What is addition property of equality

Answers

Answer 1

Answer: In an equation, the additive property of equality states that if we add or subtract the same number to both sides of an equation, the sides remain equal

Answer 2

Answer:

Answer:

Additive property of equality states that if we add or subtract the same number to both sides of an equation, the sides remain equal.

Related Questions

Please answer correctly !!!!!!!! Will mark brainliest !!!!!!!!!!!!!!
Which are natural numbers, integers, rational numbers, irrational numbers and real numbers?0, 1, 1/12, 1/16, 1/20
Chang 0.83 into a fraction
The diameter of a circle has endpoints whose coordinates are R(-2, 2) and S(4, 2). what is the length of the radius?
Kendra hasn’t missed a day of school in 245 days. This is twenty days less than five times the number of days it has been since Brandon has missed a day of school. How many days has it been since Brandon missed a day of school?

What number would complete the pattern below? 16 4 12 36 9 27 44 11 __

Answers

The answer to this question is 33. Within the sequence are pairs of numbers, and each pair is separated by the resultant figure when they are subtracted from one another. So, 16 - 12 = 4 36 - 27 = 9, and 44 - 33 = 11. Hope that solves the question for you!

Please , I didn't have time to study. god bless to all <3Feel free to show you show work. God bless

Answers

This is the first half of the question.
Let's solve your equation step-by-step.5x=9x3+2x2−5x+4Step 1: Subtract 9x^3+2x^2-5x+4 from both sides.5x−(9x3+2x2−5x+4)=9x3+2x2−5x+4−(9x3+2x2−5x+4)−9x3−2x2+10x−4=0Step 2: Use cubic formula.x=−1.31953Answer:x=−1.31953

URGENT! PLEASE HELP!if the train from milan, italy to rome, italy takes 6 hours at a speed of 130 mph, how many miles from milan is rome?

Answers

Answer:

780 miles :)

Step-by-step explanation:

Alright, so in one hour, the train goes 130 miles, right?

So, in 6 hours, the train would simply go 130 * 6 = 780 miles! :)

Sketch the angle in standard position -95

Answers

Sketching the angle at standard position starts at Quadrant I. Imagine a cartesian plane, Quadrant I is located where x and y values are positive.

So the angle 0 is at the positive y-axis position; 90 degrees is at positive x-axis.
Sketching positive angles starts from positive y-axis counterclockwise.
Sketching negative angles stars from positive y-axis clockwise.

The question asked for the -95 degrees, the it is located at Quadrant III.

Which of the following is an arithmetic sequence?A. -4,-2, 0, 2, ...
B. -8, -4,-2, -1, ...
C.-4, -3, -1, 2, ...
D. -4, 0, -4, 0, ...

Answers

is equal to zero if. a) a, b, c are in arithmetic progression ... progression. d) α is a root of the equation ax2 + bx + c = 0.Missing: 4,

Answer: Choice A) -4, -2, 0, 2

Explanation:

This is because we are adding the same thing to each term to get the next term. That is the common difference d = 2

second term = (first term)+d = -4+2 = -2
third term = (second term)+d = -2+2 = 0
fourth term = (third term)+d = 0+2 = 2

Solve the system of equations using cramer's rule -x+y-3z=-4 3x-2y+8z=14 2x-2y+5z=7

Answers

System of Equations
$-1x + 1y - 3z = -4 \n3x - 2y + 8z = 14 \n2x - 2y + 5z = 7$

Coefficient Matrix's Determinant
$D = \left[\begin{array}{ccc}-1&1&-3\n3&-2&8\n2&-2&5\end{array}\right]$

Answer Column
$\left[\begin{array}{ccc}-4\n14\n7\end{array}\right]$

Dx: Coefficient Determinant with Answer-Column values in X-Column
$D_(x) = \left[\begin{array}{ccc}-4&1&-3\n14&-2&8\n7&-2&5\end{array}\right]$

Dy: Coefficient Determinant with Answer-Column Values in Y-Column
$D_(y) = \left[\begin{array}{ccc}-1&-4&-3\n3&14&8\n2&7&5\end{array}\right]$

Dz: Coefficient Determinant with Answer-Column Values in Z-Column
$D_(z) = \left[\begin{array}{ccc}-1&1&-4\n3&-2&14\n2&-2&7\end{array}\right]$

