MATHEMATICS COLLEGE

Solve the equation. X^5-5x^3+4x=0

Answers

Answer 1

Answer:

Answer:

Wait

Step-by-step explanation:

Is a equation or polynomial

Answer 2

Answer:

Answer:

0, +/- 1. +/- 2

Step-by-step explanation:

$x^(5) -5x^(3) +4x=0$ Write the equation in the form of P(x) = 0.

$x(x^(4) - 5x^(2) + 4) = 0$ Factor out the GCF, x.

$x(x^(2))^(2) - 5x^(2) + 4 = 0$ Factor $(x^(2))^(2)- 5x^(2) + 4 = 0$ .

$x = 0,$ $(x^(2))^(2) - 5x^(2) + 4 = 0$ Let a = $x^(2)$ and substitute.

$a^(2) - 5a + 4 = 0$ Factor.

$(a - 4)(a - 1) = 0$ Replace a with $x^(2)$ .

$(x^(2) - 4)(x^(2) -1) = 0$ Factor $(x^(2) - 4)$ as a difference of squares.

$(x -2)(x+2)(x^(2) -1) = 0$ Use the Zero Product Property

$x = 2, x = -2, x^(2) = -1$

$x = 0, 1, -1, 2, -2$

Related Questions

6-2d=42 What is D please help me find what it is
Find the angle between the diagonal of a cube of side length 9 and the diagonal of one of its faces, so that the two diagonals have a common vertex. The angle should be measured in radians. (hint: we may assume that the cube is in the first octant, the origin is one of its vertices, and both diagonals start at the origin.)
PLEASE help it’s a multiple choice question i’ll mark u brainliest
What is the maximum height of the basketball when the player passes the ball to someone? Initially, the ball moves at a speed of 12m/sec at an angle with respect to the horizontal of 45 degrees. Is it possible that other player standing 8m away is able to catch the ball without any bounces?
A rectangular window has a length of 81.47 cm and a width of 34.2 CM what is the least

Will a truck that is 10 feet wide carrying a load that reaches 12 feet above the ground clear the semielliptical arch on the one-way road that passes under the bridge shown in the figure on the right? 13 ft --- 52 ft It will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately (Round to two decimal places as needed.) feet.

Answers

Height of the archway 5 feet from the center is required.

The height of the archway 5 feet away from the center is 12.757 feet.

Semi-major axis = $a=(52)/(2)=26\ \text{feet}$

Semi-minor axis = $b=13\ \text{feet}$

The formula for ellipse is

$(x^2)/(a^2)+(y^2)/(b^2)=1\n\Rightarrow (x^2)/(26^2)+(y^2)/(13^2)=1$

At 10 feet is the width of the truck.

The truck is passing through the center so the $x=(10)/(2)=5$

$(5^2)/(26^2)+(y^2)/(13^2)=1\n\Rightarrow y=\sqrt{(1-(5^2)/(26^2))* 13^2}\n\Rightarrow y=12.757\ \text{feet}$

Now $y=12.757\ \text{feet}>12\ \text{feet}$

So, the height of the archway 5 feet away from the center is 12.757 feet.

Learn more:

brainly.com/question/15864536?referrer=searchResults

Figure is missing, so i have attached it.

Answer:

it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft

Step-by-step explanation:

The standard form of equation of an ellipse is;

x²/a² + y²/b² = 1

From the figure in the image attached, we can see that the radius is; a = 52/2 = 26 ft

While the value of b = 13 ft

Thus;

x²/26² + y²/13² = 1

x²/676 + y²/169 = 1

We want to find the height of the archway of the bridge 5 feet from the center.

Thus, we will plug in 5 for x to get;

5²/676 + y²/169 = 1

(25/676) + (y²/169) = 1

Multiply through by 676 to get;

25 + 4y² = 676

4y² = 676 - 25

y² = 651/4

y² = 162.75

y = 12.76 ft

Thus height of the truck is 12 ft and so it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft

It is believed that the average amount of money spent per U.S. household per week on food is about $98, with standard deviation $11. A random sample of 36 households in a certain affluent community yields a mean weekly food budget of $100. We want to test the hypothesis that the mean weekly food budget for all households in this community is higher than the national average. State the null and alternative hypotheses for this test, the test statistic and determine if the results significant at the 5% level.

