Write the following statement as Prolog clauses: Mammals have four legs and no arms, or two arms and two legs. A horse is a mammal. A horse has no arms. Can Prolog derive that a horse has four legs

Answers

Answer 1
Answer:

Answer:

Explanation:

mammal(X) :- legs(X,4), arms(X,0).

mammal(X) :- legs(X,2), arms(X,2).

mammal(horse).

arms(horse,0).

As far as I can tell, prolog cannot derive that a horse has four legs. Why so? You may ask. I'd say then, because there isn't any rule(s) for prolog to use in determining the legs. Inference rules can also not be used to determine that the fact that a horse is a mammal and it has 0 arms, it certainly must have 4 legs.


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During which stage of the cell cycle does cell division occur? o interphase o quiescence o cell growth 0 mitosis​

Answers

Answer:

Mitosis.

Explanation:

Mitosis is the process by which body cells divide. is the process by which body cells divide. The cells in multicellular organisms undergo mitosis repeatedly. The cells produced by mitosis are used for growth. They are also used to repair body tissues and replace worn-out cells. The image shows the input and output of mitosis. Notice that two cells are produced when one cell undergoes mitosis and cell division. Both cells produced are identical to the starting cell.

-Therefore, mitosis is the correct answer.

During interphase


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Why does water move through a membrane?

Answers

Answer:

The cells need water to maintain their metabolic functions, the way water enters through cells membranes is by osmosis.

Explanation:

The cell membrane is a lipidic bilayer composed of phospholipids and embedded proteins. Phospholipids have the characteristic of being amphiphilic which means that possess hydrophilic and lipophilic characteristics. The most common way is by osmosis, that is a mechanism that moves water from high concentration to less concentration of water.  In the cell membrane, there are is channels of proteins called aquaporins that facilitate the pass of water through the membrane. Also, as water is a very small molecule without charge, this characteristic allows passing a limit amount of water molecules through the hydrophilic characteristic of membranes.

"An experiment was performed to determine the role that ATP plays in kinesin movement along microtubules. Kinesin and microtubules were incubated together in a test tube, but instead of ATP, a non-hydrolyzable analog of ATP was added to the tube. What impact on kinesin function do you expect to observe in the presence of this ATP analog?"

Answers

Answer:

There will be no movement of kinesin motor protein along the microtubules .

Explanation:

Microtubules is an important component of cytoskeleton which play an important role in maintaining cell shape,cell motility,cell division regulation etc.

  Whereas kinesin belongs to the family of motor proteins present in the eukaryotic cell.Kinesin plays an important role axonal transport.

  The hydrolysis of ATP generates energy to power up the movement of kinesin along the microtubules.

 According to the given question if kinesin and microtubules were incubated with an non hydrolyzable ATP analog instead of ATP,then the movement of kinesin along the microtubules will not occur due to lack of energy because the non-hydrolyzable analog of ATP cannot undergo hydrolysis to release energy.

8. In an attempt to breed winter barley that is resistant to barley mild mosaic virus, agricultural researchers cross a susceptible domesticated strain with a resistant wild strain. The F1 plants are all susceptible, but when the F1 plants are crossed with each other, some of the F2 individuals are resistant. Is the resistance allele recessive or dominant? How do you know?

Answers

Answer:

The resistance allele is recessive

Explanation:

According to Darwin's pea experiment, the recessive trait appeared after a few generations.

Here in this case too the resistant individuals appeared after the first generation. This also implies that the offspring of first generation must be carrier of this recessive trait.

Let the susceptible domesticated strain  trait be represented by "S"

and the recessive resistant wild  strain trait be represented by "s"

Then,

F1 generation

SS * ss

Ss, Ss, Ss, Ss ------ All are heterozygous susceptible individuals

F2 generation

Ss * Ss

SS, Ss, Ss, ss

ss shows reappearance of resistant wild  trait.

Hence, the resistance allele is recessive.

Benedict’s solution is an alkaline copper sulfate solution which is used to detect the presence of aldehyde groups. In the presence of Benedict’s solution, the aldehyde group is oxidized and the aqueous blue Cu2+ ion is reduced to a red Cu2O precipitate. Sugars such as glucose, which produce the red precipitate when Benedict’s solution is added, are called reducing sugars because they can reduce Cu2+ to Cu+. Which of the following carbohydrates would give a positive reaction with Benedict’s reagent? a. galactose; b. sorbitol (see below); c. β-ethylglucoside; d. gluconate .

Answers

Answer:

Galactose

Explanation:

Galactose is a sugar with six carbons and one aldehyde group present at the end. The presence of a free aldehyde group in galactose makes it a reducing sugar. Galactose can reduce the Cu2+ of Benedict solution into Cu+ and produce a red precipitate.  Sorbitol, β-ethylglucoside, and gluconate do not have aldehyde group to reduce Cu2+ ions and therefore, do not give the positive test with Benedict solution.

The Isotope calcium-41 decays Into potassium-41, with a half-life of 1.03 x 105 years. There is a sample of calcium-41 containing 5 x 10⁹ atoms.How many atoms of calcium-41 and potassium-41 will there be after 4.12 x 105 years?
OA 3.125 x 108 atoms of calcium-41 and 4.375 x 10⁹ atoms of potassium-41
OB. 6.25 x 108 atoms of calcium-41 and 4.6875 x 10° atoms of potassium-41
OC. 6.25 x 108 atoms of calcium-41 and 4.375 x 109 atoms of potassium-41
OD. 3.125 x 108 atoms of calcium-41 and 4.6875 x 10° atoms of potassium-41
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Answers

The correct answer for this question will be option D.

Calcium-41 = 3.12×10^8 atoms

Potassium-41 = 4.69×10^9 atoms

As stated in the question,

Half life of isotope of Ca-14 which decays into K-14 = 1.03 × 10^5 years

Therefore, after 1.03 × 10^5 years (1 half life)

Ca-41 will be 50%

and, K-41 will be 50%

After 2.06 × 10^5 years (2 half lives)

Ca-41 will be 25%

K-41 will be 75%

After 3.09 × 10^5 years (3 half lives)

Ca-41 will be 12.5%

K-41 will be 87.5%

After 4.12 × 10^5 years (4 half lives)

Ca-41 will be 6.25%

K-41 will be 93.75%

After 4.12 × 10^5 years,

Ca-41 = 6.25/100 × 5×10^9

= 3.12 × 10^8 atoms

K-41 = 93.75/100 × 5×10^9

= 4.69 × 10^9 atoms

Therefore, option D is correct.

Learn more about half-lives here:

brainly.com/question/16387602

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