MATHEMATICS HIGH SCHOOL

Compare and order the numbers below from least to
greatest.
4.6,2.8,,17,7

Answers

Answer 1
Answer:

2.8, 4.6, 7, 17  

The first number is less than the second number by 1.8, second number is less than the third number by 2.4, third number is less than the forth number by 10.

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the price of the printer was reduced from $400 to $180 . what was the percent decrease? amount of increase or decrease divided by amount of original multiplied by 100

Answers

400 - 180 = 220

220/400 = 0,55

0.55 x 100  = 55

So the percentage of decrease would be : 55 %

Hope this helps

I need help filling out the boxes because I'm not understand the pattern going on.

Answers

ΔRST: R(-2, -3)
            S(0, 2)
            T(2, -3)

ΔR'S'T': R'(-6, -9)
              S'(0, 6)
              T'(6, -9)

S' = 3S
T' = 3T

Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto’s average speed was 0.25 miles per minute and Riko’s average speed was 0.35 miles per minute, then Riko will be behind Yuto when 0 ≤ t < 52.5, where t is time in minutes. Explain what this solution means and why t cannot be less than zero.

Answers

Riko will be behind Yuto when 0 ≤ t < 52.5.

This means for the first 52.5 minutes, Riko will be behind Yuto as he started late. At 52.5th minute Riko will cross Yuto and move ahead because average speed of Yuto is larger than average speed of Riko.

So for first 52.5 minutes, Yuto takes the lead and for the remaining time Riko takes the lead on the path.

t represents time in the given scenario. Time cannot have negative values, it can only be zero or have some positive value. Therefore, t cannot be less than 0. When t is equal to 0 it indicates the start of journey. 
The solution means that Riko will be behind Yuto until they both reach 52.5 miles, t cannot be zero because is the time spent since they both left home.

In ΔOPQ, p = 180 inches, q = 120 inches and ∠O=171°. Find the length of o, to the nearest inch.

Answers

Given:

In ΔOPQ, p = 180 inches, q = 120 inches and ∠O=171°.

To find:

The length of o, to the nearest inch.

Solution:

According to cosine formula,

a^2=b^2+c^2-2bc\cos A

Using cosine formula in ΔOPQ, we get

o^2=p^2+q^2-2pq\cos O

On substituting the values, we get

o^2=(180)^2+(120)^2-2(180)(120)\cos (171^\circ)

o^2=32400+14400-43200(-0.9877)

o^2=46800+42668.64

o^2=89468.64

Taking square root on both sides.

o=√(89468.64)

o=299.113

o\approx 299

Therefore, the length of o is about 299 inches.

Answer:299

Step-by-step explanation:

3y+2/4=7 I don't understand this at all

Answers

Don't let the fraction confuse you.

3y + 2/4 = 7

You could multiply each side by 4 to get rid of the fraction:

12y + 2 = 28

Subtract 2 from each side:

12y = 26

Divide each side by 12 :

y = 26/12  or  13/6   or    2 and 1/6
Actually u want to find the value of 'y' step1:rearranging 3y=7-2/4 step2:take LCM and subract 3y=26/4 step3:simplify 3y=13/2 y=13/6

In the paper airplane shown , ABCD =EFGH, M

Answers

The answer is d because angle b is a 90 degree angle (because it is as corner of paper); angle c is also 90 (it's given); and angle a is 143 (also given). You add all three up and get 323. Subtract 323 from 360 (because 360 is how many degrees that are in a quadrilateral) and the answer is 37
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