The angle of elevation must be 68.202 degrees
Solution:
Given that, 14 foot ladder is used to scale a 13 foot wall
We have to find the angle of elevation must the ladder be situated in order to reach the top of the wall
The figure for this solution is attached below
The ladder, wall and the ground forms a right angled triangle
ABC is a right angled triangle
AB is the height of wall = 13 feet
AC is the length of ladder = 14 feet
We have to find the angle of elevation
Let the angle of elevation be "x"
For right angled triangle ABC, We can use the definition for sine
Here, in figure, opposite = AB and hypotenuse = AC
Thus the angle of elevation must be 68.202 degrees
The angle of elevation the ladder will be situated in order to reach the top of the wall is 68°.
A right triangle has one of its angles as 90 degrees. The angle of elevation can be found using trigonometric ratios.
Therefore, the angle of elevation can be calculated as follows;
The length of the ladder is the hypotenuse.
The opposite side is the height of the wall.
Therefore,
sin ∅ = opposite / hypotenuse
sin ∅ = 13 / 14
∅ = sin⁻¹ 0.92857142857
∅ = 68.2129901712
∅ = 68°
learn more on right triangle here: brainly.com/question/22479729
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A. Each sector of a circle graph shows a category and the relative size of the category .
B. A circle graph can only be used for categories where the data adds up to 360.
C. Each sector of a circle graph that is the same size must be the same color .
D. The percents in each circle graph add up to 360 .
The number should be 65.
Given that,
Based on the above information,
Therefore we can conclude that the number should be 65.
Learn more: brainly.com/question/17429689
Answer:
The Answer is: There are 5 large boxes and 8 small boxes. (The graphical plot will need to be solved using the software).
Step-by-step explanation:
Let xx = small boxes and yy = large boxes:
xx + yy = 13
xx = 13 - yy
The number of small boxes times 20, plus the number of large boxes times 40 is equal to 360:
20xx + 40yy = 360
Substitute the algebraic value of xx, so we only have one variable to consider and solve for yy:
20(13 - yy) + 40yy = 360
260 - 20yy + 40yy = 360
260 + 20yy = 360
20yy = 100
yy = 100 / 20 = 5 large boxes.
Solve for xx:
xx = 13 - yy
xx = 13 - 5 = 8 small boxes.
There are 5 large boxes and 8 small boxes. (The graphical plot will need to be solved using the software).
Proof:
20xx + 40yy = 360
20(8) + 40(5) = 360
160 + 200 = 360
360 = 360
To solve the problem graphically, set up a system of equations: x + y = 13 and 20x + 40y = 360. Graph the equations to find the intersection point which represents the solution.
To solve this problem graphically, we can set up a system of equations based on the given information. Let's denote the number of small boxes as x and the number of large boxes as y. From the given information, we can write the following equations:
x + y = 13 (equation 1, representing the total number of boxes)
20x + 40y = 360 (equation 2, representing the total number of books)
To graph these equations, we can plot them on a coordinate plane, where the x-axis represents the number of small boxes (x) and the y-axis represents the number of large boxes (y). The intersection point of these two lines will represent the solution to the system of equations, giving us the values of x and y (the number of small and large boxes sent, respectively).
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Answer:7
Step-by-step explanation:
7,because 30-1/2=7
Half of 30 students would be 15 (30 / 2 = 15)
One third of 15 is 5 (15 / 3 = 5)
15 students have cellphones, 5 of them are allowed to use social media.