Why is it important for scientists to be curious?

Answers

Answer 1

Answer: it is important for scientists to be curious because they will never find out the answer to their curiosity unless they well find out

Answer 2

Answer: It's important for scientists to be curious because everyday we live in a specticul world. and as soon as we learn how to talk our language starts to get more and more advance. But then we start to ask question's that lead up to our curiosity. this is very important because we can make a difference in life. we can uncover new mysteries that appear based on a theory.

I hopee this helped you

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What chromosomes are found in body cells but not sex cells

Answers

haploid and diploid cells

Which of the following is not needed to make a model of the water cycle?

Answers

grass.. dirt... land things

Answer:

The answer is a drain

The factor being measured in an experiment is thea. Scientific law
B. Variable
C. Control
D. Hypothesis

Answers

The factor being measured in the experiment is a variable B.

A student that jumps a vertical height of 50 cm during the hang time activity.a. What is the hang time of the student?
b. What speed must the student leave the ground with to reach that height?

Answers

The hang time of the student is 0.64 seconds, and he must leave the ground with a speed of 3.13 m/s

Why?

To solve the problem, we must consider the vertical height reached by the student as max height.

We can use the following equations to solve the problem:

Initial speed calculations:

$v_(f)^(2)=v_(o)^(2)+2*a*d$

At max height, the speed tends to zero.

So, calculating, we have:

$v_(f)^(2)=v_(o)^(2)+2*a*d\n\n0=v_(o)^(2)+2*(-9.81(m)/(s^(2)))*0.5m\n\nv_(o)^(2)=9.81(m^(2) )/(s^(2))\n\nv_(o)=\sqrt{9.81(m^(2) )/(s^(2))}=3.13(m)/(s)$

Hang time calculations:

We must remember that the total hang time is equal to the time going up plus the time going down, and both of them are equal,so, calculating the time going down, we have have:

$y-yo=vo.t+(1)/(2)*9.81(m)/(s^(2))*t^(2) \n\n0.5m-0=0*t+4.95*t^(2)\n\nt^(2)=(0.5)/(4.95)\n\nt=√(0.101)=0.318s$

Then, for the total hang time, we have:

$TotalHangTime=2*0.318seconds=0.64seconds$

Have a nice day!

Find the equivalent resistance in the circuit between A and B

Answers

Answer:

6Ω

Explanation:

The 6Ω resistor and the 3Ω resistor are in parallel.

R = 1 / (1/6 + 1/3)

R = 1 / (1/6 + 2/6)

R = 1 / (3/6)

R = 6/3

R = 2

The 8Ω resistor and the other 8Ω resistor are also in parallel.

R = 1 / (1/8 + 1/8)

R = 1 / (2/8)

R = 8/2

R = 4

This 4Ω resistance is in series with the 4Ω resistor.

R = 4 + 4

R = 8

The 2Ω resistor and the 6Ω resistor are also in series.

R = 2 + 6

R = 8

These two 8Ω resistances are in parallel.

R = 1 / (1/8 + 1/8)

R = 1 / (2/8)

R = 8/2

R = 4

Finally, this 4Ω resistance is in series with the 2Ω resistance we found earlier.

R = 4 + 2

R = 6

The total equivalent resistance is 6Ω.

Table C. The Effects of a Magnet on Electric CurrentScenario
Observations of Compass Needle Movement in
Galvanometer
Magnet moving right
to left
(or top to bottom)
Magnet moving left to
right
(or bottom to top)
Magnet stationary
in coil
Pencil moving right to
left
(or top to bottom)
Pencil moving left to
right
(or bottom to top)

Can someone please help me

Answers

magnet moving left to right

Answer:

huh

Explanation:

do u need the whole table?

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