MATHEMATICS HIGH SCHOOL

Which inequality is true?O A. > 1
O B. 51> 15
O C. 41-2<10
O D. 17+ 9 < 12

Answers

Answer 1
Answer:

Answer:

B

Step-by-step explanation:

51 is larger than 15.

Hope this helps.
Answer 2
Answer:

Answer:

bobux

Step-by-step explanation:

yes because are

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one angle of a triangle is three times as large as another. the measure of the third angle is 40 degrees more than that of the smallest angle. find the measure of each angle

Answers

Hello,

Let x the second angle
the first is 3x
the third 40°

3x+x+40=180
==>4x=140
==>x=35°
3x=3*35=105°

The curve ax squared - 4x+1 has a stationary point where x equals -3find the value of a and determine the nature of the stationary point

Answers

f(x)=ax^2-4x+1\nf'(x)=2ax-4\n0=2a\cdot(-3)-4\n6a=-4\na=-(4)/(6)=-(2)/(3)

It's the quadratic equation where a<0 so the stationary point is a maximum.

The roots of an equation are x = -1 ± i. The equation is x2 + + 2 = 0.

Answers

im pretty sure its x=-1

A car travels 32 km due north andthen 46 km in a direction 40° west of
north. Find the magnitude of the
car's resultant vector.

Answers

Answer:

73.2km

Step-by-step explanation:

first you have to decompose 46 km into y and x components.

x=sin40°*46km

x=0.64*46km

x=29.44km

y=cos40°*46km

y=0.76*46km

y=34.96

now you add the y components together

32+34.96=66.98

finally use Pythagorean thereom to find the resultant vector.

a*a+ b*b=c*c

66.98*66.98+29.44*29.44=c*c

c*c= 4486.3+866.7

c=√5353

c=73.2 km this is the approximate value

Write the first three terms of the series for which tn = 2(n+3). Find the number of terms of the series required to make the sum 228.

Answers

Answer:

The first three terms of the series are 8, 10 and 12. The number of terms is 12 to make the sum 228.

Step-by-step explanation:

The series is defined as

t_n=2(n+3)

Put n=1.

t_1=2(1+3)=2* 4=8

Put n=2.

t_2=2(2+3)=2* 5=10

Put n=3.

t_3=2(3+3)=2* 6=12

The first three terms of the series are 8, 10 and 12.

It is an arithmetic series. The first terms is 8 and the common difference is

d=a_2-a_1=10-8=2

The sum of n terms of an arithmetic series is

S_n=(n)/(2)[2a+(n-1)d]

288=(n)/(2)[2(8)+(n-1)2]

288=(2n)/(2)[8+n-1]

288=n[n+7]

0=n^2+7n-288

0=n^2+19n-12n-288

0=n(n+19)-12(n+19)

0=(n+19)(n-12)

Equate each factor equal to zero.

n=-19,12

The number of terms can not be negative, therefore the value of n must be 12.

Write the expression for the phase 7 inches shorter than Sue

Answers

Answer:I'm pretty sure its -7

Step-by-step explanation:
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