Answer:
Explanation:
mammal(X) :- legs(X,4), arms(X,0).
mammal(X) :- legs(X,2), arms(X,2).
mammal(horse).
arms(horse,0).
As far as I can tell, prolog cannot derive that a horse has four legs. Why so? You may ask. I'd say then, because there isn't any rule(s) for prolog to use in determining the legs. Inference rules can also not be used to determine that the fact that a horse is a mammal and it has 0 arms, it certainly must have 4 legs.
Answer:
Mitosis.
Explanation:
Mitosis is the process by which body cells divide. is the process by which body cells divide. The cells in multicellular organisms undergo mitosis repeatedly. The cells produced by mitosis are used for growth. They are also used to repair body tissues and replace worn-out cells. The image shows the input and output of mitosis. Notice that two cells are produced when one cell undergoes mitosis and cell division. Both cells produced are identical to the starting cell.
-Therefore, mitosis is the correct answer.
Answer:
The cells need water to maintain their metabolic functions, the way water enters through cells membranes is by osmosis.
Explanation:
The cell membrane is a lipidic bilayer composed of phospholipids and embedded proteins. Phospholipids have the characteristic of being amphiphilic which means that possess hydrophilic and lipophilic characteristics. The most common way is by osmosis, that is a mechanism that moves water from high concentration to less concentration of water. In the cell membrane, there are is channels of proteins called aquaporins that facilitate the pass of water through the membrane. Also, as water is a very small molecule without charge, this characteristic allows passing a limit amount of water molecules through the hydrophilic characteristic of membranes.
Answer:
There will be no movement of kinesin motor protein along the microtubules .
Explanation:
Microtubules is an important component of cytoskeleton which play an important role in maintaining cell shape,cell motility,cell division regulation etc.
Whereas kinesin belongs to the family of motor proteins present in the eukaryotic cell.Kinesin plays an important role axonal transport.
The hydrolysis of ATP generates energy to power up the movement of kinesin along the microtubules.
According to the given question if kinesin and microtubules were incubated with an non hydrolyzable ATP analog instead of ATP,then the movement of kinesin along the microtubules will not occur due to lack of energy because the non-hydrolyzable analog of ATP cannot undergo hydrolysis to release energy.
Answer:
The resistance allele is recessive
Explanation:
According to Darwin's pea experiment, the recessive trait appeared after a few generations.
Here in this case too the resistant individuals appeared after the first generation. This also implies that the offspring of first generation must be carrier of this recessive trait.
Let the susceptible domesticated strain trait be represented by "S"
and the recessive resistant wild strain trait be represented by "s"
Then,
F1 generation
SS * ss
Ss, Ss, Ss, Ss ------ All are heterozygous susceptible individuals
F2 generation
Ss * Ss
SS, Ss, Ss, ss
ss shows reappearance of resistant wild trait.
Hence, the resistance allele is recessive.
Answer:
Galactose
Explanation:
Galactose is a sugar with six carbons and one aldehyde group present at the end. The presence of a free aldehyde group in galactose makes it a reducing sugar. Galactose can reduce the Cu2+ of Benedict solution into Cu+ and produce a red precipitate. Sorbitol, β-ethylglucoside, and gluconate do not have aldehyde group to reduce Cu2+ ions and therefore, do not give the positive test with Benedict solution.
OA 3.125 x 108 atoms of calcium-41 and 4.375 x 10⁹ atoms of potassium-41
OB. 6.25 x 108 atoms of calcium-41 and 4.6875 x 10° atoms of potassium-41
OC. 6.25 x 108 atoms of calcium-41 and 4.375 x 109 atoms of potassium-41
OD. 3.125 x 108 atoms of calcium-41 and 4.6875 x 10° atoms of potassium-41
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The correct answer for this question will be option D.
Calcium-41 = 3.12× atoms
Potassium-41 = 4.69× atoms
As stated in the question,
Half life of isotope of Ca-14 which decays into K-14 = 1.03 × years
Therefore, after 1.03 × years (1 half life)
Ca-41 will be 50%
and, K-41 will be 50%
After 2.06 × years (2 half lives)
Ca-41 will be 25%
K-41 will be 75%
After 3.09 × years (3 half lives)
Ca-41 will be 12.5%
K-41 will be 87.5%
After 4.12 × years (4 half lives)
Ca-41 will be 6.25%
K-41 will be 93.75%
After 4.12 × years,
Ca-41 = 6.25/100 × 5×
= 3.12 × atoms
K-41 = 93.75/100 × 5×
= 4.69 × atoms
Therefore, option D is correct.
Learn more about half-lives here:
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