Question 4 options:Point N is the midpoint of line GC.

If GC = 10x – 6, and NC = 3x + 5.

Find the length of line GC.

x=

GC=

Answers

Answer 1
Answer: X= 1.5 and line GC= 9

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A washer and a dryer cost $857 combined. The washer costs $93 less than the dryer. What is the cost of the dryer?

Answers

The cost of the dryer is $475 and the cost of the washer is $382.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Given that, a washer and a dryer cost $857 combined.

Let the cost of dryer be x.

The washer costs $93 less than the dryer.

Then, the cost of washer will be x-93

So, x+x-93=857

2x=857+93

2x=950

x=$475

x-93=475-93

= $382

Hence, the cost of the dryer is $475.

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Answer:

Dryer cost $475;  Washer cost $382

Step-by-step explanation:

For this problem, we will simply set up a system of equations to find the value of each the washer (variable x) and the dryer (variable y).

We are given the washer and dryer cost $857 together.

x + y = 857

We are also given that the washer cost $93 less than the dryer.

x = y - 93

So to find the cost of the dryer, we simply need to find the value of y.

x + y = 857

x = y - 93

( y - 93 ) + y = 857

2y - 93 = 857

2y = 950

y = 475

So now we have the value of the dry to be $475.  We can check this by simply plugging in the value and see if it makes sense.

x + y = 857

x + 475 = 857

x = 382

And check this value:

x = y - 93

382 ?= 475 - 93

382 == 382

Therefore, we have found the values of both the washer and the dryer.

Cheers.

On two investments totaling $6,000, Kevin lost 3% on one and earned 6% on the other. If his net annual receipts were $288, how much was each investment?

Answers

ANSWER:

$ 800 was invested in the account at 3%

$5200 was invested in the account at 6%

STEP-BY-STEP EXPLANATION:

We can establish the following system of equations thanks to the help of the statement:

Let x represent the amount invested in the investment that lost value

Let y represent the amount invested in the investment that gained

value.

\begin{gathered} x+y=6000\rightarrow y=6000-x\text{ (1)} \n -0.03x+0.06y=288\text{ (2)} \end{gathered}

We replace equation (1) in (2) and solve for x:

\begin{gathered} -0.03x+0.06\cdot(6000-x)=288 \n -0.03x+360-0.06x=288 \n -0.09x=288-360 \n x=(-72)/(-0.09) \n x=800 \n \text{ Now, for y replacing in (1)} \n y=6000-800=5200 \end{gathered}

Therefore, $ 800 was invested in the account the lost value, and $ 5200 was invested in the account that gained value.

Which is equivalent to the following expression (3m^2+2mn-n^2)+(m^2+4mn-n^2)

Answers

Based on the available information, the expression (3m² + 2mn - n²) + (m² + 4mn - n²) is equivalent to 4m² + 6mn - 2n².

How the equivalent expression is determined?

To simplify the expression (3m² + 2mn - n²) + (m² + 4mn - n²), we can combine like terms.

Like terms have the same variables and the same exponents.

Let's group the like terms together:

(3m² + m²) + (2mn + 4mn) + (-n²- n²)

Combining like terms within each group, we get:

4m² + 6mn - 2n²

Therefore, in this case, it is concluded that the expression (3m² + 2mn - n²) + (m² + 4mn - n²) is equivalent to 4m² + 6mn - 2n².

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Answer:

4m² + 6mn - 2n²

Step-by-step explanation:

(3m^2+2mn-n^2)+(m^2+4mn-n^2)\n\n=3m^2+2mn-n^2+m^2+4mn-n^2\qquad\text{combine like terms}\n\n=(3m^2+m^2)+(2mn+4mn)+(-n^2-n^2)\n\n=\boxed{4m^2+6mn-2n^2}

Can you help me find abcd please

Answers

Answer:

A.2 B.4 C.3 D.4 E.6

Step-by-step explanation:

1/2 ÷ 3/4 = 1/2 x 4/3 (flip 3/4 and keep 1/2)

If you multiply 1/2 x 4/3 you will get 4/6.

Consider the optimization problem where A m × n , m ≥ n , and b m . a. Show that the objective function for this problem is a quadratic function, and write down the gradient and Hessian of this quadratic.

b. Write down the fixed-step-size gradient algorithm for solving this optimization problem.

c. Suppose that Find the largest range of values for α such that the algorithm in part b converges to the solution of the problem.

Answers

Answer:

Answer for the question :

Consider the optimization problem where A m × n , m ≥ n , and b m .

a. Show that the objective function for this problem is a quadratic function, and write down the gradient and Hessian of this quadratic.

b. Write down the fixed-step-size gradient algorithm for solving this optimization problem.

c. Suppose that Find the largest range of values for α such that the algorithm in part b converges to the solution of the problem.

is explained din the attachment.

Step-by-step explanation:

Solve the equation
- 1
- m - 7 = 5
3

Answers



1/3m-7=5

One solution was found :

m = 36
Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

1/3*m-7-(5)=0

Step by step solution :

Step 1 :

1
Simplify —
3
Equation at the end of step 1 :

1
((— • m) - 7) - 5 = 0
3
Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

7 7 • 3
7 = — = —————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

m - (7 • 3) m - 21
——————————— = ——————
3 3
Equation at the end of step 2 :

(m - 21)
———————— - 5 = 0
3
Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

5 5 • 3
5 = — = —————
1 3
Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

(m-21) - (5 • 3) m - 36
———————————————— = ——————
3 3
Equation at the end of step 3 :

m - 36
—————— = 0
3
Step 4 :

When a fraction equals zero :

4.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

m-36
———— • 3 = 0 • 3
3
Now, on the left hand side, the 3 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
m-36 = 0

Solving a Single Variable Equation :

4.2 Solve : m-36 = 0

Add 36 to both sides of the equation :
m = 36

One solution was found :

m = 36

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