An object has a density of 0.755 g/mL. Its volume is 640 mL. What is its mass?

Answers

Answer 1

Answer:

Answer:Density = 7.5 g/ml (By putting the given values.) [ The ratio of the mass to volume is the density, that's why the unit of the density is also the ratio of the unit of mass to the unit of volume. ] Hence, the density of the object is 7

Explanation: Google

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The (nonconservative) force propelling a 1.50 103-kg car up a mountain road does 5.00 106 J of work on the car. The car starts from rest at sea level and has a speed of 25.0 m/s at an altitude of 1.90 102 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are non conservative forces.

A derived unit is a combination of fundamental units. Which of the following is an example of a derived unit?a) centimeter (used to measure distance)

b) gram (used to measure mass)

c) cubic centimeter (used to measure volume)

Answers

Answer:

Option (c)

Explanation:

The combination of two or more fundamental units is called derived unit. For example, cubic metre, newton per metre, metre per second.

Thus, cubic centimetre is a derived unit.

C)Cubic centimeter is derived unit here;

Which model of earth's interior does this image show? if u answer i'll give u a thanks

Answers

It shows the inner core, core, mantle, and crust

Final answer:

The student's question lacks an image, so a specific model can't be identified. However, a common model of Earth's interior includes four parts: the crust, mantle, outer core, and inner core. Each of these parts have distinct characteristics and they are made up of different materials.

Explanation:

Unfortunately, I'm not able to identify the specific model of Earth's interior based on your question as it doesn't include an image for me to review. However, I can tell you that commonly used models include the crust, mantle, outer core, and inner core model, based on our current understanding of geology. The crust is the surface layer, followed by the mantle which is the largest part of Earth's interior. Below the mantle are the outer core and the inner core, which are primarily made up of iron and nickel and exhibit different physical properties.

Learn more about Earth's interior models here:

brainly.com/question/32845465

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Calculate how much steam from water boiling at 100 C will just melt 50 gm of wax at 20 C. (Melting point of wax=55 C, sp. heat capacity of wax=0.7cal/g C, sp. latent heat of fusion of wax=35cal/g)

Answers

Answer:

m₁ = 5.507 x 10⁻³ kg = 5.507 g

Explanation:

The heat released by the steam must be absorbed by the melting wax, according to the law of conservation of energy:

Heat Released by Steam = Heat Absorbed by Wax

Latent Heat of Fusion of Steam = Heat Absorbed by Wax + Latent Heat of Fusion of Wax

m₁H₁ = m₂CΔT₂ + m₂H₂

where,

m₁ = mass of water = ?

H₁ = Latent Heat of Fusion of Water = 2260 KJ/kg = 2.26 x 10⁶ J/kg

m₂ = mass of wax = 50 g = 0.05 kg

C = specific heat capacity of wax = (0.7 cal/g°C)(1000 g/1 kg)(4.184 J/1 Cal)

C = 2928.8 J/kg.°C

ΔT₂ = Change in Temperature of Wax = 55°C - 20°C = 35°C

H₂ = Latent Heat of Fusion of Wax = (35 cal/g)(1000 g/1 kg)(4.184 J/1 Cal)

H₂ = 146440 J/kg

Therefore,

m₁(2.26 x 10⁶ J/kg) = (0.05 kg)(2928.8 J/kg.°C)(35°C) + (0.05 kg)(146440 J/kg)

m₁ = (5125.4 J + 7322 J)/2.26 x 10⁶ J/kg

m₁ = 5.507 x 10⁻³ kg = 5.507 g

When preparing for a rocket launch, the mission control center uses the phrase "T minus" before liftoff. ...T minus 3, T minus 2, T minus 1, ... After the rocket has launched, "T plus" is used while the rocket is in flight. ...T plus 1, T plus 2, T plus 3, ... When does the rocket launch? What does "T" represent?

Answers

The rocket launches when the countdown reaches "T minus 0." "T" represents the time remaining until a specific event.

What does "T" symbolize in rocket launch countdowns?

In the context of rocket launches, "T" represents time. The countdown begins with "T minus" indicating the time remaining until liftoff. As the countdown progresses, the value of "T" decreases, counting down to zero, which marks the exact moment of launch.

Once the rocket is airborne, the countdown transitions to "T plus," denoting the time elapsed since liftoff. This standardized countdown terminology allows mission control to communicate crucial timing information precisely and efficiently during various phases of the rocket's journey.

Answers

The conservation of mechanical energy allows to find the results for the questions of the motion of mass in a conservative force are;

a) the velocity at x = 4 m is: v = 16.9 m / s

b) The acceleration at x = 4m is: a = 17.8 m / s²

c) The maximum elongations is: x = 6.67 m

Given parameters

The potential energy U = - α x² + β x³ with α= 2 j/m² and β= 0.3 j/m³

The mass of the body m = 0.0900 kg

The distance x = 4.00 m

To find

a) The speed

b) The acceleration

c) The maximum value of the distance

The conservation of mechanical energy is one of the most important concepts in physics, stable that if there is not friction the mechanical energy remains constant at all points.

Em = K + U

Where Em mechanical energy, K the kinetical energy ang U the potential energy.

a) Let's find the velocity using the conservation of mechanical energy

Starting point. Where the mass is released.

Em₀ = U (0)

Final point. When for a distance of x = 4 m here we have potential and kinetic energy.

$Em_f$ = K + U (4)

They indicate that the only force is conservative, therefore mechanicalenergy is conserved

Em₀ = $Em_f$

0 = ½ m v² + U (4)

½ m v² = -U (4)

v² = 2 / m (αx² - β x³)

Let's calculate

v² = $(2)/(0.09)$ (2 4² - 0.3 4³)

v = $√(284.44)$

v = 16.9 m / s

b) Acceleration is requested at this point.

We use that potential energy and force are related

F = $- ( dU)/(dx)$

We carry out the derivatives

F = 2αx - 3βx²

Let's calculate

F = 2 2 4 - 3 0.3 4²

F = 1.6 N

Now we use Newton's second law that relates the net force with the product of the mass and the acceleration of the body.

F = ma

a = $(F)/(m)$

a = $(1.6)/(0.09)$

a = 17.8 m / s²

c) At maximum displacement.

Let's use conservation of mechanical energy

Starting point. Where x = 0 is released

Emo = U (0) = 0

Final point. Point of maximum elongation, kinetic energy is zero

$Em_f$ = U (xmax)

Energy is conserved

Em₀ = $Em_f$

$0 = U(x_(max))$

-αx² + βx³ = 0

x² (-α + βx) = 0

the solutions of this equation is:

x = 0

-α + βx = 0

x = $(\alpha)/(\beta )$

Let's calculate

x = $(2)/(0.3)$

x = 6.67 m

In conclusion using the conservation of mechanical energy we can find the results for the questions of the motion of mass in a conservative force are;

a) the velocity at x = 4 m is: v = 16.9 m / s

b) The acceleration at x = 4m is: a = 17.8 m / s²

c) The maximum elongations is: x = 6.67 m

Learn more here: brainly.com/question/2615468

Answer:

a) v= 284.44 $(m)/(s^(2))$

b) a=17.78 $(m)/(s^(2) )$

c) x=6.67m

Explanation:

a).

$U(x)=-\alpha *x^(2) +\beta*x^(3)\n\alpha=2(J)/(m^(2))\n\beta=0.3(J)/(m^(2))\nU(0)+V(0)=U(4)+V(4)\nU(0)=-\alpha *0^(2) +\beta*0^(3)=0\nU(0)=0\nV(0)=0\n0=U(4)+V(4)\nU(4)=-\alpha *4^(2) +\beta*4^(3)\nU(4)=-2*4^(2)+0.3*(4^(3))\nU(4)=-12.8 J\n0=-12.8J+V(4)\n12.8=(1)/(2)*m*(v_(4))^(2) \n v_(4)^(2) =(2*12.8J)/(0.09kg)\n v_(4)^(2)=284.44$

$v_(4)=√(284.44)\nv_(4)=16.8 (m)/(s)$

b).

$F_(x)=(dU)/(dt)\nF_(x)=2*\alpha*x-3*\beta *x^(2) \nF_(4)=2*2*4-3*0.3*(4)^(2)\nF_(4)=1.6N\nF_(4)=m*a\na=(F_(4))/(m)=(1.6N)/(0.09kg)\na=17.7 (m)/(s^(2) )$

c).

$F_(x)=m*ax\nax=(F_(x))/(m) \nax=(4x-0.9x^(2))/(0.09kg)\n(dVx)/(dt)= (4x-0.9x^(2))/(0.09kg)\n\int\limits^x_x {(1)/(0.09)*(4x-0.9x^(2)) } \, dx\n (Vx^(2) )/(2)=22.2x^(2) -3.3x^(3)$

Value x,0

$Vx^(2) =44.4x^(2) -6.6x^(3)\n Vx=\sqrt{44.4x^(2) -6.6x^(3)}$

Inside the square root is the value of maximum value of x

$44.4x^(2) -6.6x^(3)=0\nx^(2)(44.4-6.6x)=0\n x=0$ but that value is not real so:

$44.4-6.6x=0\n6.6x=44.4\nx=(44.4)/(6.6)\n x=6.67m$

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