The Graduate Management Admission Test (GMAT) is taken by individuals interested in pursuing graduate management education. GMAT scores are used as part of the admissions process for more than 6100 graduate management programs worldwide. The mean sore for all test‑takers is 550 with a standard deviation of 120. A researcher in the Philippines is concerned about the performance of undergraduates in the Philippines on the GMAT. She believes that the mean scores for this year's college seniors in the Philippines who are interested in pursuing graduate management education will be less than 550. She has a random sample of 250 college seniors in the Philippines interested in pursuing graduate management education who plan to take the GMAT. Suppose we know that GMAT scores are Normally distributed with standard deviation σ=120. The null and alternative hypotheses are H0:µ=550 versus Ha:µ<550.Required:
State the null and alternative hypotheses for the study of the performance on the GMAT of college seniors in the Philippines.
Answers
Answer:
H₀:μ = 550 vs. Hₐ:μ < 550.
Step-by-step explanation:
A researcher believes that the mean scores for this year's college seniors in the Philippines who are interested in pursuing graduate management education will be less than 550.
The mean sore for all test‑takers is μ = 550 with a standard deviation of σ = 120.
A random sample of n = 250 college seniors in the Philippines interested in pursuing graduate management education who plan to take the GMAT were selected.
The null and alternative hypotheses for the study of the performance on the GMAT of college seniors in the Philippines is as follows:
H₀: The mean scores for this year's college seniors in the Philippines who are interested in pursuing graduate management education will not be less than 550, i.e. μ = 550.
Hₐ: The mean scores for this year's college seniors in the Philippines who are interested in pursuing graduate management education will be less than 550, i.e. μ < 550.
Related Questions
A study is being conducted to compare the average training time for two groups of airport security personnel: those who work for the federal government and those employed by private security companies. From a random sample of 12 government-employed security personnel, average training time was 72 hours, with a sample standard deviation of 8 hours. In a random sample of 16 privately employed security personnel, training time was 65.4 hours, with a sample standard deviation of 12.3 hours. Assume that training time for each group is normally distributed. Use the following notations:μ1: The mean training time for the population of airport security personnelemployed by the federal government.μ2: The mean training time for the population of airport security personnelemployed by private security companies.The goal of the statistical analysis is to determine whether the sample data support the hypothesis that average training time for government-employed security personnel is higher than those employed by private security companies.1. What is the null hypothesis H0?Select one:a. μ1- μ2 <= 0b. μ1- μ2 < 0c. μ1- μ2 =/ 0d. μ1- μ2 > 02. What is the alternative hypothesis Ha?Select one:a. μ1- μ2 > 0b. μ1- μ2 <= 0c. μ1- μ2 = 0d. μ1- μ2 >= 0
Graph the line 3x + 6y =12.
Which of the following statements is true for ∠a and ∠b in the diagram?
What is a linear function?
Answers
Answer:
The correct answer is A. The probability of randomly selecting a daisy from Bouquet S is less than the probability of randomly selecting a daisy from bouquet T.
Step-by-step explanation:
We are told that Bouquet S contains 30 flowers and 13 of those flowers are daisies. Therefore, the probability of selecting a daisy from Bouquet S can be modeled by:
13/30, which is greater than 1/3 but less than 1/2
We are also told that Bouquet T contains 13 flowers and 13 daises. From this information, we can conclude that all of the flowers in Bouquet T are daises, or the probability can be modeled by:
13/13 = 1
Therefore, because the probability of selecting a daisy from Bouquet S is 13/30 and the probability of selecting a daisy from Bouquet T is 1, we can conclude that, as option A states, the probability of selecting a daisy from Bouquet S is less than the probability of selecting a daisy from Bouquet T.
Hope this helps!
Answer:
I believe the answer is A.
Step-by-step explanation:
If there are 13 daises per bouquet, that means one bouquet is all daises. The other bouquet has 30 flowers. 30-13 is 17 which means there are 17 other flowers rather than daises. 17 is greater than 13 by 4 which is not that much. Therefore I think the answer is letter A.
-2x-3=8
-2x+4y=22
Answer (-7,2)
Answers
Answers
Answer:
n= 21
Step-by-step explanation:
The equation is simple, you just have to reason the sentence, the quotient of a number, this means that the result of the division is 3.5, and the number has to be divided by 6, so the equation would end up looiking like this:
As 6 is dividing and you want to clear N, you just put it on the other side of the equation multiplying, and you end up with this:
n=6(3.5)
n=21
So your answer for this equation would be n= 6.
Multiply both sides by 6.
n = 21
Answers
Answer:
1. 15 to 21 = 21 - 15 / 15 = 0.4*100% = 40%
2. 12 teachers to 48 teachers = 48 - 12/48 = 0.75 * 100% = 75%
3. 80 pencil to 120 pencil = 120 - 80 / 80 = 0.5*100% = 50%
4. 40 cans to 70 cans = 70 - 40 / 70 = 0.43 * 100% = 43%
25/4
as a percentage?
Answers
Answer:
625%
Step-by-step explanation:
Convert fraction (ratio) 25 / 4 Answer: 625%
Answer:
Google says 625% and 6.25 as a decimal
A. 1223 + 1
B. 6432 + 1
C. 6413 + 48y2 + 16y + 3
D. 6413 + 4812 + 12y + 1