Solve for p3(p + q) = p
A. q = -2/3p
B. q = -3/2p
C. p = -2/3q
D. p = -3/2q

Answers

Answer 1
Answer: it’s A! hope this helps you out!

Related Questions

The endpoints of AB are A(4, 2) and B(1,-2). What are the coordinates of the midpoint of AB?​
Simplify-2(3x - 4y) +5(x+3y)
Please Help. I have no idea how to do this. Anything helps.
Triangle P=27,Q=40,P=33 law of sines round measures to the nearest tenth
Find the area of a triangle with base b = 24 ft and height h = 17 ft.

Find the slope of the line whose equation is y=2/3x-3.
Please explain :)

Answers

Answer:

m=2/3.

Step-by-step explanation:

the equation for slope is y=mx+b, where m is slope. So, 2/3 is your slope.

In a right triangle, the measure of one acute angle is 26°. What is the measure of the other acute angle?

Answers

The answer is 64 degrees

The pyramid of khagra,in Egypt,is 488 feet tall. The Eiffel Tower,in France,is 1,063 feet tall. How much taller is the Eiffel Tower than the Pyramid of Khafra?

Answers

Answer:

The Eiffel Tower in France is 575 feet taller than pyramid of khagra.          

Step-by-step explanation:

We are given the following in the question:

Height of pyramid of khagra = 488 feet

Height of Eiffel Tower in France = 1,063 feet

Difference in height =

= Height of Eiffel Tower in France - Height of pyramid of khagra

=1063 - 488\n= 575\text{ feet}

Thus, the Eiffel Tower in France is 575 feet taller than pyramid of khagra.

Use the function f(x)=x 2 −6x+8 to answer the following questions: a. What is the y-intercept? b. What are the x-intercepts? c. What is the vertex? d. What is the axis of symmetry?

Answers

Answer:

see explanation

Step-by-step explanation:

given the function

f(x) = x² - 6x + 8

(a)

to find the y- intercept , let x = 0 in f(x)

f(0) = 0² - 6(0) + 8 = 0 - 0 + 8 = 8 ← y- intercept

(b)

to find the x- intercepts , let f(x) = 0 , that is

x² - 6x + 8 = 0 ← in standard form

(x - 2)(x - 4) = 0 ← in factored form

equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x - 4 = 0 ⇒ x = 4

the x- intercepts are x = 2 and x = 4 or (0, 2 ), (0, 4 ) in coordinate form

(c)

given a quadratic in standard form

f(x) = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the vertex is

x_(vertex) = - (b)/(2a)

f(x) = x² - 6x + 8 ← is in standard form

with a = 1 and b = - 6 , then

x_(vertex) = - (-6)/(2) = - (- 3) = 3

evaluate f(3) for corresponding y- coordinate

f(3) = 3² - 6(3) + 8 = 9 - 18 + 8 = - 9 + 8 = - 1

vertex = (3, - 1 )

(d)

the axis of symmetry is a vertical line , passing through the vertex with equation

x = c ( c is the value of the x- coordinate of the vertex )

equation of axis of symmetry is then x = 3

How do solve for 2m2 +2m-12=0
This if quadratic formula

Answers

2m^2 +2m-12=0 \ /:2\n \nm^2+m-6=0\n \nm^2+3m-2m-6=0\n \nm(m+3)-2(m+3)=0\n \n(m+3)(m-2)=0\n \nm+3=0\ \ \ \vee\ \ \ m-2=0\n \n.\ \ \ \ m=-3\ \ \ \ \ \ \ \ \ \ \ \ m=2

Given: x + 2y = -6.

Solve for y.

Answers

x + 2y =-6

Subtract x on both sides

x + 2y-x =-6-x

2y =-6-x

Divide by 2 on both sides

(2y)/(2) =(-x-6)/(2)\n\ny =(-x-6)/(2)\n\n \boxed{\bf{y=-(1)/(2)x -3}}