Answer:
3(u^2 +u-3)
-------------------
u(u-3)^2
Step-by-step explanation:
u 1
---- + -------
u-3 u
-------------------------
u-3
----------
3
Get a common denominator for the numerator
u *u 1(u-3)
---- + -------
(u-3)u u(u-3)
-------------------------
u-3
----------
3
u *u + (u-3)
-----------
(u-3)u
-------------------------
u-3
----------
3
Now use copy dot flip
u *u + (u-3) 3
----------------- * -------------
(u-3)u u-3
3(u^2 +u-3)
-------------------
u(u-3)^2
x y
1 4
−1 −2
3 10
5 16
Yes
No
Yes or no?
Answer:
Yes this is a function..
Step-by-step explanation:
We have to see the inputs and outputs for the function.
Here x represents input and y represents output.
For a relation to be a function there should be no repition in domain or input of the function i.e. every element in domain should be unique.
The domain for given relation is:
{1,-1,3,5}
All the inputs are only once mapped to the output so this relation is a function ..
Yes. You should add commas next time to make it easier to read.
fix) = 3x2+6x-1 y gix) = 2x2-3x-3
find f(x) - g(x) =
Answer:
f(x)-g(x)=x^2+9x+2
Step-by-step explanation:
f(x)-g(x)=(3x^2+6x-1)-(2x^2-3x-3)
=3x^2+6x-1-2x^2+3x+3
=(3x^2-2x^2)+(6x+3x)+(-1+3)
=x^2+9x+2
Answer:
Step-by-step explanation:
Answer: 0.0465116279
Step-by-step explanation: