`. Select all the pairs of equivalent expressions.a. (43)3 and 43 ⋅ 43
b. (34)4 and 38 ⋅ 38
c. 64 ⋅ 34 and 188
d. 43 ⋅ 53 and 203
e. (43)3 and 43 ⋅ 43 ⋅ 43

2. Choose an equivalent expression for 123 • 129 • 124 • 122.
a. 12^4
b. 12^18
c. 12^35
d. 12^216

3. Choose an equivalent expression for 106 ÷ 104.
a. 10^2
b. 10^3
c. 10^10
d. 10^24

4. Select all the expressions that are equivalent to 78 • 7.
a. 73 • 73
b. 7^18/7^9
c. (73)3
d. 74 + 75
e. 74 • 75

5. Is this equation correct?

63 ⋅ 73 = 423

A. Yes; 63 • 73 is equal to (6 • 7)3 or 423.

B. Yes; 63 • 73 is equal to (6 • 7 • 3) or (42 • 3).

C. No; 63 • 73 is equal to (6 • 7 • 3) or (42 • 3).

D. No; 63 • 73 is equal to (6 • 7)3 + 3 or 426.

Answers

Answer 1
Answer:

This question was not properly written

Complete Question

Select all the pairs of equivalent expressions.

a. (4³)³ and 4³ ⋅ 4³

b. (3⁴)⁴ and 3⁸ ⋅ 3⁸

c. 6⁴ ⋅ 3⁴ and 18⁸

d. 4³ ⋅ 5³and 20³

e. (4³)³ and 4³ ⋅ 4³ ⋅ 4³

2. Choose an equivalent expression for 12³ • 12⁹• 12⁴ • 12².

a. 12^4

b. 12^18

c. 12^35

d. 12^216

3. Choose an equivalent expression for 10⁶ ÷ 10⁴.

a. 10^2

b. 10^3

c. 10^10

d. 10^24

4. Select all the expressions that are equivalent to 7⁸ • 7.

a. 7³• 7³

b. 7^18/7^9

c. (7³)³

d. 7⁴ + 7⁵

e. 7⁴ • 7⁵

5. Is this equation correct?

6³⋅ 7³= 42³

A. Yes; 6³• 7³ is equal to (6 • 7)³ or 42³.

B. Yes; 6³ • 7³is equal to (6 • 7 • 3) or (42 • 3).

C. No; 6³ • 7³ is equal to (6 • 7 • 3) or (42 • 3).

D. No; 6³ • 7³ is equal to (6 • 7)³+ 3 or 42⁶.

Answer:

1 The correct answer is

d. 4³ ⋅ 5³ and 20³

e. (4³)³ and 4³ ⋅ 4³ ⋅ 4³

2b. 12^18

3 a = 10²

4a. 7³ • 7³

c. (7³)³

e. 7⁴ • 7⁵

5 A. Yes; 6³• 7³ is equal to (6 • 7)³ or 42³.

Step-by-step explanation:

1) Select all the pairs of equivalent expressions.

These are the correct options

d. 4³ ⋅ 5³and 20³

4³ × 5³ = 8000

20³ = 8000

e. (43)3 and 43 ⋅ 43 ⋅ 43

2. Choose an equivalent expression for 12³ • 12⁹• 12⁴• 12².

For an Algebraic Expressions,

We have the rule

x^a × x^b = x ^a+ b

Hence: 12³ • 12⁹• 12⁴ • 12².

= 12^3+9+4+2 = 12^18

Hence, b. 12^18

3. Choose an equivalent expression for

10⁶ ÷ 10⁴.

For an Algebraic expressions

x^a ÷ x^b = x ^a - b

Therefore

10⁶÷ 10⁴ = 10²

a. 10^2 Is the correct option

4. Select all the expressions that are equivalent to 7⁸ • 7.

7⁸ . 7= 7^8+1

= 7^9 or 7⁹

The equivalent expressions are:

a. 7³ • 7³ = 7⁹

b. 7^18/7^9 = 7⁹

c. (7³)³ = 7⁹

e. 7⁴ • 7⁵ = 7⁹

5. Is this equation correct?

6³ ⋅ 7³ = 42³

A. Yes; 6³• 7³ is equal to (6 • 7)³ or 42³

Answer 2
Answer:

1. There are equivalent expressions in options (a) and (e).(43)3 and 43 ⋅ 43,  (43)3 and 43 ⋅ 43 ⋅ 43

2. The equivalent expression for 123 • 129 • 124 • 122 is 12^18. Option b

3. The equivalent expression for 106 ÷ 104 is 10^2.Option a

4. Equivalent expressions in options (a) and (c) represent 78 • 7.

5. The equation 63 ⋅ 73 = 423 is not correct; the correct result is 63 • 73 = 1369.Option C

1. Pairs of Equivalent Expressions:

a. (43)3 and 43 ⋅ 43: These are equivalent expressions because (43)3 means 43 raised to the power of 3, which is the same as 43 multiplied by itself 3 times.

e. (43)3 and 43 ⋅ 43 ⋅ 43: These are equivalent expressions because (43)3 means 43 raised to the power of 3, which is the same as 43 multiplied by itself 3 times.

