MATHEMATICS HIGH SCHOOL

Let f(x) = -x + 5 and g(x)=3x+ 2. Find f(x) – g(x).

Answers

Answer 1

Answer:

Answer: f(x) - g(x) = -4x+3

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Work Shown:

f(x) - g(x) = ( f(x) ) - ( g(x) )

f(x) - g(x) = ( -x+5 ) - ( 3x+2 )

f(x) - g(x) = -x+5 - 3x - 2

f(x) - g(x) = (-x-3x) + (5-2)

f(x) - g(x) = -4x+3

In step 3, make sure to distribute the negative to everything in the parenthesis for (3x+2)

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I'm stuck on both of these questions. Any answer will be better than what I got. Please include brief explanation :)

Answers

Answer:

B. $x>-17.5$

C. $x\leq-30$

Step-by-step explanation:

B.)

$(-8)/(14)x+22>32\n-8x+308>448\n-8x>140\nx>-17.5$

C.)

$0.9x+12\leq-15\n0.9x\leq-27\nx\leq-30$

Hope this helped!! <3

If someone made 65 ounces of jelly if they put the same amount of jelly in 6 jars how much jelly is in each jar

Answers

There would be 10.8 ounces in each jar.

3.90 ounces in each jelly jar

A single fair is tossed. find the probability of rolling a number grater than 4

Answers

Probability of the outcome you're looking for =

(number of ways your outcome can happen)
divided by
(total number of possible outcomes) .

Total number of possible outcomes when a single fair is tossed = 6 .

The outcomes you're looking for: 5 or 6 . (two of them) .

Probability = 2 / 6 = 1/3 = 33-1/3 %

Given the set definitions below, find MxN.M= {a,b,c}
N= {d, el
A. MxN= {(d).(a,e).(3,4).(b.e). (c,d).(c.e)}
B. MXN= {(2,6). (a,0).(d,e)}
C. MXN= {(a,b,c). (d.e)}
D. MXN= {a,b,c,d,e

Answers

Answer:

Step-by-step explanation:

Multiply.

2/7 x 35 =

Answers

If you would like to calculate 2/7 * 35, you can do this using the following steps:

2/7 * 35 = 2 * 35/7 = 2 * 5 = 10

The correct result would be 10.

I am confused on numbers 25 and 29, the instructions are at the top.

Answers

Pretty sure you already had something posted about this... in case you've lost it, or have questions:

#25 is fairly simple. Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.
$√(12-(-4)) = √(16) = \frac{+}{}4$
Extraneous root in this case is positive four since +4≠-4
$√(12-3) = √(9) = \frac{+}{}3$
In this case it's negative 3, since -3≠3

#29 can be turned into a quadratic equation.
$x= √(2x+3)$
Square both sides to get
$x^(2)=2x+3$
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
$x^(2)-2x-3=0$
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1. Plug both back into the original equation. Whichever does not work is the extraneous root, and the answer is the one that does.
$x= √(2x+3)$
$3= √(2(3)+3)$
$3= √(9)$
Extraneous root would be negative 3.

$-1= √(2(-1)+3)$
$-1= √(1)$
Extraneous root would be positive 1.

Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.

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