Pls help me with this i will give crown
jacleldridge25 avatar

Answers

Answer 1
Answer:

Answer:

C

Step-by-step explanation:

The easiest way to solve this would be to find the difference between the numbers. We can do -3-(-9) to find the difference of 6. We can then make sure this is true for the rest of the sequence by adding 6 to each number.

-9+6=-3

-3+6=3

3+6=9

9+6=15

Now that we've verified that this is true, we know the answer is C

Answer 2
Answer:

Answer:

u on go to padlet now

Step-by-step explanation:


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Which Property of Equality should be used first to solve the equation p/7 - 5 = -3 for pAddition Property of Equality Subtraction Property of Equality Multiplication Property of Equality Division Property of Equality 
4.75 yards at$5.37 a yard
Simply the equation and show your work
Please help with this, and please show me the steps to getting the answers
−1 1/2−(+3 1/2)−(−5/8)

SOMEONE PLEASE HELP ;-;

Answers

Answer:

864 rhinestones

Step-by-step explanation:

There are 36 rhinestones in the design. If this repeats 24 times, multiply the amount of rhinestones times how many times it repeats.

36(24)=864

If an 8 pound bag of rice cost $9.60 , what is the cost of 1 pound of rice ?

Answers

the answer is $1.20
to get this you divide 9.60 by 8

What is the perimeter of a rectangle 33 sq m by 3 m

Answers

The answer is 72 because the permeter is 33 by 3 so you multiply 33 and 3 by 2 and add them up
66+6=72

Find the greatest common factor 15x^2 y^3, and -20x^3 yz.

Answers

Answer:

5x^2y

Step-by-step explanation:

We are given that  two terms are

15x^2y^3, -20x^3yz

We have to find the GCF of given terms

15x^2=3* 5* y* y* y* x* x

-20x^3yz=-2* 2* 5* x* x* x* y* z

GFC=5* x* x* y

GCF=5x^2y

Answer:5x^2y

15x^2y^3=3*5*x*x*y*y*y
-20x^3yz=-1*2*2*5*x*x*x*y*z
comon numbers are
5,x,x,y

greatest common factor is 5x^2y

I am a quadrangleI have 2 pairs of parallel sidesall of my angles are right anglesI am not a square

Answers


In that case, it must follow as the night follows the day
that you are none other than a rectangle !

There are 20 counters in a box . A counter is chosen and replaced 100 times , The results are 32 blue and 62 red . How many of each colour do you think there are in the box , can someone help me out on this please ? I'm very confused

Answers

The numbers in the question are wrong.  It says you pulled something
out of the box and put it back in the box 100 times.  The total of
everything you pulled out should be 100, but it says you got
(32 + 62) = 94 things. 

I'm going to change the numbers slightly, so you'll see how to do it.
We're going to say that you get blue ones  33  times, and you get
red ones  67 times.   That's better, because  (33 + 67) = 100 .


When you do the experiment, the things in the box are shaken and
completely mixed up, and when you reach in to pick one, you always
keep your eyes closed so you don't see what you're getting.  The
choice is always "random".  That means what you get is determined
completely by chance, not by anything you do.

Then the result of your experiment is:

-- A blue thing comes out  33  times in  100 draws.
   That's  33%  of the time.

-- A red thing comes out  67  times in  100 draws.
   That's  67%  of the time.

If the choice is really random chance every time, then the only thing
that can influence what you get is how many of each thing is in the box. 
Whatever there are more of, you'd expect to get more often.  Whatever
there's less of, you'd expect to get less often.

-- You pulled things out of the box 100 times.
-- You got blue things 33% of the times.
-- You got red things 67% of the times.
-- Now, you take an educated guess, and you tell everyone: 

         "I estimate that roughly 33% of the things in the box are blue,
          and roughly 67% of the things in the box are red."

Then you ask:   "How many things are in the box all together ?"

There are 20 things in the box all together, Makookoo.

"Well OK then.  33% of 20 things is  6-2/3 things.  But all the things
in the box are whole things. There aren't any pieces of things.  So I'll round my estimate to the nearest whole thing.  6-2/3 rounds to 7 . . .  Roughly 7 of the things in the box are blue.

And furthermore . . .

"67% of 20 things is 13.4 things.  But all the things in the box are
whole things. There aren't any pieces of things.  So I'll round my
estimate to the nearest whole thing.  13.4 rounds to 13 . . .  Roughly
13 of the things in the box are red."

I was confused too. I'd say 60 red and 40 blue because I multiplied 62*2 and 32*2

I got 124 and 64.

Then, I subtracted 124 and 64 to get 60 for red and added 40 to get 100

so... red is 60 and blue is 40.

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