
Answer:

Answer:

N=1

Step-by-step explanation:

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Find three consecutive integers whose sum is 216. (Hint: if n represents the smallest of the three integers, n + 1 and n + 2 representthe other two numbers.)

Answers

Answer:

71, 72, 73

Step-by-step explanation:

So we want to find three consecutive integers that equal 216.

Let the first integer be n.

Then the second integer is n+1, and the third integer is n+2.

Thus:

n+(n+1)+(n+2)=216

Combine like terms:

3n+3=216

Subtract 3 from both sides:

3n=213\n

Divide 3 from both sides:

n=71

So, the first term is 71.

And the other two is 72 and 73.

And we are done :)

The legend on a map states that 1 cm is 20 km. If you measure 9 centimeters on the map, how many kilometers would the actual distance be?

Answers

Making a proportion helps solve this problem. Cm on top, km on bottom.


1 9

---- = ----

20 ?


Cross multiply to get 1? = 180


? = 180.


The distance is 180 km.

Final answer:

The conversion of 9 cm on the map to an actual distance, using the given scale of 1 cm for 20 km, results in an actual distance of 180 kilometers.

Explanation:

The question is asking for the actual distance corresponding to 9 cm on the map. According to the given scale on the map, 1 cm corresponds to an actual distance of 20 km. So to find out how many kilometers 9 cm on the map would be in real life, we simply multiply the length measured on the map by the distance each centimeter represents. This gives us:

9 cm * 20 km/cm = 180 km

So, according to the map, 9 cm corresponds to an actual distance of 180 kilometers.

Learn more about Map Scale Conversion here:

brainly.com/question/32219836

#SPJ3

You have just completed an experiment measuring the length (in mm) of 12 soybean plants after 3 days of sprouting. The measurements are listed below:53 47 51 54 43 39 61 57 55 46 44 43

If you doubled every measurement in this dataset (e.g., 106, 94, 102, ...), what would the new IQR equal? (Think about the SD too!)

Answers

Answer:

The new IQR is 22.    

Step-by-step explanation:

We are given the following data of  length (in mm) of 12 soybean plants after 3 days of sprouting.

53, 47, 51, 54, 43, 39, 61, 57, 55, 46, 44, 43

Sorted data:

39, 43, 43, 44, 46, 47, 51, 53, 54, 55, 57, 61

Formula:

IQR = Q_3 - Q_1\nQ_3 = \text{upper median},\nQ_1 = \text{ lower median}

Median:\n\text{If n is odd, then}\n\nMedian = \displaystyle(n+1)/(2)th ~term \n\n\text{If n is even, then}\n\nMedian = \displaystyle((n)/(2)th~term + ((n)/(2)+1)th~term)/(2)  

Median ==(6^(th)+7^(th))/(2) (47+51)/(2) = 49

Q_1 =(3^(rd)+4^(th))/(2) = (43 + 44)/(2) = 43.5\n\nQ_3 =(9^(th)+10^(th))/(2)= (54 + 55)/(2) = 54.5

IQR = Q_3 -Q_1 =54.5-43.5= 11

If every measurement is doubled, then, the IQR will also double itself.

Thus,

New IQR =

2* \text{IQR}\n=2\TIMES 11\n=22

Thus, the new IQR is 22.

Please help!! Need to know ASAP

Answers

Answer:

Quadratic function

Step-by-step explanation:

Hope this helps you. Have a great day and I hope to get a brainliest.

Find the Unit Rate: Twenty emails in 5 minutes.

Answers

Answer:

4 emails per minute

Step-by-step explanation:

20/5=4

Pleaseeeee helpppppppppppp

Answers

9514 1404 393

Answer:

  • maximum height: 26.5 ft
  • air time: 2.5 seconds

Step-by-step explanation:

I find the easiest way to answer these questions is to use a graphing calculator. It can show you the extreme values and the intercepts. The graph below shows the maximum height is 26.5 ft. The time in air is about 2.5 seconds.

__

If you prefer to solve this algebraically, you can use the equation of the axis of symmetry to find the time of the maximum height:

  t = -b/(2a) = -(40)/(2×-16) = 5/4

Then the maximum height is ...

  h(5/4) = -16(5/4)² +40(5/4) +1.5 = -25 +50 +1.5 = 26.5 . . . feet

__

Now that we know the vertex of the function, we can write it in vertex form:

  h(t) = -16(t -5/4)² +26.5

Solving for the value of t that makes this zero, we get ...

  0 = -16(t -5/4)² +26.5

  16(t -5/4)² = 26.5

  (t -5/4)² = 26.5/16 = 1.65625

Then ...

  t = 1.25 +√1.65625 ≈ 2.536954

The cannon ball is in the air about 2.5 seconds.
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