2. Equivalent Expression for 123 • 129 • 124 • 122:

b. 12^18: This expression represents the product of 12 raised to the power of 18, which is equivalent to multiplying the given numbers.

3. Equivalent Expression for 106 ÷ 104:

a. 10^2: This expression represents 10 raised to the power of 2, which is equivalent to the given division.

4. Expressions Equivalent to 78 • 7:

a. 73 • 73: This expression represents the square of 7^3, which is equivalent to 78 • 7.

c. (73)3: This expression represents 7^3 raised to the power of 3, which is equivalent to 78 • 7.

5. Is the Equation Correct?

C. No; 63 • 73 is equal to (6 • 7 • 3) or (42 • 3). The equation 63 ⋅ 73 = 423 is not correct; the correct result is 63 • 73 = 1369. The provided equation does not accurately represent the multiplication of 63 and 73.

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Skye's two new aquariums each hold exactly 200 gallons of water. One aquarium will hold small fish and the other will hold large fish. Now hew needs new fish for his aquariums. She will buy 5 small fish for every 10 gallons of water in the aquarium. She will buy 8 large fish for every 40 gallons of water in the aquarium. What is the total number of fish Skye will have?

Answers

Answer=140 fish

200 gallons of water in the first aquarium.

200 gallons of water in the second aquarium.

The first will be for the small fishes.

   5 small fish            x fish
_____________=__________
     10 gallons        200 gallons

cross multiply
10x=1000
divide both sides by 10
x=100 small fish

The first aquarium has 100 small fish.

The second aquarium holds large fish.

   8 large fish            x fish
____________=___________
    40 gallons        200 gallons

cross multiply
40x=1600
divide both sides by 40
x=40 large fish

The second aquarium has 40 large fish.

100small fish+40 large fish=140 total fish
In terms of the first aquarium, the number of small fish Skye will have is:
200 gallons of water* (5 small fish/ 10 gallons of water)= 100 small fish.

In terms of the second aquarium, the number of large fish Skye will have is:
200 gallons of water* (8 large fish/ 40 gallons of water)= 40 large fish.

The total number of fish Skye will have is:
100 fish+ 40 fish= 140 fish.

Final answer: 140 fish.

Hope this would help~

If Leah is 6 years older than her sister,Sue, and John is 5 years older than Leah, and the total of their ages is 41. Then how old is Sue?

Answers

Let us assume the age of Sue = x years
Then
Age of Leah = x + 6
Age of John = 5 + (x + 6)
                    = x + 11
Total of their ages = 41
So
x + x + 6 + x + 11 = 41
3x + 17 = 41
3x = 41 - 17
3x = 24
x = 24/3
   = 8 years
So Sue is 8 years old.
She is 30 years old.

What is the simplified form of x minus 5 over x squared minus 3x minus 10 ⋅ x plus 4 over x squared plus x minus 12? (6 points)

Answers

Answer: Our simplified form will be

(1)/((x+2)(x-3))

Step-by-step explanation:

Since we have given that

(x-5)/(x^2-3x-10)* (x+4)/(x^2+x-12)

So, first we split the middle term of the denominator ,

x^2-3x-10=0\n\n=x^2-5x+2x-10\n\n=x(x-5)+2(x-5)\n\n=(x-5)(x+2)

Similarly,

x^2+x-12=0\n\nx^2+4x-3x-12=0\n\nx(x+4)-3(x+4)=0\n\n(x+4)(x-3)=0

Now, we put in our expression above:

(x-5)/((x-5)(x+2))* (x+4)/((x-3)(x+4))\n\n=(1)/(x+2)* (1)/(x-3)\n\n=(1)/((x+2)(x-3))

Hence, our simplified form will be

(1)/((x+2)(x-3))

Step 1 is to factor everything! 

After factoring you will get:

x-5 over (x+2)(x+5) times x+4 over (x-3)(x+4)

Step 2 is to remove the duplicate factors!
Remove x+4 and x+5

x-5 over (x+2)(x-5) times 1 over x-3 = 1 over x+2 times 1 over x-3 

Step 3 is to multiply the numerators and the denominators.

End result is 1 over (x+2)(x-3)




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Answers

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Answers

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True or false

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Answers

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answer is TRUE
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