The image (A'B'C'D') of ABCD , in Option C cannot be produced using only reflection.
Image is the copy of a figure made along the axis.
The figure attached as two figures , object and image ,the image has some transformation done to it
Figure 1 , option 1 :
In the figure
Object Coordinates :
ABCD : ( -6 ,4) , (-6,6) , (-2,6) , (-4,4)
A'B'C'D' : ( 6,-4) , (6,-6) , (2,-6) , (4,-4)
Figure 2 :
Object Coordinates :
ABCD : ( -6 ,4) , (-6,6) , (-2,6) , (-4,4)
A'B'C'D' : ( 4 , -6) , (6,-6) , (6,-2 ) , (4,-4)
Figure 3
Object Coordinates :
ABCD : ( -6 ,4) , (-6,6) , (-2,6) , (-4,4)
A'B'C'D' : ( 6 , -6) , (6,-4) , (2,-4 ) , (4,-6)
Figure 4
Object Coordinates :
ABCD : ( -6 ,4) , (-6,6) , (-2,6) , (-4,4)
A'B'C'D' : (4 , 6) , (6,6) , (2,6 ) , (4,4)
As all the image formed is just by reflection except of Option C , Figure 3.
Therefore Option C is the answer.
To know more about Image
#SPJ1
B. The soaring bird quickly disappeared from our sight.
C. The woods went up in flame.
D. I think that I shall never see a poem lovely as a tree.
Answer:
D. I think that I shall never see a poem lovely as a tree.
Step-by-step explanation:
A simile is an explicit comparison of people or things with the help of special comparison words (like, as, resembles, than).
As we see, only the last statement contains this special word (as), so D would be the correct choice.
Area of rectangle having length 11 cm and breadth 11/2 cm is 121/2 cm² .
Given, that length of rectangle is double that of its width.
Area of rectangle = l × b
l = Length of rectangle .
b = Breadth of rectangle .
As length of rectangle is double of width.
Width = 11/2 cm
Length = 2 × (11/2) cm
Length = 11 cm
Substitute the values in the area formula,
Area of rectangle = l × b
Area of rectangle =
Area of rectangle =
Therefore the area of rectangle is .
Know more about rectangle,
#SPJ5
6 / 15 = 2 / x
6x = 30
x = 30 / 6 = 5