MATHEMATICS COLLEGE

6. Find the value of the expression.
40 = 8 x 9

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

Answer 2

Answer: 72 I KNOW THIS bye thanks

Related Questions

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1 For a recipe, Paul uses 3 cups of sugar for every 4 cups of flour. Which table showsequivalent ratios for this recipe?

Mary wants to buy a new house but needs money for the down payment. Her parents agree to lend her money at an annual rate of 2%, charged as simple interest. They lend her $6000 for 3 years. She makes no payments except the one at the end of that time. Answer the following questions. If necessary, refer to the list of financial formulas. (a) How much total interest will Mary have to pay?
(b) What will the total repayment amount be (including interest)? X

Answers

Answer:

a) Simple interest paid = $360

b) Total repayment amount = $6360

Step-by-step explanation:

It is given that:

Principal, P = $6000

Rate of interest, R = 2%

Time, T = 3 years

(a) Total interest paid:

Formula for Simple Interest is given as:

$S.I. = (P * R * T)/(100)$

Putting the values of P, R and T to find out Simple Interest: $\n\Rightarrow S.I. = (6000 * 2 * 3)/(100)\n\Rightarrow S.I. = \$360$

(b) Total repayment amount:

We know that formula for total amount is given as:

Amount = Principal + Simple Interest

Amount = 6000 + 360 = $6360

So, total repayment amount = $6360

So, the answers are:

a) Simple interest paid = $360

b) Total repayment amount = $6360

ree heights: Cherry trees in a certain orchard have heights that are normally distributed with mean μ = 119 inches and standard deviation σ = 17 inches. Use the TI-84 PLUS calculator to answer the following. Round the answers to at least four decimal places. (a) What proportion of trees are more than 130 inches tall? (b) What proportion of trees are less than 90 inches tall? (c) What is the probability that a randomly chosen tree is between 95 and 105 inches tall? Part: 0 / 30 of 3 Parts Complete Part 1 of 3 What proportion of trees are more than 130 inches tall? The proportion of trees that are more than 130 inches tall is .

Answers

Answer:

a) 0.2588

b) 0.044015

c) 0.12609

Step-by-step explanation:

Using the TI-84 PLUS calculator

The formula for calculating a z-score is is z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

From the question, we know that:

μ = 119 inches

standard deviation σ = 17 inches

(a) What proportion of trees are more than 130 inches tall?

x = 130 inches

z = (130-119)/17

= 0.64706

Probabilty value from Z-Table:

P(x<130) = 0.7412

P(x>130) = 1 - P(x<130) = 0.2588

(b) What proportion of trees are less than 90 inches tall?

x = 90 inches

z = (90-119)/17

=-1.70588

Probability value from Z-Table:

P(x<90) = 0.044015

For x = 95

z = (95-119)/17

= -1.41176

Probability value from Z-Table:

P(x = 95) = 0.07901

For x = 105

z = (105 -119)/17

=-0.82353

Probability value from Z-Table:

P(x<105) = 0.2051

The probability that a randomly chosen tree is between 95 and 105 inches tall

P(x = 105) - P(x = 95)

0.2051 - 0.07901

= 0.12609

Tina makes 480 sandwiches

Answers

Why is Tina making so many sandwiches?

I´ll go find if there is the rest of the question

I believe if this is the correct question then this would be the rest

Tina makes 480 sandwiches she only makes tuna sandwiches, beef sandwiches, hand sandwiches and cheese sandwiches. 3/8 of the sandwiches are tuna. 35% of the sandwiches are beef. the ratio of the number of ham sandwiches to the number of cheese sandwiched is 5 : 6. work out the number of ham sandwiches that Tina makes

3 / 8 ×480 + 35 /100× 480 + 5x + 6x = 480

180 + 24 × 7 + 11x = 480

180 + 168 + 11x = 480

348 + 11x = 480

11x = 480 - 348

= 132

x = 132 / 11

= 12

no of ham sandwiches = 5x

= 5 ×12

= 60

therefore , the # of ham sandwiches = 60

HOPe tHIS HELPS

An elementary school is offering 3 language classes: one in Spanish, one inFrench, and one in German. The classes are open to any of the 100 students inthe school. There are 28 students in the Spanish class, 26 in the French class,and 16 in the German class. There are 12 students that are in both Spanish andFrench, 4 that are in both Spanish and German, and 6 that are in both Frenchand German. In addition, there are 2 students taking all 3 classes.(a) If a student is chosen randomly, what is the probability that he or she isnot in any of the language classes

Answers

Answer:

0.5 = 50% probability that he or she is not in any of the language classes.

Step-by-step explanation:

We treat the number of students in each class as Venn sets.

I am going to say that:

Set A: Spanish class

Set B: French class

Set C: German class

We start building these sets from the intersection of the three.

In addition, there are 2 students taking all 3 classes.

This means that:

$(A \cap B \cap C) = 2$

6 that are in both French and German

This means that:

$(B \cap C) + (A \cap B \cap C) = 6$

$(B \cap C) = 4$

4 French and German, but not Spanish.

4 that are in both Spanish and German

This means that:

$(A \cap C) + (A \cap B \cap C) = 4$

$(A \cap C) = 2$

2 Spanish and German, but not French

12 students that are in both Spanish and French

This means that:

$(A \cap B) + (A \cap B \cap C) = 12$

$(A \cap B) = 10$

10 Spanish and French, but not German

16 in the German class.

This means that:

$(C - B - A) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 16$

$(C - B - A) + 2 + 4 + 2 = 16$

$(C - B - A) = 8$

8 in only German.

26 in the French class

$(B - C - A) + (A \cap B) + (B \cap C) + (A \cap B \cap C) = 26$

$(B - C - A) + 10 + 4 + 2 = 26$

$(B - C - A) = 10$

10 only French

28 students in the Spanish class

$(A - B - C) + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 16$

$(A - B - C) + 10 + 2 + 2 = 28$

$(A - B - C) = 14$

14 only Spanish

At least one of them:

The sum of all the above values. So

$(A \cup B \cup B) = 14 + 10 + 8 + 10 + 2 + 4 + 2 = 50$

None of them:

100 total students, so:

$100 - (A \cup B \cup B) = 100 - 50 = 50$

(a) If a student is chosen randomly, what is the probability that he or she is not in any of the language classes?

50 out of 100. So

50/100 = 0.5 = 50% probability that he or she is not in any of the language classes.

Find the value of X Need help ASAP.

Answers

1. 4 inside angles must sum to 360:

X = 360-45-65-95 = 155

2. All the outside angles must sum

To 360:

2x + 70+ 86 + 9 = 2x + 248

2x = 360-248

2x = 112

X = 112/2 = 56

3. Sum of interior angles for 6 sides figure = 720.

X = 720 - 90-120-130-140-150

X = 90

4. Exterior angles sum to 360

4x +x + 98 + 162 = 360

5x + 260 = 360

5x = 100

X = 100/5

X = 20

Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematical notation, and clearly identify the claim and type of testing.

Answers

Answer:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): $\mu \geq 2000$