Answers

Answer:

The null hypothesis is

$H_o : \mu =$ $98

The alternative hypothesis is

$H_a : \mu >$ $98

test statistics $t_s = 1.091$

The the result of the test statistics is significant

Step-by-step explanation:

From the question we are told that

The population mean is $\mu =$ $98

The standard deviation is $\sigma =$ $11

The sample size is $n = 36$

The sample mean is $\= x =$ $100

The level of significance is $\alpha = 5$ % = 0.05

The null hypothesis is

$H_o : \mu =$ $98

The alternative hypothesis is

$H_a : \mu >$ $98

Now the critical values for this level of significance obtained from critical value for z-value table is $z_\alpha = 1.645$

The test statistics is mathematically evaluated as

$t_s = (\= x - \mu)/( (\sigma )/( √(n) ) )$

substituting values

$t_s = (100 - 98)/( (11 )/( √(36) ) )$

$t_s = 1.091$

Looking at $z_\alpha \ and \ t_s$ we see that $z_\alpha \ > t_s$ hence the we fail to reject the null hypothesis

hence there is no sufficient evidence to conclude that the mean weekly food budget for all households in this community is higher than the national average.

Thus the the result is significant

In a video game, the chance of rain each day is always 30%. At the beginning of each day in the video game, the computer generates a random integer between 1 and 50. Explain how you could use the number to simulate the weather in the video game

Answers

Answer:

If the integer is in the range 1–15, then the weather could be declared rainy

Step-by-step explanation:

Assuming the integers are uniformly distributed 15 of them will constitute 30% of the possible integer. If the integer is in the range 1–15, then the weather could be declared rainy. That would make the probability of rain 30%, as required.

You have just completed an experiment measuring the length (in mm) of 12 soybean plants after 3 days of sprouting. The measurements are listed below:53 47 51 54 43 39 61 57 55 46 44 43

If you doubled every measurement in this dataset (e.g., 106, 94, 102, ...), what would the new IQR equal? (Think about the SD too!)

Answers

Answer:

The new IQR is 22.

Step-by-step explanation:

We are given the following data of length (in mm) of 12 soybean plants after 3 days of sprouting.

53, 47, 51, 54, 43, 39, 61, 57, 55, 46, 44, 43

Sorted data:

39, 43, 43, 44, 46, 47, 51, 53, 54, 55, 57, 61

Formula:

$IQR = Q_3 - Q_1\nQ_3 = \text{upper median},\nQ_1 = \text{ lower median}$

$Median:\n\text{If n is odd, then}\n\nMedian = \displaystyle(n+1)/(2)th ~term \n\n\text{If n is even, then}\n\nMedian = \displaystyle((n)/(2)th~term + ((n)/(2)+1)th~term)/(2)$

$Median ==(6^(th)+7^(th))/(2) (47+51)/(2) = 49$

$Q_1 =(3^(rd)+4^(th))/(2) = (43 + 44)/(2) = 43.5\n\nQ_3 =(9^(th)+10^(th))/(2)= (54 + 55)/(2) = 54.5$

IQR = $Q_3 -Q_1 =54.5-43.5= 11$

If every measurement is doubled, then, the IQR will also double itself.

Thus,

New IQR =

$2* \text{IQR}\n=2\TIMES 11\n=22$

Thus, the new IQR is 22.

Please help I really don’t understand this

Answers

You input the values and the equation would end up as

-5 = -3/2 (6) + b

You use y = mx + b

Y is -5
M is the slope = -3/2
X is 6
B is the y intercept but that is not given

Which of the following expression are equivalent to 2x+4 select three answers?A.6x
B.1/3(18x)
c.1/3(6x+12)
d.2/3(3x+6)
e.2(x+4)
f.4(1/2x+1)

Answers

Answer:

A.6x

Step-by-step explanation:

hope i helped!! ...............

Other Questions

Help PLEASE!!!!!!!If BD bisects angle ABC, measure of DBC = 79 degrees, and measure of angle ABC= 9x-4, find the value of x.

What is 4901 and 75 estimated to

A company has two factories, factory A and factory B. The cost per item to produce q items in factory A is 200 + 3q q . The cost per item to produce q items in factory B is 400 + q 3q . Find an expression for the sum of these costs per item. Then divide this expression by 2 to find an expression for the average cost per item to produce q items in each factory.

A container in a pharmacy holds 0.92 liter of a solution. Mrs. Dwyer used 0.5 of the container for a prescription. How much did she use?A 0.046 litersB 0.46 litersC 4.6 litersD 46 liters