MATHEMATICS COLLEGE

. Emma is making bracelets for her friends. She noticed that 12 out of 20 of her beads are red. What decimal is equivalent to the fraction of Emma's beads that are red?

Answers

Answer 1
Answer:

Answer:

0.6

Step-by-step explanation:

12/20 = 6/10 = 0.6

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Answer:

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Step-by-step explanation:

Il give brainliest thanks

Answers

Answer:

D) a = 14, b = 6√2

Step-by-step explanation:

The given figure is trapezoid.

When we draw perpendicular to base "a", we get h = 6

From 45, 45, 90 degrees triangle, the ratio of sides 1:1:√2

since h = 6, b = 6√2

a = 8 + 6

a= 14

Therefore, a = 14 and b = 6√2

Thank you.

Find the area of the right triangle.

Answers

Answer:

area is 28 units²

Step-by-step explanation:

find the area of the rectangle with sides 7 and 8 and divide it in half

A=7*8/2= 56/2=28

How do you write 914.238 in word form

Answers

Answer:

Nine hundred fourteen point two three eight

OR

Nine hundred one ten 4 one two tenths three hundredths and eight thousandths

Find an equation for the tangent to the curve at P and the horizontal tangent to the curve at Q. y = 5 + cot x - 2 csc x 0 1 2 3 0 2 4 x y Upper QUpper P left parenthesis StartFraction pi Over 2 EndFraction comma 3 right parenthesis

Answers

Answer with explanation:

The given function in x and y is,

  y= 5 +cot x-2 Cosec x

To find the equation of tangent, we will differentiate the function with respect to x

y'= -\csc^2 x+2 \csc x* \cot x

Slope of tangent at (π/2,3)

 y'_{((\pi)/(2),3)}= -\csc^2(\pi)/(2) +2 \csc (\pi)/(2)* \cot (\pi)/(2)\n\n=-1+2* 1 * 0\n\n= -1

Equation of tangent passing through (π/2,3) can be obtained by

\rightarrow (y-y_(1))/(x-x_(1))=m(\text{Slope})\n\n \rightarrow (y-3)/(x-(\pi)/(2))=-1\n\n\rightarrow 3-y=x-(\pi)/(2)\n\n\rightarrow x+y-3-(\pi)/(2)=0

⇒There will be no Horizontal tangent from the point(π/2,3).

Given that r = ( 7, 3, 9) and v = ( 3, 7, -9), evaluate r + va. (-21,-21,81)
b. (10,10,0)
c. (21,21,-81)
d. (-10,-10,0)

Answers

Answer:

b. (10,10,0)

Step-by-step explanation:

r+v can be evaluated if the vectors/matrices have the same dimensions.

These do. They are both 1 by 3 vectors.

Just add first to first in each.

Just add second to second in each.

Just add third to third in each.

Example:

(5,-5,6)+(1,2,3)

=(5+1,-5+2,6+3)

=(6,-3,9)

Done!

In general, (a,b,c)+(r,s,t)=(a+r,b+s,c+t).

r+v

=(7,3,9)+(3,7,-9)

=(7+3,3+7,9+-9)

=(10,10,0)

Done!
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