MATHEMATICS HIGH SCHOOL

I need help pleeeeeaaaaasssseeeee
I need help pleeeeeaaaaasssseeeee - 1

Answers

Answer 1
Answer: 15 units is the area
Answer 2
Answer: The formula for finding Area is, Length x Width.
In this case the length is 5 and the width is 3.
Multiply them and you’ll get 15.
Hopefully that helped :)

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Y = 3x + 4y, x + 2y = -1 using substitution

Answers

Answer:

x = 1

y = -1

Step-by-step explanation:

y = 3x + 4y

3x + 3y = 0

So, we have 2 equations that are

3x + 3y = 0

x + 2y = -1

Times the second equation by -3

3x + 3y = 0

-3x - 6y = 3

-3y = 3

y = -1

Now put -1 in for y and solve for x

x + 2(-1) = -1

x - 2 = -1

x = 1

Let's check

1 + 2(-1) = -1

1 - 2 = -1

-1 = -1

So, x = 1 and y = -1 is the correct answer.
The answers should be x=1 and y=-1

HELP NOW PLEASE HOW DO I FIGURE THIS OUT?

Answers

Hello,

∛72=∛(2^3*3^2)=2*∛3^2=2∛9
Answer C

What is the solution to the linear system of equations?y = 3x + 1
y = –x + 5

A.
(2, 7)


B.
(0, 5)


C.
(1, 4)


D.
The system has no solution.

Answers

Hello,

Answer C

y=3x+1
y=-x+5
==>3x+1=-x+5
==>4x=4
==>x=1 and y=-x+5=-1+5=4

(1,4) is the solution.

Name the property used to make the conclusion.If x 3=17, then x=14

Answers

This is the right way to solve it  14+3 = 17 .

What's 17⁄12 as a mixed number? A. 1 5⁄12
B. 1 12⁄7
C. 1 7⁄12
D. 7 1⁄2

Answers

You need to simplify. 12 goes into 17 once so it is defiantly not D. 17-12=5, so it is A.

An object is traveling around a circle with a radius of 10 cm. If in 20 seconds a central angle of 1/3 radian is swept out, what is the linear speed of the object?

Answers

The linear speed of the object is (1)/(6)

  • The Radius, r = 10 cm
  • The Fraction of Radius swept out = (1)/(3)
  • The distance = 10 / (1)/(3)
  • The distance covered = (10)/(3)

The linear speed :

  • Radius swept out ÷ time taken
  • (10)/(3) * (1)/(20) = (1)/(6)

The linear speed of the object is (1)/(6)

Learn more : brainly.com/question/15154430?referrer=searchResults
Firstly, we will find the distance covered by the object in the 20 seconds:

\text{angle}(in~radians)=\frac{\text{arch}}{\text{radius}}\Longrightarrow (1)/(3)=(d)/(10~cm)\iff d=(10)/(3)~cm

We must know that v=(d)/(\Delta t). So:

v=(d)/(\Delta t)\Longrightarrow v=((10)/(3)~cm)/(20~s)\iff \boxed{v=(1)/(6)~cm/s}
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