Answer:
Step-by-step explanation:
The midpoint M of two endpoints of a line segment can be found by using the formula
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
A(2,-5); B(6,1)
So we have
We have the final answer as
Hope this helps you
The required height of the tree is 32.5 meters.
Given that,
A person 100 meters from the base of a tree, observes that the angle between the ground and the top of the tree is 18 degrees. To estimate the height h of the tree to the nearest tenth of a meter.
These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operations.
Here,
let the height of the tree be x, and the slant height from the foot of the person to the top of the tree be h,
according to the question,
base length = 100
cos 18 = 100 / h
h = 105.14
Now,
sin 18 = x / h
sin 18 = x / 105.14
x = 32.5 meters
Thus, the required height of the tree is 32.5 meters.
Learn more about trigonometry equations here:
#SPJ2
This is right angle trig. We know that...
cos(18°) x hypotenuse = 100
hypotenuse = 100/cos(18°)
hypotenuse = 105.15 meters approx.
Because they want the height of the tree we want "sin(18°) x hypotenuse".
sin(18°) x 105.15 = 32.5 meters approx.
answer: 32.5 meters approx.
Answer:
50
Step-by-step explanation:
Answer: 50 millimeters
A.
equiangular
B.
regular
C.
equilateral
B.
C.
D.
Answer:
C
Step-by-step explanation:
A straight diagonal line going the middle of the graph is a proportianal relationship.
the answer is the letter
Step-by-step explanation:
the answer is C
fountains, each of which can launch a vertical stream of water to a different height, as indicated in the table below. Model A Model B Model C
height 77 100 240
time to fall (s) 2.194, ----, ----
initial velocity 70.2 , ----, 123.9
complete the following tasks, filling in the missing values in the table as you find them:(1)Find the time water would take to fall from each height in the table back to its starting level.(2)Find the initial upward velocity required for fountain B to launch the water to its maximum height(3)Create a function that will give you the minimum initial upward velocity ,v ,required to launch water to any given height , h. thank you
I am only in the seventh grade so it might not be right, but this is what I would do:
Set up a proportion: 77/2.194/70.2 = 100/x/y = 240/z/123.9
Then solve for x: if 77 equals 100, that means 2.194 is 77% of x. So x equals 2.849350649
*the 350649 repeats
Then solve for y: Like mentioned before 70.2 is going to only be 77% of y, so if you set that up in a proportion, it is: 70.2/77 = y/100. So when you solve you get 91.16883116883117...
Then finally we solve for z: 100 is only 41.6% of 240, so that means 2.849350649 is only 41.6% of z. So then we set it up as a proportion: 141.6/100 = z/2.849350649, then we solve. It equals 4.034680518984.
Sorry if my answer was redundant, but hope this helped!
Answer: 12 Wreaths
Explanation:
If he wants to have the same amount of each item on the wreaths, we need to find the factors of each to find the highest amount of wreaths he can make.
60=2×2×3×5=(2×2×3)×5
36=2×2×3×3=(2×2×3)×3
48=2×2×2×2×3=(2×2×3)×2×2
So, 2×2×3 is in each which is equal to 12 so he can make 12 wreaths with the amount and factor on each wreath below:
12 wreaths
5 bows on each
3 silk roses each
4 silk carnations each
Hope this helps! :)
Answer: 12 Wreaths
Explanation:
If he wants to have the same amount of each item on the wreaths, we need to find the factors of each to find the highest amount of wreaths he can make.
60=2×2×3×5=(2×2×3)×5
36=2×2×3×3=(2×2×3)×3
48=2×2×2×2×3=(2×2×3)×2×2
So, 2×2×3 is in each which is equal to 12 so he can make 12 wreaths with the amount and factor on each wreath below:
12 wreaths
5 bows on each
3 silk roses each
4 silk carnations each
Hope this helps! :)