Evaluate −b2−2bx2−x when x=−2.
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An expression is defined as a set of numbers, variables, and mathematical operations. The value of −b²−2bx²−x when the value of x=-2 is −b²−8b + 4.
What is an Expression?
In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
The value of the expression −b²−2bx²−x will be,
−b² − 2bx² − x
= − b² − 2b(-2)² − (-2)
= − b² − 8b + 4
Hence, the value of −b²−2bx²−x when the value of x=-2 is −b²−8b + 4.
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Related Questions
Let A and B be non-empty, bounded subsets of R. (a) Why does sup(AUB) exist? (b) Prove that sup(AUB) = max{sup A, sup B}.
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Please solve needed asap
One number is 10 more than twice another. Their sum is 1. Find the numbers
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Answer:
Step-by-step explanation:
Remark
You could do it a very convoluted way or you could do it simply. The simple way, I think, is the one intended. The x on the second equation is sitting by it itself. So is it in the first equation. Put the x from the first equation into the second.
Solution
x=6y+3 ===> x+2y=5.
6y + 3 + 2y = 5 First Step
8y + 3 = 5 Subtract 3 from both sides
8y = 5 - 3 Combine
8y = 2 Divide by 8
y = 2/8
y = 1/4
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x = 6y + 3
x = 6*(1/4) + 3
x = 6/4 + 3
x = 1.5 + 3
x = 4.5
Solution (4.5 , 0.25)
Answer:
x= 9/2 y=1,4
Step-by-step explanation:
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Final answer:
To reduce the average cost per item to less than $500, it is necessary to produce more than 20 items according to the function C(x)=300x+6000.
Explanation:
The function C(x)=300x+6,000 represents the cost to produce x items. The average cost per item is given by C(x)/x. We need to find when this average cost is less than $500.
Setting up the inequality, we get C(x)/x < 500. Substituting the value of C(x) into the inequality, we get (300x + 6000)/x < 500. Simplifying this inequality, we end up with: x > 20.
Therefore, more than 20 items need to be produced for the average cost to be less than $500.
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Answer:
More than 30 items
Step-by-step explanation:
C(x)=300x+6,000
First, find c(x), the average cost function.
c(x)c(x)=C(x)x=300x+6,000x
The average cost function is shown below.
c(x)=300x+6,000x
We want the function c(x) to be less than 500.
c(x)<500
Substitute the rational expression for c(x).
300x+6,000x<500x≠0
Subtract 500 to get 0 on the right.
300x+,6000x−500<0
Find the LCD, and rewrite the left side as one quotient.
300x+6,000x−500xx−200x+6,000x<0<0
Factor the numerator to show all factors.
−200(x−30)x<0
Find the critical points when the numerator or denominator are equal to 0.
−200(x−30)−200≠0x−30x=0x=0=0=30
More than 30 items must be produced to keep the average cost below $500 per item.
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Answer:
-36
Step-by-step explanation:
80 + (-36) = 44
The negative in the 36 allows it to be subtracted from 80
Answer:
80 + -36
Step-by-step explanation:
80 - 44 = 36
80 + -36 = 44
Factor the polynomial completely
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Answer:
(y-9)(2y^2 +9)
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i thing the answer is D the last chart