Evaluating each Determinant
$D= \left[\begin{array}{ccc}-1&1&-3\n3&-2&8\n2&-2&5\end{array}\right] \nD = (-1 * (-2) * 5) + (1 * 8 * 2) + (-3 * 3 * (-2)) - (2 * (-2) * (-3)) - (-2 * 8 * (-1)) - (5 * 3 * 1) \nD = (10) + (16) + (18) - (12) - (16) - (15) \nD = 10 + 16 + 18 - 12 - 16 - 15 \nD = 26 + 18 - 12 - 16 - 15 \nD = 44 - 12 - 16 - 15 \nD = 32 - 16 - 15 \nD = 16 - 15 \nD = 1$

$D_(x) = \left[\begin{array}{ccc}-4&1&-3\n14&-2&8\n7&-2&5\end{array}\right] \nD_(x) = (-4 * (-2) * 5) + (1 * 8 * 7) + (-3 * 14 * (-2)) - (7 * (-2) * (-3)) - (-2 * 8 * (-4)) - (5 * 14 * 1)) \nD_(x) = (40) + (56) + (84) - (42) - (64) - (70) \nD_(x) = 40 + 56 + 84 - 42 - 64 - 70 \nD_(x) = 96 + 84 - 42 - 64 - 70 \nD_(x) = 180 - 42 - 64 - 70 \nD_(x) = 138 - 64 - 70 \nD_(x) = 74 - 70 \nD_(x) = 4$

$D_(y) = \left[\begin{array}{ccc}-1&-4&-3\n3&14&8\n2&7&5\end{array}\right] \nD_(y) = (-1 * 14 * 5) + (-4 * 8 * 2) + (-3 * 3 * 7) - (2 * 14 * (-3)) - (7 * 8 * (-1)) * (5 * 3 * (-4)) \nD_(y) = (-70)+ (-64) + (-63) - (-84) - (-56) - (-60) \nD_(y) = -70 - 64 - 63 + 84 + 56 + 60 \nD_(y) = -134 - 63 + 84 + 56 + 60 \nD_(y) = -197 + 84 + 56 + 60 \nD_(y) = -113 + 56 + 60 \nD_(y) = -57 + 60 \nD_(y) = 3$

$D_(z) = \left[\begin{array}{ccc}-1&1&-4\n3&-2&14\n2&-2&7\end{array}\right] \nD_(z) = (-1 * (-2) * 7) + (1 * 14 * 2) + (-4 * 3 * (-2)) - (2 * (-2) * (-4)) - (-2 * 14 * (-1)) - (7 * 3 * 1) \nD_(z) = (14) + (28) + (24) - (16) - (28) - (21) \nD_(z) = 14 + 28 + 24 - 16 - 28 - 24 \nD_(z) = 42 + 24 - 16 - 28 - 21 \nD_(z) = 66 - 16 - 28 - 21 \nD_(z) = 50 - 28 - 21 \nD_(z) = 22 - 21 \nD_(z) = 1$

$x = (D_(x))/(D) = (4)/(1) = 4 \ny = (D_(y))/(D) = (3)/(1) = 3 \nz = (D_(x))/(D) = (1)/(1) = 1 \n(x, y, z) = (4, 3, 1)$

Other Questions

Point G is located at (3, −1) and point H is located at (−2, 3). Find y value for the point that is 2 over 3 the distance from point G to point H.

What is pie the equivalent to?

Write (5+2yi)(4-3i)-(5-2yi)(4-3i) on a+bi form, where y is a real number

Grandma Gertrude's Chocolates, a family owned business, has an opportunity to supply its product for distribution through a large coffee house chain. However, the coffee house chain has certain specifications regarding cacao content as it wishes to advertise the health benefits (antioxidants) of the chocolate products it sells. In order to determine the mean percentage of cacao in its dark chocolate products, quality inspectors sample 36 pieces. They find a sample mean of 60% with a standard deviation of 8%. What is the correct value of t to construct a 90% confidence interval for the true mean percentage of cacao? (Round to the nearest thousandth.)Select Answer:A. (0.577, 0.623)B. (0.539, 0.561)C. (0.527, 0.573) D. (0.589, 0.611)