PLEASE HELP!!!The points A, B, C, and D are plotted on a line, consecutively. AB = BC = CD = 6 cm. Find the distance between M and N, which are the midpoints of segments AB and CD , respectively. Fill in the blanks of the Statement/Reason solution.

Answers

Answer 1
Answer:

The distance between Mand N, which are the midpoints of segments AB and CD is 12cm.

What is segment?

Segment is a part of a line that is bounded by two distinct end points, and contains every point on the line that is between its endpoints.

What is line?

Line is defined as a straight 1D figure having no thickness and extending infinitely in both directions.

We have,

AB=BC=CD=6cm,

And, Mand N  are the midpoints of segments AB and CD.

According to question,

AB=BC=CD=6cm,

So,

Total length of line is 18cm.

As M and N are midpoints of   and AB and CD,

So,

MN=18-(AM+BN)

MN=18-6

MN=12cm

Hence, we can say that the distance between Mand N, which are the midpoints of segments AB and CD is 12cm.

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Answer 2
Answer:

Answer:

12 inches

Step-by-step explanation:


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A group of 100 people, some students and some faculty, attended a museum opening. Each student paid $10 per person for entrance to the museum and each of the faculty paid $25 per person for entrance. If the total paid, for all 100 people, was $1300, how many students attended the museum opening?

Answers

The number of students who attended the museum opening is 80.

What is a linear equation?

A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.

Given, A group of 100 people, some students and some faculty, attended a museum opening.

Assuming no. of students to be x and no. of faculty to be y.

x + y = 100...(i)

Each student paid $10 per person for entrance to the museum and each of the faculty paid $25 per person for entrance and the total cost is $1300.

10x + 25y = 1300...(ii)

Now multiplying eqn(i) by 10 we get 10x + 10y = 1000...(iii)

Subtracting eqn(iii) from eqn(ii) we get 15y = 300 ⇒ y = 20 and substitting value of y in eqn(iii) we get x = 80.

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STUDENTS               X              10               

FACULTY           100-X              25


                                   10X + 25(100-X) = 1300

                                    10X + 2500 -25X = 1300

                                    10X - 25X = -2500 + 1300

                                             -15X = -1200

                                               15X = 1200

                                                    X = 1200/15

                                                    X = 80 STUDENTS <--------SOLUTION

I need help as soon as possible with the problem bellowSimplify each of the following with justifications for your answer:
a. 290 mod 26
b. 9^{-1} mod 26
c. -15 mod 26

Answers

a)  290 mod 26

We subtract the largest multiple of 26 which is less than 290. The answer we get after the subtraction is the answer.

Largest multiple of 26 is 286, because 26 * 11 = 286

290 - 286 = 4.

290 mod 26 = 4.

b). 9^(-1)   mod 26 =   0.111  mod 26.

 0 * 26 = 0.
The largest multiple of 26 which is less than 0.111 is 0.
We subtract this from 0.111

0.111 -  0 = 0.111

9^(-1)   mod 26 =  9^(-1)  = 0.111

c). -15 mod 26.

Take note this is negative numbers. But same rules applies here.

The largest multiple of 26 which is less than -15 is -26.

We subtract this from -15

-15 - (-26) = -15 + 26 = 11

-15 mod 26 = 11

Final answer:

The results of the modulo operations are: 290 mod 26 results in 2; 9^{-1} mod 26 is equivalent to 3; and -15 mod 26 equals 11.

Explanation:

To simplify each of the following with justifications:

  1. 290 mod 26: When you divide 290 by 26, the remainder is 2. Therefore, 290 mod 26 = 2.
  2. 9^{-1}  mod 26: First, you need to find the multiplicative inverse of 9 in mod 26. The multiplicative inverse of an integer a modulo m is an integer b such that (ab) mod m = 1. For 9, the multiplicative inverse is 3, since (9*3) mod 26 = 27 mod 26 = 1. Therefore, 9^{-1} mod 26 = 3.
  3. -15 mod 26: In modular arithmetic, if you end up with a negative number, you add the modulus until you get a positive result. Here, adding 26 once to -15 gives you 11. Therefore, "-15 mod 26 = 11".

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6. You deposit $1500 in an account that pays 5% interest yearly.a. Write an exponential equation describing this situation.




b. How much money do you have after 6 years?

Answers

The answer to B is $1950 because the 5% equal 75 dollars and 75 times 6 equals 450 so 1500 plus 450 equal 1950

The line y= -3 is a reflection of the line y=5. What is the equation for the line of reflection?

Answers

Answer:

y = 1

Step-by-step explanation:

The line of reflection will be a parallel line midway between y = - 3 and y = 5

y = (-3+5)/(2) = (2)/(2) = 1

line of reflection is y = 1

Answer:

y=1

Step-by-step explanation:

the line of reflection will be a parallel line midway between y=-3and y=5

y=-3+5/2

=2/2=1

Rachel can buy licorice sticks for $0.75 and cherry candies for $0.50 and has a budget of $25. If her expenses are represented by the equation 0.75x + 0.5y = 25, where x is the number of licorice sticks and y is the number of cherry candies, how many cherry candies can she buy if she wishes to spend the entire $25 on cherry candies?

Answers

Answer:

She can buy 50 cherry candies if she wishes to spent the entire $25 on cherry candies

Step-by-step explanation:

Cost of each licorice sticks = $0.75

Cost of each cherry candy = $0.50

Total budget = $25

Equation to represent her expenses is 0.75x + 0.5y = 25

where x is the number of licorice sticks and y is the number of cherry candies

Let the number of cherry candies she can buy be c.

So,

Cost of each cherry candy * Number of cherry candies = Total budget

=> 0.50 x c = 25

We get

0.50c = 25

We need to eliminate 0.50 from the left so we divide both sides by 0.50

(0.50c)/(0.50)=(25)/(0.50)

Cancelling out 0.50 from the top and bottom of the left side we get,

c = 50

So, she can buy 50 cherry candies if she wishes to spent the entire $25 on cherry candies.

She will be able to buy 50 candies if she wish to spend her entire 25 dollars on only cherry candies.

Stan earns $12 per hour by working as an intern at a law firm. How much money does he earn in a week in which he works 28 hours? A. $400 B.$380 C.$350 D.$336 E.$300

Answers

Answer:

The answer is D

Step-by-step explanation: