Answer:
x=-1 y=5
Step-by-step explanation:
A. 4x+y=1 multiply the equation negative 2
B. x+2y=9
-8x-2y=-2 add this to equation b
x+2y=9
-7x=7 divide both sides by -7
x=-1
now substitute x for -1 in either of the original equations
-4+y=1 add 4 to both sides
y=5
-4+5=1
-1+10=9
We will work on adding two fractions correctly with different denominators. The two denominators must be equated first.
In order to add these fractions, we need finding the common denominator by multiplying both denominators together.
Both denominators, 16 and 2, are multiplied by one another. What about numerators? Pay attention to the treatment of each fraction.
Let's take a break here to think.
Alternatively, develop a sharper method as below.
Note how this is performed. Absolutely indeed, cross-multiplication!
The numerator and denominator are divided by two to make it a simple fraction. After that, we simplify again into mixed fractions.
Gently let's take a break once more to think strategically.
Observing the steps above, we still find a large number when there is a direct multiplication of the two denominators. Are there more highly recommended steps? Of course there is!
The denominators 2 and 16 have LCM = 16. So, we convert the given fractions into equivalent fractions with denominator 16.
Do not forget simplifying again into mixed fractions.
Note:
In the form of fractions, the steps that must be considered are
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a. Al
b. Bi
c. Na
d. Fe
greater product.
1. 29 x 8 92x3
2. 54 x 17 45 x 71
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3. Determine whether or not AB is tangent to circle O. Show your work.
The line AB touching the circle at point B in the considered diagram is not tangent to the circle O.
If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:
where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).
There is a theorem in mathematics that:
If there is a circle O with tangent line L intersecting the circle at point A, then the radius OA is perpendicular to the line L.
So, if AB is a tangent, then ∠ABO = 90° and therefore satisfies Pythagoras theorem.
Assuming AB is tangent, then ABO is right angled we should get:
This statement is false, and therefore, so as our assumption is false that ABis tangent to circle O. Thus, AB is not tangent to circle O.
(so it might be that even if AB looks like touching at one point the circle O, but AB might be intersecting the circle at two points, or not touching it at all)
Thus, the line AB touching the circle at point B in the considered diagram is not tangent to the circle O.
Learn more about tangent to a circle here:
Answer:
not tangent
Step-by-step explanation:
two reasons, first
Triangle AOB is not a right triangle
line AB intersects the circle O at two points.
Answer Step-by-step explanation: ITS B