Answer:
7
Step-by-step explanation:
Given that a ride can hold 30 people at once, and that 220 people in total went on the ride, one minus the total number of people (to account for the last ride not being completely filled) divided by the total ride capacity gives us 7.3. This means the ride was completely filled 7 times.
To find out how many times the carnival ride was completely filled, we will divide the total number of people who went on the ride, by the maximum number of people the ride can hold at a time. However, we know that the last ride was not completely full, meaning there was at least one less person on the ride than it can hold, so we need to subtract 1 from the total number of people before proceeding.
So, we have: (220 people - 1) ÷ 30 people = 7.3. Since a ride can't be partially filled (i.e. 0.3 of a ride), we know that the ride was filled completely 7 times, and the remaining 0.3 represent the last, not completely filled ride.
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Answer:
The 3rd choice
Answer: the third one
Step-by-step explanation:
to get from 6 to 3 u divide by 2 and same thing goes for 10 to 5 and 14 to 7
hope this help! :)
Answer:
50
Step-by-step explanation:
The distance between the friends is changing at the constant rate of 50 mph.
___
The equation for the distance in the westerly direction is ...
w = 30t . . . . . miles, where t is time in hours
The equation for the distance in the southerly direction is ...
s = 40t . . . . . miles, where t is time in hours
Then the total distance between the friends is ...
d = √((30t)² + (40t)²) = √(2500t²) = 50t . . . . miles, where t is time in hours
And the rate of change of distance is the derivative of this with respect to t:
dd/dt = 50 . . . . . . miles per hour
Answer:
$440
Step-by-step explanation:
100%-25%=75%
75%=330
1%=330÷75=4.4
100%=100x4.4=440
Hope this helps! Thanks.
The distance between the midpoints of the first segment and the third segment is 2k/3. Hence, option A is the right choice.
The mid-point of a line segment is the point from which the distance to both ends of the line segment is equal.
In the question, we are given a line segment of length k units, which is divided into 3 equal parts.
We are asked to find the distance between the midpoints of the first and third segments.
Firstly, we divide the line segment at points k/3 and 2k/3, to get three equal parts of lengths k/3 each.
Now, the mid-point of the first segment = (0 + k/3)/2 = k/6.
The mid-point of the third segment = (2k/3 + k)/2 = 5k/6
Therefore, the distance between the midpoints of the first segment and the third segment is (5k/6 - k/6) = 4k/6 = 2k/3. Hence, option A is the right choice.
Learn more about midpoints at
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Line segment of length k is divided into 3 equal parts.
so first segment is 0-k/3 and third segment is 2/3k-k
so mid-pt of 1st = k/6 and 3rd = 5/6k
so the distance in between = 5/6k-k/6 = 4/6k = 2/3k
ans is A
B. There is evidence to conclude that p1C.There is evidence to conclude that p1>p2 because all values in the interval are positive.
D. There is evidence to conclude that p1E. There is evidence to conclude that p2>p1 because 0.247 and 0.325 are both greater than 0.05.
You can use the fact that the 90% confidence interval given is all positive value for the test statistic being the difference of and .
The conclusion that is supported by the given confidence interval is given by:
Option C: There is evidence to conclude that because all values in the interval are positive.
Since it is given that the difference is measured by ,
and since the given confidence interval at 90% confidence for that difference is obtained to be (0.247,0.325), thus we can say that 90% difference value of , will be lying in that given interval.
Since the interval is all positive, thus we can say that 90% of the times, the difference will be positive which indicates that
Thus, the conclusion that is supported by the interval is given by:
Option C: There is evidence to conclude that because all values in the interval are positive.
Learn more about confidence interval here:
Answer:
C
Step-by-step explanation:
Statistics!!
When we have a confidence interval for the difference in proportions or means, our null hypothesis is always that there's no difference. (H0 = p1-p2 = 0.)
If the difference is positive, that means we have sufficient evidence p1>p2.
If it's negative, then we have sufficient evidence p2>p1.
Why not A: incorrect interpretation of the interval
Why not B: doesn't look like a complete answer
Why not D: also doesn't look like a complete answer
Why not E: this confuses the definition of alpha-level and p-value with confidence interval values. If those were p-values and greater or less than an alpha-level, we would reject or fail to reject the null hypothesis. That isn't the case here.