Answer:
Scandium
Explanation:
the ability of bases to release sodium ions into solution
the ability of bases to release hydrogen ions into solution
the ability of a base to react with carbonate or bicarbonate
the ability of a base to react with a soluble metal salt
The Big Island of Hawaii
The Appalachian Mountains
The Himalaya Mountain Range
Given data:
Sublimation of K
K(s) ↔ K(g) ΔH(sub) = 89.0 kj/mol
Ionization energy for K
K(s) → K⁺ + e⁻ IE(K) = 419 Kj/mol
Electron affinity for Cl
Cl(g) + e⁻ → Cl⁻ EA(Cl) = -349 kj/mol
Bond energy for Cl₂
1/2Cl₂ (g) → Cl Bond energy = 243/2 = 121.5 kj/mol
Formation of KCl
K(s) + 1/2Cl₂(g) → KCl(s) ΔHf = -436.5 kJ/mol
To determine:
Lattice energy of KCl
K⁺(g) + Cl⁻(g) → KCl (s) U(KCl) = ?
Explanation:
The enthalpy of formation of KCl can be expressed in terms of the sum of all the above processes, i.e.
ΔHf(KCl) = U(KCl) + ΔH(sub) + IE(K) + 1/2 BE(Cl₂) + EA(Cl)
therefore:
U(KCl) = ΔHf(KCl) - [ΔH(sub) + IE(K) + 1/2 BE(Cl₂) + EA(Cl)]
= -436.5 - [89 + 419 + 243/2 -349] = -717 kJ/mol
Ans: the lattice energy of KCl = -717 kj/mol
The lattice energy of KCl is calculated using the Born-Haber cycle by considering the energies of several steps including the sublimation of potassium, ionization of potassium, dissociation of Cl bond, electron affinity of Cl, and formation of KCl. The given values are plugged into a formula resulting in a lattice energy of -718 kJ/mol.
To calculate the lattice energy of KCl using the Born-Haber cycle, we need to follow several thermochemical steps. The steps include, first sublimation of potassium, the ionization of potassium, bond dissociation enthalpy to produce Cl, the electron affinity of Cl, and formation of KCl (s). Combining energy changes associated with all these steps would give us energy change for the formation of KCl from individual K and Cl2, it is called as enthalpy of formation (ΔH°f) for KCl.
Using the given values for each step, we use the formula: ΔH°f = ΔHsub + IE1 + 1/2* DCl2 - EA1 + lattice energy.
Substituting the given values, -436.5 = 89 + 419 + 1/2*243 -349 + lattice energy. Solving gives the lattice energy as -718 kJ/mol.
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Explanation:
Substances with their density less than the density of water which is 1 g/cm³ will float on it whiles those greater than that of water will sink into the water.
From the question the density of the object is 0.8 g/cm³
Since it's density is less than that of water the object will float on water .
Hope this helps you
An object with a density of 0.8 g/cm3 will float in water because its density is less than the density of water, which is 1 g/cm3.
The question is asking whether an object with a density of 0.8 g/cm3 will float or sink in water. Floating and sinking are determined by the principle of buoyancy, which depends on the density of the object compared to the fluid (in this case, water) it is placed in.
Water has a density of 1 g/cm3. So, if the object's density is less than 1 g/cm3, it will float, if it's more it will sink. Since 0.8 g/cm3 is less than 1 g/cm3, an object with this density will float in water.
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