Answer: No.
Step-by-step explanation: It's obviously a quiz of some sort. If it's not, then why would it be timed? Please don't do this :(
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Answer:
see attached
Step-by-step explanation:
Most of this exercise is looking at different ways to identify the slope of the line. The first attachment shows the corresponding "run" (horizontal change) and "rise" (vertical change) between the marked points.
In your diagram, these values (run=1, rise=-3) are filled in 3 places. At the top, the changes are described in words. On the left, they are described as "rise" and "run" with numbers. At the bottom left, these same numbers are described by ∆y and ∆x.
The calculation at the right shows the differences between y (numerator) and x (denominator) coordinates. This is how you compute the slope from the coordinates of two points.
If you draw a line through the two points, you find it intersects the y-axis at y=4. This is the y-intercept that gets filled in at the bottom. (The y-intercept here is 1 left and 3 up from the point (1, 1).)
y − x = 9
The linear-quadratic system has
(select)
points of intersection.
Answer:
2 points of interception of (3.12 , 12./12) and (-5.12 , 3.87)
Step-by-step explanation:
y − x = 9
y = x + 9
x+9 = x²+3x-7
x²+2x-16=0
x = (-2±√2²-4(1)(-16)) / 2 = (-2 ± √68) / 2 = -1 ± √17
x = 3.12 or x = -5.12
y = 12.12 or y = -3.87
Answer:
The coordinates of O is (d,c) .
Option (a) is correct .
Step-by-step explanation:
As given
In the coordinate plane, three vertices of rectangle MNOP are M(0, 0), N(0, c), and P(d, 0).
As MNOP is a rectangle .
Thus opposite sides of the rectangles are equal .
Formula
NM = c units
MP = d units
Thus the coordinate of the O (d,c) .
(This is because opposit sides of the rectangle are equal thus distance of point O from point P must be d and distance of point O from point N must be c .)
Therefore the coordinates of O is (d,c) .
Option (a) is correct .
The width of the rectangular lot is 33 meters and the length of the rectangular lot is 37 meters.
Let, the width of the rectangular lot is W meters.
According to the problem, the length of the rectangular lot is 4 meters more than the width, so the length would be (W + 4) meters.
Now, we can use the formula for the perimeter of a rectangle:
Perimeter = 2 * Length + 2 * Width
Given that the perimeter is 140 meters, we can set up the equation:
140 = 2 * (W + 4) + 2 * W
Now, solve for W:
140 = 2W + 8 + 2W
Combine like terms:
140 = 4W + 8
Subtract 8 from both sides:
132 = 4W
Finally, divide by 4:
W = 33
So, the width of the rectangular lot is 33 meters.
Now, we can find the length:
Length = Width + 4
Length = 33 + 4
Length = 37
Therefore, the length of the rectangular lot is 37 meters.
Learn more about perimeter here:
#SPJ3
the length is 37 and the width is 33 if you add 33+33+37+37 you get 140
thus obtained is N ÷ 21. Find N.