12q+-8=16q I need help quick!!!!

Answers

Answer 1
Answer:

Answer:

q=-2

Step-by-step explanation:

12q+-8=16q

12q+(-8)=16q

Start by getting rid of the addition sign, as a positive multiplied by a negative is negative:

12q-8=16q

Subtract 12q from both sides of the equation:

-8=4q

Divide both sides of the equation by the coefficient of q, which is 4:

-2=q

or

q=-2

_

Check your by substituting the solved q value in to the initial equation:

12(-2)+(-8)=16(-2)

-24-8=-32

-32=-32

Since both sides of the equation are equal, our answer is correct!

Answer 2
Answer:

Answer:

q=-2

Step-by-step explanation:


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Answers

The answer is 8.5

Hope this helped

Refer to the graph. Find the slope of each line

Answers

the top line has a slope of 2/4 which reduces to 1/2 and the second line has a slope of -1/4

Answer:

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Answers

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Answers

12y+11
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Find the mode.19, 1, 17, 19, 3, 20, 5, 2


A. 10.75
B. 11
C. 19
D. 20

Answers

The answer is C. 19

Rearrange the series from the lowest to the highest value:
1, 2, 3, 5, 19, 19, 20

The mode is the value that occurs most frequently. Number 19 is found twice, so it is the mode.
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Which statements about the graph of the function f(x) = 2x2 – x – 6 are true? Check all that apply.The domain of the function is .


The range of the function is all real numbers.


The vertex of the function is .


The function has two x-intercepts.


The function is increasing over the interval (, ∞

Answers

The correct answer for the question that is being presented above is this one: "The range of the function is all real numbers; The function has two x-intercepts. The statements about the graph of the function f(x) = 2x2 – x – 6 that are true includes: The range of the function is all real numbers; The function has two x-intercepts.

we have

f(x) = 2x^(2) -x-6

using a graphing tool

see the attached figure

This is a quadratic equation (vertical parabola) open up

The vertex is a minimum---------> Vertex (0.25,-6.125)

The domain of the function is all real numbers-------> interval (-∞,∞)

The range of the function is the interval----------> [-6.125,∞)

The function has two x-intercepts-----> (-1.5,0) and (2,0)

The function is increasing over the interval-----> (0.25,∞)

The function is decreasing over the interval-----> (-∞,0.25)