a soccer tournament 12 teams are wearing red shirts, 6 teams are wearing blue shirts, 4 teams are wearing orange shirts, and 2 teams are wearing white shirts. for every 2 teams at the tournament, there is 1 team wearing shirt

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Answer 1

Answer: when you add up 12, 6, 4 and 2 you get 24 team. Of the 24 teams, there are 12 teams (1/2 of all the teams) wearing red. This means that for every 2 teams, 1 team is wearing red

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One number is 1 more than 2 times another. Their product is 10. Find the numbers.

PLZ Help 20 points!!!!!

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So i think you gotta see where the point is ay and if it isnt rig

Cx/2=ag answer needed for x

Answers

Cx/2=ag
First multiply each side by 2 Cx=2ag
Then divide by C on both sides x=2ag/C

ANSWER: x=2ag/C

The answer to this answer is 56

Nick is now seven times as old as harry. In 6 years , nick will be five times as old as harry. How old will harry be in 6 years?

Answers

Answer:

18 years

Step-by-step explanation:

Let Nick age is x years and Harry's age is y years.

Hence, we have the equation

x = 7y ......(1)

After six years, Nick's age is (x+6) and Harry's age is (y+6)

Hence, we have

$x+6=5(y+6)\nx+6=5y+30$

Plugging x = 7y, we get

$7y+6=5y+30\n2y=24\ny=12$

Hence, from equation (1)

x = 7(12)

x =84

In 6 years, Harry will be of 12 + 6 =18 years.

x = Harry's Age

Nick's age is 7x

In 6 years Harry is 7x+6, and Nick is 5(x+6)

7x+6=5x+30

2x+6=30

2x = 24

x = 12

Harry = 12 years old and in 6 years Harry will be 18.

ABCD is rectangle. Find the length of each diagonal
AC=c/3
BD=4-c

Answers

Answer:

Recall the following result:

In a rectangle ABCD, the diagonals AC and BD are equal to each other, that is, AC = BD.

Consider the following statement:

$\text{AC}=(c)/(3)$ and BD =4-c

The objective is to find the length of each diagonal.

As per the result:

In a rectangle ABCD:

AC = BD

Substitute the given values:

$(c)/(3) =4-c$

Multiply both sides by 3:

$c = 3(4-c)$

Simplify:

c = 12-3c

Add 3c to both sides :

4c= 12

Divide both sides by 4;

c = 3

Then,

$\text{AC}=(3)/(3)=1$

BD=4-3 = 1

Therefore, the length of each diagonal is, 1.

The lenght of each diagonals is 1.

Consider the quadratic equation y = –3x2 – 2x + 4. A. Find the value of the discriminant. B. How many real roots does the equation have? C. Does the vertex of the graph of the equation lie above, on, or below the x-axis?

Answers

A. discriminant = 52;
B. 2, because 52 > 0
C. - discrminant / 4a = -52 / -12 = 6 > 0 => the vertex of the graph of the equation lie above the x-axis.

Given the equations y = x2 - 4x - 5 and y + x = -1, one point that satisfies both equations is

Answers

$\left \{ {{y=x^2-4x-5} \atop {y+x=-1}} \right. \n \n \left \{ {{y=x^2-4x-5} \atop {y=-1-x}} \right. \n\n \n x^2-4x-5=-1-x\n \n x^2-3x-4=0\n \n \Delta=(-3)^2-4.1.(-4)=9+15=25\n \n x=(3 \pm5)/(2)\n \n x_1=-1 \rightarrow y=-1+1=0\n \n x_2=4 \rightarrow y=-1-4=-5$

We found 2 points that satisfies both equations (4,-5) and (-1,0)

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five dice are thrown simultaneously. find the number of outcomes in which at most one of the dice shows 5?